summaryrefslogtreecommitdiff
path: root/75904-0.txt
diff options
context:
space:
mode:
Diffstat (limited to '75904-0.txt')
-rw-r--r--75904-0.txt6495
1 files changed, 6495 insertions, 0 deletions
diff --git a/75904-0.txt b/75904-0.txt
new file mode 100644
index 0000000..59bb40f
--- /dev/null
+++ b/75904-0.txt
@@ -0,0 +1,6495 @@
+
+*** START OF THE PROJECT GUTENBERG EBOOK 75904 ***
+
+
+
+
+
+ THE
+ SLIDE RULE:
+ A PRACTICAL MANUAL
+
+
+ BY
+
+ CHARLES N. PICKWORTH
+
+ WHITWORTH SCHOLAR; EDITOR OF “THE MECHANICAL WORLD”; AUTHOR OF
+ “LOGARITHMS FOR BEGINNERS”; “THE INDICATOR: ITS CONSTRUCTION AND
+ APPLICATION”; “THE INDICATOR DIAGRAM: ITS ANALYSIS AND CALCULATION,”
+ ETC.
+
+ _SEVENTEENTH EDITION_
+
+ MANCHESTER:
+ EMMOTT AND CO., LIMITED,
+ 65 KING STREET;
+
+ NEW YORK:
+ D. VAN NOSTRAND CO.,
+ 8 WARREN STREET.
+
+ LONDON:
+ EMMOTT AND CO., LIMITED,
+ 20 BEDFORD STREET, W.C.
+
+ AND
+ PITMAN AND SONS, LIMITED,
+ PARKER ST., KINGSWAY, W.C. 2.
+
+ [_Three Shillings and Sixpence net_]
+
+
+
+
+ _All rights reserved._
+
+
+
+
+ PREFACE TO THE FIFTEENTH EDITION.
+
+
+Several new slide rules for special calculations are described in this
+edition, and the contents further extended to include a section dealing
+with screw-cutting gear calculations by the slide rule—an application of
+the instrument to which attention has been given recently.
+
+Mention should be made of the fact that some of the special slide rules
+described in previous editions are no longer obtainable. As, however,
+the descriptive notes may be of service to those possessing the
+instruments, and are, in some measure, of general interest, they have
+been allowed to remain in the present issue.
+
+The author tenders his thanks to the many who have evinced their
+appreciation of his efforts to popularise the subject; also for the many
+kind hints and suggestions which he has received from time to time, and
+with a continuance of which he trusts to be favoured in the future.
+
+ C. N. P.
+
+WITHINGTON, MANCHESTER, _November 1917_.
+
+
+ PREFACE TO THE SEVENTEENTH EDITION.
+
+The sustained demand for this very successful work having resulted in
+the early call for a new edition, the opportunity has been taken to
+introduce descriptions of new slide rules and to effect some slight
+revisions.
+
+ C. N. P.
+
+WITHINGTON, MANCHESTER, _December 1920_.
+
+
+
+
+ CONTENTS.
+
+
+ PAGE
+ Introductory 5
+ The Mathematical Principle of the Slide Rule 6
+ Notation by Powers of 10 8
+ The Mechanical Principle of the Slide Rule 9
+ The Primitive Slide Rule 10
+ The Modern Slide Rule 12
+ The Notation of the Slide Rule 14
+ The Cursor or Runner 17
+ Multiplication 19
+ Division 24
+ The Use of the Upper Scales for Multiplication and Division 26
+ Reciprocals 27
+ Continued Multiplication and Division 28
+ Multiplication and Division with the Slide Inverted 30
+ Proportion 31
+ General Hints on the Elementary Uses of the Slide Rule 36
+ Squares and Square Roots 37
+ Cubes and Cube Roots 40
+ Miscellaneous Powers and Roots 45
+ Power and Roots by Logarithms 45
+ Other Methods of Obtaining Powers and Roots 47
+ Combined Operations 49
+ Hints on Evaluating Expressions 52
+ Gauge Points 53
+ Examples in Technical Calculations 56
+ Trigonometrical Application 74
+ Slide Rules with Log-log Scales 84
+ Special Types of Slide Rules 92
+ Long-Scale Slide Rules 96
+ Circular Calculators 101
+ Slide Rules for Special Calculations 109
+ Construction Improvements in Slide Rules 110
+ The Accuracy of Slide Rule Results 111
+ Appendix:—
+ New Slide Rules 113
+ The Solution of Algebraic Equations 122
+ Screw-Cutting Gear Calculations 124
+ Gauge Points and Signs on Slide Rules 126
+ Tables and Data 128
+ Slide Rule Data Slips 133
+
+
+
+
+ THE SLIDE RULE.
+
+
+
+
+ INTRODUCTORY.
+
+
+The slide rule may be defined as an instrument for mechanically
+effecting calculations by logarithms. Those familiar with logarithms and
+their use will recognise that the slide rule provides what is in effect
+a concisely arranged table of logarithms, together with a simple and
+convenient means for adding and subtracting any selected values. Those,
+however, who have no acquaintance with logarithms will find that only an
+elementary knowledge of the subject is necessary to enable them to make
+full use of the slide rule. It is true that for simple slide-rule
+operations, as multiplication and division, a knowledge of logarithms is
+unnecessary; indeed, many who have no conscious understanding of
+logarithms make good use of the instrument. But this involves a blind
+reliance upon rules without an appreciation of their origin or
+limitations, and this, in turn, engenders a want of confidence in the
+results of any but the simplest operations, and prevents the fullest use
+being made of the instrument. For this reason a brief, but probably
+sufficient _résumé_ of the principles of logarithmic calculation will be
+given. Those desiring a more detailed explanation are referred to the
+writer’s “Logarithms for Beginners.”
+
+The slide rule enables various arithmetical, algebraical and
+trigonometrical processes to be performed with ease and rapidity, and
+with sufficient accuracy for most practical purposes. A grasp of the
+simple fundamental principles which underlie its operation, together
+with a little patient practice, are all that are necessary to acquire
+facility in using the instrument, and few who have become proficient in
+this system of calculating would willingly revert to the laborious
+arithmetical processes.
+
+
+
+
+ THE MATHEMATICAL PRINCIPLE OF THE SLIDE RULE.
+
+
+Logarithms may be defined as a series of numbers in _arithmetical_
+progression, as 0, 1, 2, 3, 4, etc., which bear a definite relationship
+to another series of numbers in _geometrical_ progression, as 1, 2, 4,
+8, 16, etc. A more precise definition is:—The logarithm of a number to
+any base, is the _index of the power_ to which the base must be raised
+to equal the given number. In the logarithms in general use, known as
+_common logarithms_, and with which we are alone concerned, 10 is the
+base selected. The general definition may therefore be stated in the
+following modified form:—_The common logarithm of a number is the index
+of the power to which 10 must be raised to equal the given number._
+Applying this rule to a simple case, as 100 = 10^2, we see that the base
+10 must be squared (_i.e._, raised to the 2nd power) in order to equal
+100, the number selected. Therefore, as 2 is the index of the power to
+which 10 must be raised to equal 100, it follows from our definition
+that 2 is the common logarithm of 100. Similarly the common logarithm of
+1000 will be 3, while proceeding in the opposite direction the common
+log. of 10 must equal 1. Tabulating these results and extending, we
+have:—
+
+ Numbers 10,000 1000 100 10 1
+ Logarithms 4 3 2 1 0
+
+It will now be evident that for numbers
+
+ between 1 and 10 the logs. will be between 0 and 1
+ „ 10 „ 100 „ „ 1 „ 2
+ „ 100 „ 1000 „ „ 2 „ 3
+ „ 1000 „ 10,000 „ „ 3 „ 4
+
+In other words, the logarithms of numbers between 1 and 10 will be
+wholly fractional (_i.e._, decimal); the logs. of numbers between 10 and
+100 will be 1 _followed by a decimal quantity_; the logs. of numbers
+between 100 and 1000 will be 2 followed by a decimal quantity, and so
+on. These decimal quantities for numbers from 1 to 10 (which are the
+logarithms of this particular series) are as follows:—
+
+ Numbers 1 2 3 4 5 6 7 8 9 10
+ Logarithms 0 0·301 0·477 0·602 0·699 0·778 0·845 0·903 0·954 1·000
+
+Combining the two tables, we can complete the logarithms. Thus for 3
+multiplied successively by 10, we have:—
+
+ Numbers 3 30 300 3000 30,000 etc.
+ Logarithms 0·477 1·477 2·477 3·477 4·477 „
+
+We see from this that for numbers having the _same significant figure_
+(or figures), 3 in this case, the decimal part or _mantissa_ of the
+logarithm is the same, but that the integral part or _characteristic_ is
+always _one less than the number of figures before the decimal point_.
+
+For numbers less than 1 the same plan is followed. Thus extending our
+first table downwards, we have:—
+
+ Numbers 1 0·1 0·01 0·001 0·0001 etc.
+ Logarithms 0 −1 −2 −3 −4 „
+
+so that for 3 divided successively by 10, we have:—
+
+ Numbers 3 0·3 0·03 0·003 0·0003 etc.
+ Logarithms 0·477 ̅1·477 ̅2·477 ̅3·477 ̅4·477 „
+
+Here again we see that with the same significant figures in the numbers,
+the mantissa of the logarithm has always the same (_positive_) value,
+but the characteristic is _one more_ than the _number of 0’s immediately
+following the decimal point_, and is _negative_, as indicated by the
+minus sign written over it. Only the decimal parts of the logarithms of
+numbers between 1 and 10 are given in the usual tables, for, as shown
+above, the logarithms of all tenfold multiples or submultiples of a
+number can be obtained at once by modifying the characteristic in
+accordance with the rules given.
+
+An examination of the two rows of figures giving the logarithms of
+numbers from 1 to 10 will reveal some striking peculiarities, and at the
+same time serve to illustrate the principle of logarithmic calculation.
+First, it will be noticed that the addition of any two of the logarithms
+gives the logarithm of the _product_ of these two numbers. Thus, the
+addition of log. 2 and log. 4 = 0·301 + 0·602 = 0·903, and this is seen
+to be the logarithm of 8, that is, of 2 × 4. Conversely, the difference
+of the logarithms of two numbers gives the logarithm of the _quotient_
+resulting from the division of these two numbers. Thus, log. 8 − log. 2
+= 0·903 − 0·301 = 0·602, which is the log. of 4, or of 8 ÷ 2.
+
+One other important point is to be noted. If the logarithm of any number
+is _multiplied_ by 2, 3, or any other quantity, whole or fractional, the
+result is the logarithm of the original number, raised to the 2nd, 3rd,
+or other power respectively. Thus, multiplying the log. of 3 by 2, we
+obtain 0·477 × 2 = 0·954, and this is seen to be the log. of 9, that is,
+of 3 raised to the 2nd power, or 3 _squared_. Again, log. 2 multiplied
+by 3 = 0·903—that is, the log. of 8, or of 2 raised to the 3rd power, or
+2 _cubed_. Conversely, dividing the logarithm of any original number by
+any number _n_, we obtain the logarithm of the _n_th root of the
+original number. Thus, log. 8 ÷ 3 = 0·903 ÷ 3 = 0·301, and is therefore
+equal to log. 2 or to the log. of the _cube root_ of 8.
+
+Only simple logs. have been taken in these examples, but the student
+will understand that the same reasoning applies, whatever the number.
+Thus for 20^3 we prefix the characteristic (1 in this case) to log. 2,
+giving 1·301. Multiplying by 3, we have 3·903 as the resulting
+logarithm, and as its characteristic is 3, we know that it corresponds
+to the number 8000. Hence 20^3 = 8000.
+
+In this brief explanation is included all that need now be said with
+regard to the properties of logarithms. The main facts to be borne
+clearly in mind are:—(1.) That to find the _product_ of two numbers, the
+logarithms of the numbers are to be _added_ together, the result being
+the logarithm of the product required, the value of which can then be
+determined. (2.) That in finding the _quotient_ resulting from the
+division of one number by another, _the difference_ of the logarithms of
+the numbers gives the logarithm of the quotient, from which the value of
+the latter can be ascertained. (3.) That to find the result of _raising
+a number to the nth power_, we _multiply_ the logarithm of the number by
+_n_, thus obtaining the logarithm, and hence the value, of the desired
+result. And (4.) That to find the n_th root of a number_, we _divide_
+the logarithm of the number by _n_, this giving the logarithm of the
+result, from which its value may be determined.
+
+
+
+
+ NOTATION BY POWERS OF 10.
+
+
+A convenient method of representing an arithmetical quantity is to split
+it up into two factors, of which the first is the original number, with
+the decimal point moved so as to immediately follow the first
+significant figure, and the second, 10^{_n_} where _n_ is the number of
+places the decimal point has been moved, this index being _positive_ for
+numbers greater than 1, and _negative_ for numbers less than 1.[1] In
+this system, therefore, we regard 3,610,000 as 3·61 × 1,000,000, and
+write it as 3·61 × 10^6. Similarly 361 = 3·61 x 10^2; 0·0361 (=
+(3·61)/(100)) = 3·61 × 10^{−2}; 0·0000361 = 3·61 × 10^{−5}, etc. To
+restore a number to its original form, we have only to move the decimal
+point through the number of places indicated by the index, moving to the
+right if the index is positive and to the left (prefixing 0’s) if
+negative. This method, which should be cultivated for ordinary
+arithmetical work, is substantially that followed in calculating by the
+slide rule. Thus with the slide rule the multiplication of 63,200 by
+0·0035 virtually resolves itself into 6·32 × 10^4 × 3·5 × 10^{−3} or
+6·32 × 3·5 × 10^{4–3} = 22·12 x 10^1 = 221·2. It will be seen later,
+however, that the result can be arrived at by a more direct, if less
+systematic, method of working.
+
+
+
+
+ THE MECHANICAL PRINCIPLE OF THE SLIDE RULE.
+
+
+[Illustration: FIG. 1.]
+
+The mechanical principle involved in the slide rule is of a very simple
+character. In Fig. 1, A and B represent two rules divided into 10 equal
+parts, the division lines being numbered consecutively as shown. If the
+rule B is moved to the right until 0 on B is opposite 3 on A, it is seen
+that any number on A is equal to the coinciding number on B, plus 3.
+Thus opposite 4 on B is 7 on A. The reason is obvious. By moving B to
+the right, we add to a length 0·3, another length 0·4, the result read
+off on A being 7. Evidently, the same result would have been obtained if
+a length 0·4 had been added, by means of a pair of dividers, to the
+length 0·3 on the scale A. By means of the slide B, however, the
+addition is more readily effected, and, what is of much greater
+importance, the result of adding 3 to _any one of the numbers_ within
+range, on the lower scale, is _immediately_ seen by reading the adjacent
+number on A.
+
+Of course, subtraction can be quite as readily performed. Thus, to
+subtract 4 from 7, we require to deduct from 0·7 on the A scale, a
+length 0·4 on B. We do this by placing 4 on B under 7 on A, when over 0
+on B we find 3, on A. It is here evident that the _difference_ of any
+pair of coinciding numbers on the scales is constantly equal to 3.
+
+[Illustration: FIG. 2.]
+
+An important modification results if the slide-scale B is inverted as in
+Fig. 2. In this case, to find the sum of 4 and 3 we require to place the
+4 of the A scale to 3 on the B scale, and the result is read on A over 0
+on B. Here it will be noted, the _sum_ of any pair of coinciding numbers
+on the scales is constant and equal to 7. This case, therefore,
+resembles that of the immediately preceding one, except that the _sum_,
+instead of the _difference_, of any pair of coinciding numbers is
+constant.
+
+To find the difference of two factors, the converse operation is
+necessary. Thus, to subtract 4 from 7, 0 on B is placed opposite 7 on A,
+and over 4 on B is found 3 on A.
+
+From these examples it will be seen that with the slide _inverted_ the
+methods of operation are the reverse of those used when the slide is in
+its normal position.
+
+It will be understood that although we have only considered the primary
+divisions of the scales, the remarks apply equally to any subdivisions
+into which the primary spaces of the scales might be divided. Further,
+we note that the length of scale taken to represent a unit is quite
+arbitrary.
+
+
+
+
+ THE PRIMITIVE SLIDE RULE.
+
+
+The application of the foregoing principles to the slide rule can be
+shown most conveniently by describing the construction of a simple form
+of slide rule:—Take a strip of card about 11 in. long and 2 in. wide;
+draw a line down the centre of its width, and mark off two points, 10
+in. apart. Draw cross lines at these points and figure them 1 and 10 on
+each side, as in Fig. 3. Next mark off lengths of 3·01, 4·77, 6·02,
+6·99, 7·78, 8·45, 9·03 and 9·54 inches, from the line marked 1. Draw
+cross lines as before, and figure these lines, 2, 3, 4, 5, 6, 7, 8 and
+9. To fill in the intermediate divisions of the scale, take the logs, of
+1·1, 1·2, 1·3, etc. (from a table), multiply each by 10, and thus obtain
+the distances from 1, at which the several subdivisions are to be
+placed. Mark these 1·2, 1·3, 1·4, etc., and complete the scale, making
+the interpolated division marks shorter to facilitate reading, as with
+an ordinary measuring rule. Cutting the card cleanly down the centre
+line, we have the essentials of the slide rule.
+
+[Illustration: FIG. 3.]
+
+The fundamental principle of the slide rule is now evident:—Each scale
+is graduated in such a manner that the _distance of any number from 1 is
+proportional to the logarithm of that number_.
+
+[Illustration: FIG. 4.]
+
+“We know that to find the product of 2 × 3 by logarithms, we add 0·301,
+or log. 2, to 0·477, the log. of 3, obtaining 0·778, or log. 6. With our
+primitive slide rule we place 1 on the lower scale to 3·01 in. (which we
+have marked 2) on the upper scale (Fig. 4). Then over 4·77 in. on the
+lower scale (which we marked 3), we have 7·78 in. (which we marked 6) on
+the upper scale. Conversely, to divide 6 by 3, we place 3 on the lower
+scale in agreement with 6 on the upper, and over 1 on the lower scale
+read 2 on the upper scale. This method of adding and subtracting scale
+lengths will be seen to be identical with that used in the simple case
+shown in Fig. 1.
+
+
+
+
+ THE MODERN SLIDE RULE.
+
+
+The modern form of slide rule, variously styled the Gravêt, the
+Tavernier-Gravêt, and the Mannheim rule, is frequently made of boxwood,
+but all the leading instrument makers now supply rules made of boxwood
+or mahogany, and faced with celluloid, the white surface of which brings
+out the graduations much more distinctly than lines engraved on a
+boxwood surface. The celluloid facings should not be polished, as a dull
+surface is much less fatiguing to the eyes. The most generally used, and
+on the whole the most convenient size of rule, is about 10½in. long,
+1¼in. wide, and about ⅜in. thick; but 5 in., 8 in., 15 in., 20 in., 24
+in. and 40 in. rules are also made. In the centre of the stock of the
+rule a movable slip is fitted, which constitutes the slide, and
+corresponds to the lower of the two rules of our rudimentary examples.
+
+[Illustration: FIG. 5.]
+
+From Fig. 5, which is a representation of the face of a Gravêt or
+Mannheim slide rule, it will be seen that four series of logarithmic
+graduations or scale-lines are employed, the upper and lower being
+engraved on the stock or body of the rule, while the other two are
+engraved upon the slide. The two upper sets of graduations are exactly
+alike in every particular, and the lower sets are also similar. It is
+usual to identify the two upper scale-lines by the letters A and B, and
+the two lower by the letters C and D, as indicated in the figure at the
+left-hand extremities of the scales.
+
+Referring to the scales C and D, these will each be seen to be a
+development of the elementary scales of Fig. 3, but in this case each
+principal space is subdivided, more or less minutely. The principle,
+however, is exactly the same, so that by moving the slide (carrying
+scale C), multiplication and division can be mechanically performed in
+the manner described.
+
+The upper scale-line A consists of two exactly similar scales, placed
+end to end, the first lying between IL and IC, and the second between IC
+and IR. The first of these scales will be designated the _left-hand A
+scale_, and the second the _right-hand A scale_. Similarly the
+coinciding scales on the slide are the _left-hand B scale_ and the
+_right-hand B scale_. Each of these four scales is divided (as finely as
+convenient) as in the case of the C and D scales, but, of course, they
+are exactly one half the length of the latter.
+
+The two end graduations of both the C and D scales are known as the
+_left-_ and _right-hand indices_ of these scales. Sometimes they are
+figured 1 and 10 respectively; sometimes both are marked 1. Similarly IL
+and IR are the left- and right-hand indices of the A and B lines, while
+IC is the centre index of these scales. Other division lines usually
+found on the face of the rule are one on the left-hand A and B scales,
+indicating the ratio of the circumference of a circle to its diameter, π
+= 3·1416; and a line on the right-hand B scale marking the position of
+(π)/(4) = 0·7854, used in calculating the areas of circles. Reference
+will be made hereafter to the scales on the under-side of the slide, and
+we need now only add that one of the edges of the rule, usually
+bevelled, is generally graduated in millimetres, while the other edge
+has engraved on it a scale of inches divided into eighths or tenths. On
+the bottom face inside the groove of the rule either one or the other of
+these scales is continued in such a manner that by drawing the slide out
+to the right and using the scale inside the rule, in conjunction with
+the corresponding scale on the edge, it is possible to measure 20 inches
+in the one case, or nearly 500 millimetres in the other. On the back of
+the rule there is usually a collection of data, for which the slips
+given at the end of this work may often be substituted with advantage.
+
+
+
+
+ THE NOTATION OF THE SLIDE RULE.
+
+
+Hitherto our attention has been confined to a consideration of the
+primary divisions of the scales. The same principle of graduation is,
+however, used throughout; and after what has been said, this part of the
+subject need not be further enlarged upon. Some explanation of the
+method of reading the scales is necessary, as facility in using the
+instrument depends in a very great measure upon the dexterity of the
+operator in assigning the correct value to each division on the rule. By
+reference to Fig. 5, it will be seen that each of the primary spacings
+in the several scales is invariably subdivided into ten; but since the
+lengths of the successive primary divisions rapidly diminish, it is
+impossible to subdivide each main space into the same number of parts
+that the space 1–2 can be subdivided. This variable spacing of the
+scales is at first confusing to the student, but with a little practice
+the difficulty is soon overcome.
+
+With the C or D scale, it will be noticed that the length of the
+interval 1–2 is sufficient to allow each of the 10 subdivisions to be
+again divided into 10 parts, so that the whole interval 1–2 is divided
+into 100. The shorter main space 2–3, and the still shorter one 3–4,
+only allow of the 10 subdivisions of each being divided into five parts.
+Each of these main spaces is therefore divided into 50 parts. For the
+remainder of the scale each of the 10 subdivisions of each main space is
+divided into two parts only; so that from the main division 4 to the end
+of the scale the primary spaces are divided into 20 parts only.
+
+In the upper scales A or B, it will be found that—as the space 1–2 is of
+only half the length of the corresponding space on C or D—the 10
+subdivisions of this interval are divided into five parts only.
+Similarly each of the 10 subdivisions of the intervals 2–3, 3–4, and 4–5
+are further divided into two parts only, while for the remainder of the
+scale only the 10 subdivisions are possible, owing to the rapidly
+diminishing lengths of the primary spacings.
+
+The values actually given on the rule run from 1 to 10 on the lower
+scales and from 1 to 100 on the upper scales, and, as explained on page
+9, all factors are brought within these ranges of values by multiplying
+or dividing them by powers of 10. By following this plan, we virtually
+regard each factor as merely a series of significant figures, and make
+the necessary modification due to the “powers of 10” when fixing the
+position of the decimal point in the answer.
+
+Many, however, find it convenient in practice to regard the values on
+the rule as multiplied or divided by such powers of 10 as may be
+necessary to suit the factors entering into the calculation. If this
+plan is adopted, the values given to each graduation of the scales will
+depend on that given to the left index figure (1) of the lower scales,
+this being any multiple or submultiple of 10. Thus IL on the D scale may
+be regarded as 1, 10, 100, 1000, etc., or as 0·1, 0·01, 0·001, 0·0001,
+etc.; but once the initial value is assigned to the index, the ratio of
+value must be maintained throughout the whole scale. For example, if 1
+on C is taken to represent 10, the main divisions 2, 3, 4, etc., will be
+read as 20, 30, 40, etc. On the other hand, if the fourth main division
+is read as 0·004, then the left index figure of the scale will be read
+as 0·001. The figured subdivisions of the main space 1–2 are to be read
+as 11, 12, 13, 14, 15, 16, 17, 18 and 19—if the index represents 10,—and
+as corresponding multiples for any other value of the index.
+
+Independently considered, these remarks apply equally to the A or B
+scale, but in this case the notation is continued through the second
+half of the scale, the figures of which are to be read as tenfold values
+of the corresponding figures in the first half of the scale.
+
+The reading of the intermediate divisions will, of course, be determined
+by the values assigned to the main divisions. Thus, if IL on D is read
+as 1, then each of the smallest subdivisions of the space 1–2 will be
+read as 0·01, and each of the smallest subdivisions of the spaces 2–3 or
+3–4 as 0·02, while for the remainder of the scale the smallest
+subdivisions are read as 0·05. In the A or B scale the subdivisions of
+the space 1–2 of the first half of the scale are (if IL = 1) read as
+0·02, 0·04, etc.; for the divisions 2–3, 3–4, and 4–5, the smallest
+intervals are read as 0·05 of the primary spaces, and from 5 to the
+centre index of the scale the divisions represent 0·1 of each main
+interval. Passing the centre index, which is, now read as 10, the
+smallest subdivisions immediately following are read 10·2, 10·4, etc.,
+until 20·0 is reached; then we read 20·5, 21·0, 21·5 22·0, etc., until
+the figured main division 5 is reached. The remainder of the scale is
+read 51, 52, 53, etc., up to 100, the right-hand index.
+
+Further subdivision of any of the spaces of the rule can be effected by
+the eye, and after a little practice the operator will become quite
+expert in estimating any intermediate value. It affords good practice to
+set 1 on C to 1·04, 1·09, etc. on D, and to read the values on D, under
+4, 6, 8, etc. on C. As the exact results are easily calculated mentally,
+the student, by this means, will receive better instruction in
+estimating intermediate results than can be given by any diagram.
+
+Some rules will be found figured as shown in Fig. 5; in others, the
+right-hand upper scales are marked 10, 20, 30, etc. Again, others are
+marked decimally, the lower scales and the left-hand upper scales being
+figured 1, 1·1, 1·2, 1·3 ... 2·5, etc. The latter form has advantages
+from the point of view of the beginner.
+
+The method of reading the A and B scales, just given, applies only when
+these scales are regarded as altogether independent of the lower pair of
+scales C and D. Some operators prefer to use the A and B scales, and
+some the C and D scales, for the ordinary operations of proportion,
+multiplication, and division. Each method has its advantages, as will be
+shown, but in the more complex calculations, as involution and
+evolution, etc., the relation of the upper scales to the lower scales
+becomes a very important factor.
+
+The distance 1–10 on the upper scales is one-half of the distance 1–10
+on the lower scales. Hence any distance from 1, taken on the upper
+scales, represents _twice the logarithm_ which the same distance
+represents on the lower scales. In other words, the length which
+represents log. N on D, would represent 2 log. N on A; and, conversely,
+the length which represents log. N on A, would represent (log. N)/(2) on
+D.
+
+Now we have seen (page 8) that multiplying the log. of a number by 2
+gives the log. of the square of the number. Hence, above any number on D
+we find its _square_ on A, or, conversely, below any number on A, we
+find its _square root_ on D. Thus, above 2 we find 4; under 49, we find
+7 and so on. Obviously the same relation exists between the B and C
+scales.
+
+
+
+
+ THE CURSOR OR RUNNER.
+
+
+All modern slide rules are now fitted with a _cursor_ or _runner_, which
+usually consists of a light metal frame moving under spring control in
+grooves in the edges of the stock of the rule. This frame carries a
+piece of glass, mica or transparent celluloid, about 1 in. square,
+across the centre of which a fine reference line is drawn exactly at
+right angles to the line of scales. To “set the cursor” to any value on
+the scales of the rule, the frame is taken between the thumb and
+forefinger and adjusted in position until the line falls exactly upon
+the graduation, or upon an estimated value, between a pair of
+graduations, as the case may be. Having fixed one number in this way,
+another value on either of the scales on the slide may be similarly
+adjusted in reference to the cursor line. The cursor will be found very
+convenient in making such settings, especially when either or both of
+the numbers are located by eye estimation. It also finds a very
+important use in referring the readings of the upper scale to those of
+the lower, or _vice versa_, while as an aid in continued multiplication
+and division and complex calculations generally, its value is
+inestimable.
+
+_Multiple Line Cursors._—Cursors can be obtained with _two_ lines, the
+distance between them being that between 7·854 and 10 on the A scale.
+The use of this cursor is explained on page 57. Another multiple line
+cursor has short lines engraved on it, corresponding to the main
+graduations from 95 to 105 on the respective scales. This is useful for
+adding or deducting small percentages.
+
+_The Broken Line Cursor._—To facilitate setting, broken line cursors are
+made, in which the hair-line is not continued across the scales, but has
+two gaps, as shown in Fig. 6.
+
+_The Pointed Cursor_ has an index or pointer, extending over the
+bevelled edge of the rule, on which is a scale of inches. It is useful
+for summing the lengths of the ordinates of indicator diagrams, and also
+for plotting lengths representing the logarithms of numbers, sometimes
+required in graphic calculations.
+
+_The Goulding Cursor._—It has been pointed out that in order to obtain
+the third or fourth figure of a reading on the 10 in. slide rule, it is
+frequently necessary to depend upon the operator’s ability to mentally
+subdivide the space within which the reading falls. This subdivision can
+be mechanically effected by the aid of the Goulding Cursor (Fig. 7),
+which consists of a frame fitting into the usual grooves in the rule,
+and carrying a metal plate faced with celluloid, upon which is engraved
+a triangular scale A B C. The portion carrying the chisel edges E is not
+fixed to the cursor proper, but slides on the latter, so that the index
+marks on the projecting prongs can be moved slightly along the scales of
+the rule, this movement being effected by the short end of the bent
+lever F working in the slot as shown. D is a pointer which can be moved
+along F under spring control. As illustrating the method of use, we will
+assume that 1 on C is placed to 155 on D, and that we require to read
+the value on D under 27 on C. This is seen to lie between 4150 and 4200,
+so setting the pointer D to the line B C—always the first operation—we
+move the whole along the rule until the index line on the lower prong
+agrees with 4200. We then move F across the scale until the index line
+agrees with 4100, set the pointer D to the line A C, and move the lever
+back until the index line agrees with 27 on the slide. It will then be
+found that the pointer D gives 85 on A B as the value of the
+supplementary figures, and hence the complete reading is 4185.
+
+[Illustration: FIG. 6.]
+
+[Illustration: FIG. 8.]
+
+[Illustration: FIG. 7.]
+
+[Illustration: FIG. 9.]
+
+_Magnifying Cursors_ are of assistance in reading the scales, and in a
+good and direct light are very helpful. In one form an ordinary lens is
+carried by two light arms hinged to the upper and lower edges of the
+cursor, so that it can be folded down to the face of the rule when not
+in use. A more compact form, shown in Fig. 8, consists of a strip of
+plano-convex glass, on the under-side of which is the hair-line. In a
+cursor made by Nestler of Lahr, the plano-convex strip is fixed on the
+ordinary cursor. The magnifying power is about 2, so that a 5 in. rule,
+having the same number of graduations as a 10 in. rule, can be read with
+equal facility, by the aid of this cursor.
+
+The Digit-registering Cursor, supplied by Mr. A. W. Faber, London, and
+shown in Fig. 9, has a semicircular scale running from 0 at the centre
+upward to −6 and downward to +6. A small finger enables the operator to
+register the number of digits to be added or subtracted at the end of a
+lengthy operation, as explained at page 28.
+
+
+
+
+ MULTIPLICATION.
+
+
+In the preliminary notes it was shown that by mechanically adding two
+lengths representing the logarithms of two numbers, we can obtain the
+_product_ of these numbers; while by subtracting one log. length from
+another, the number represented by the latter is divided by the number
+represented by the former. Hence, using the C and D scales, we have the
+
+RULE FOR MULTIPLICATION.—_Set the index of the C scale to one of the
+factors on D, and under the other factor on C, find the product on D._
+
+[Illustration: FIG. 10.]
+
+Thus, to find the product of 2 × 4, the slide is moved to the right
+until the left index (1) of C is brought over 2 on D, when under the
+other factor (4) on C, is found the required product (8) on D. Following
+along the slide, to the right, we find that beyond 5 on C (giving 10 on
+D), we have no scale below the projecting slide (Fig. 10). If we imagine
+the D scale prolonged to the right, we should have a repetition of the
+earlier portion, but, as with the two parts of the A scales, the
+repeated portion would be of tenfold value, and 10 on C would agree with
+20 on the prolonged D scale. We turn this fact to account by moving the
+slide to the left until 10 on C agrees with 2 on D, and we can then read
+off such results as 2 × 6 = 12; 2 × 8 = 16, etc., remembering that as
+the scale is now of tenfold value, there will be two figures in the
+result. Hence, for those who prefer rules, we have the
+
+RULE FOR THE NUMBER OF DIGITS IN A PRODUCT.—_If the product is read with
+the slide projecting to the_ LEFT, ADD THE NUMBER OF THE DIGITS IN THE
+TWO FACTORS; _if read with the slide to the_ RIGHT, _deduct 1 from this
+sum_.
+
+
+ EX.—25 × 70 = 1750.
+
+ The product is found with the slide projecting to the _left_, so the
+ number of digits in the product = 2 + 2 = 4.
+
+ EX.—3·6 × 25 = 90.
+
+ The slide projects to the _right_, and the number of digits in the
+ product is therefore 1 + 2 − 1 = 2.
+
+ EX.—0·025 × 0·7 = 0·0175.
+
+ The product is obtained with the slide projecting to the _left_, and
+ the number of digits is therefore −1 + 0 = −1.
+
+ EX.—0·000184 × 0·005 = 0·00000092.
+
+ The sum of the number of digits in the two factors = −3 + (−2) = −5,
+ but as the slide projects to the _right_, the number of digits will be
+ −5 − 1 = −6.
+
+
+From the last two examples it will be seen that when the first
+significant figure of a decimal factor does not immediately follow the
+decimal point, the minus sign is to be prefixed to the number of digits,
+counting as many digits _minus_ as there are 0’s following the decimal
+point. Thus, 0·03 has −1 digit, 0·0035 has −2 digits, and so on. Some
+little care is necessary to ensure these minus values being correctly
+taken into account in determining the number of digits in the answer.
+For this reason many prefer to treat decimal factors as whole numbers,
+and to locate the decimal point according to the usual rules for the
+multiplication of decimals. Thus, in the last example we take 184 × 5 =
+920, but as by the usual rule the product must contain 6 + 3 = 9 decimal
+places, we prefix six cyphers, obtaining 0·00000092. When both factors
+consist of integers as well as decimals, the number of digits in the
+product, and therefore the position of the decimal point, will be
+determined by the usual rule for whole numbers.
+
+Another method of determining the number of digits in a product deserves
+mention, which, not being dependent upon the position of the slide, is
+applicable to all calculating instruments.
+
+GENERAL RULE FOR NUMBER OF DIGITS IN A PRODUCT.—_When the first
+significant figure in the product is smaller than in_ EITHER _of the
+factors, the number of digits in the product is equal to the_ SUM _of
+the digits in the two factors. When the contrary is the case, the number
+of digits is 1_ LESS _than the sum of the digits in the two factors.
+When the first figures are the same, those following must be compared._
+
+_Estimation of the Figures in a Product._—We have given rules for those
+who prefer to decide the number of figures by this means, but experience
+will show that to make the best use of the instrument, the result, as
+read on the rule, should be regarded merely as the _significant figures
+of the answer_, the position of the decimal point, if not obvious, being
+decided by a very rough mental calculation. In very many instances, the
+magnitude of the result will be evident from the conditions of the
+problem—_e.g._, whether the answer should be 0·3 in., 3 in., or 30 in.;
+or 10 tons, 0·1 ton, 100 tons, etc. In those cases where the magnitude
+of the answer cannot be estimated, and the factors contain many figures,
+or have a number of 0’s following the decimal point, the use of notation
+by powers of 10 (page 8) is of considerable assistance; but more usually
+it will be found, that a very rough calculation will settle the point
+with comparatively little trouble. Considerable practice is needed to
+work rapidly and with certainty, when using rules. Moreover, the
+experience thus acquired is confined to slide-rule work. The same time
+spent in practising the “rough approximation” method will enable
+reliable results to be obtained rapidly, with the advantage that the
+method is applicable to calculations generally. However, the choice of
+methods is a matter of personal preference. Both methods will be given,
+but whichever plan is followed, the student is strongly advised to
+cultivate the habit of forming an idea of the magnitude of the result.
+
+
+ EX.—33·6 × 236 = 7930.
+
+ Setting 1 on C to 33·6 on D, we read under 236 on D and find 793 on
+ D, as the significant figures of the answer. A rough calculation, as
+ 30 × 200 = 6000, indicates that the result will consist of 4
+ figures, and is therefore to be read as 7930.
+
+ EX.—17,300 × 3780 = 65,400,000.
+
+ By factorising with powers of 10
+
+ 1·73 × 10^4 × 3·78 × 10^3 = 1·73 × 3·78 × 10^7.
+
+ Setting 1 on C to 1·73 on D, we read, under 3·78 on C, the result of
+ the simple multiplication, as 6·54. Multiplying by 10^7 moves the
+ decimal point 7 places to the right, and the answer is 65,400,000.
+
+
+If it is required to find a series of products of which one of the
+factors is _constant_, set 1 on C to the constant factor on D and read
+the several products on D, under the respective variable factors.
+
+If the factors are required which will give a constant _product_ (really
+a case of division), set the cursor to the constant product on D. Then
+obviously, as the slide is moved along, any pair of factors found
+simultaneously under the cursor line on C, and on D under index of C,
+will give the product. A better method of working will be explained when
+we deal with the inversion of the slide.
+
+It is sometimes useful to remember that although we usually set the
+slide to the rule, we can obtain the result equally well by setting the
+rule to the slide. Thus, bringing 1 (or 10) on D to 2 on C, we find on
+C, _over_ any other factor, _n_ on D, the product of 2 × _n_. But note
+that the slide and rule have now changed places, and if we use rules for
+the number of digits in the result, we must now deduct 1 from the sum of
+the digits in the factors, when the _rule projects_ to the _right of the
+slide_.
+
+With the ordinary 10 in. rule it will be found in general that the
+extent to which the C and D scales are subdivided is such as to enable
+not more than three figures in either factor being dealt with. For the
+same reason it is impossible to directly read more than the first three
+figures of any product, although it is often possible—by mentally
+dividing the smallest space involved in the reading—to correctly
+determine the fourth figure of a product. Necessarily this method is
+only reliable when used in the earlier parts of the C and D scales.
+However, the last numeral of a three-figure, and in some cases the last
+of a four-figure, product can be readily ascertained by an inspection of
+the factors.
+
+EX.—19 × 27 = 513. Placing the L.H. index of C to 19 on D, we find
+opposite 27 on C, the product, which lies between 510 and 515. A glance
+at the factors, however, is sufficient to decide that the third figure
+must be 3, since the product of 9 and 7 is 63, and the last figure of
+this product must be the last figure in the answer.
+
+EX.—79 × 91 = 7189.
+
+In this case the division line 91 on C indicates on D that the answer
+lies between 7180 and 7190. As the last figure must be 9, it is at once
+inferred that the last two figures are 89.
+
+When there are more than three figures in either or both of the factors,
+the fourth and following figures to the right must be neglected. It is
+well to note, however, that if the first neglected figure is 5, or
+greater than 5, it will generally be advisable to increase by 1 the
+third figure of the factor employed. Generally it will suffice to make
+this increase in one of the two factors only, but it is obvious that in
+some cases greater accuracy will be obtained by increasing both factors
+in this way.
+
+CONTINUED MULTIPLICATION.—To find the product of more than two factors,
+we make use of the cursor to mark the position of successive products
+(the value of which does not concern us) as the several factors are
+taken into the calculation. Setting the index of C to the 1st factor on
+D, we bring the line of the cursor to the 2nd factor on C, then the
+index of C to the cursor, the cursor to the 3rd factor, index of C to
+cursor, and so on, reading the final product on D under the last factor
+on C. (Note that the 1st factor and the result are read on D; all
+intermediate readings are taken on C.)
+
+If the rule for the number of digits in a product is used, it is
+necessary to note the number of times multiplication is effected with
+the slide projecting to the right. This number, deducted from the sum of
+the digits of the several factors, gives the number of digits in the
+product. Ingenious devices have been adopted to record the number of
+times the slide projects to the right, but some of these are very
+inconvenient. The author’s method is to record each time the slide so
+projects, by a minus mark, thus −. These can be noted down in any
+convenient manner, and the sum of the marks so obtained deducted from
+the sum of the digits in the several factors, gives the number of digits
+in the product as before explained.
+
+EX.—42 × 71 × 1·5 × 0·32 × 121 = 173,200.
+
+The product given, which is that read on the rule, is obtained as
+follows:—Set R.H. index of C to 42 on D, and bring the cursor to 71 on
+C. Next bring the L.H. index of C to the cursor, and the latter to 1·5
+on C. This multiplication is effected with the slide to the right, and a
+memorandum of this fact is kept by making a mark −. Bring the R.H. index
+of C to the cursor and the latter to 0·32 on C. Then set the L.H. index
+of C to the cursor and read the result, 1732, on D under 121 on C, while
+as a slide again projects to the right, a second − memo-mark is
+recorded. There are 2 + 2 + 1 + 0 + 3 = 8 digits in the factors, and as
+there were 2 − marks recorded during the operation, there will be 8 − 2
+= 6 digits in the product, which will therefore read 173,200
+(173,194·56).
+
+For a very rough evaluation of the result, we note that 1·5 × 0·3 is
+about 0·5; hence, as a clue to the number of figures we have
+
+ 40 × 70 × 60 = 3000 × 60 = 180,000.
+
+
+
+
+ DIVISION.
+
+
+The instructions for multiplication having been given in some detail, a
+full discussion of the inverse process of division will be unnecessary.
+
+RULE FOR DIVISION.—_Place the divisor on C, opposite the dividend on D,
+and read the quotient on D under the index of C._
+
+EX.—225 ÷ 18 = 12·5.
+
+Bringing 18 on C to 225 on D, we find 12·5 under the L.H. index of C.
+
+As in multiplication, the factors are treated as whole numbers, and the
+position of the decimal point afterwards decided according to the
+following rule, which, as will be seen, is the reverse of that for
+multiplication:—
+
+RULE FOR THE NUMBER OF DIGITS IN A QUOTIENT.—_If the quotient is read
+with the slide projecting to the_ LEFT, _subtract the number of digits
+in the divisor from those in the dividend; but if read with the slide to
+the_ RIGHT, ADD _1 to this difference_.[2]
+
+In the above example the quotient is read off with the slide to the
+right, so the number of digits in the answer = 3 − 2 + 1 = 2.
+
+EX.—0·000221 ÷ 0·017 = 0·013.
+
+Here the number of digits in the dividend is −3, and in the divisor −1.
+The difference is −2; but as the result is obtained with the slide to
+the right, this result must be increased by 1, so that the number of
+digits in the quotient is −2 + 1 = −1, giving the answer as 0·013.
+
+If preferred, the result can be obtained in the manner referred to when
+considering the multiplication of decimals. Thus, treating the above as
+whole numbers, we find that the result of dividing 221 by 17 = 13, since
+the difference in the number of digits in the factors, which is 1, is,
+owing to the position of the slide, increased by 1, giving 2 as the
+number of digits in the answer. Then by the rules for the division of
+decimals we know that the number of decimal places in the quotient is
+equal to 6 − 3 = 3, showing that a cypher is to be prefixed to the
+result read on the rule.
+
+As in multiplication, so in division, we have a
+
+GENERAL RULE FOR NUMBER OF DIGITS IN A QUOTIENT.—_When the first
+significant figure in the_ DIVISOR _is greater than that in the_
+DIVIDEND_, the number of digits in the quotient is found by subtracting
+the digits in the divisor from those in the dividend. When the contrary
+is the case, 1_ IS TO BE ADDED _to this difference. When the first
+figures are the same, those following must be compared._
+
+ESTIMATION OF THE FIGURES IN A QUOTIENT.—The method of roughly
+estimating the number of figures in a quotient needs little explanation.
+
+EX.—3·95 ÷ 5340 = 0·00074.
+
+
+ Setting 534 on C to 3·95 on D we read under the (R.H.) index of C, the
+ significant figures on D, which are 74. Then 3·9 ÷ 5 is about 0·8 and
+ 0·8 ÷ 1000 gives 0·0008 as a rough estimate.
+
+
+EX.—0·00000285 ÷ 0·000197 = 0·01446.
+
+
+ Regarding this as 2·85 × 10^{−6} ÷ 1·97 × 10^{−4} we divide 2·85 by
+ 1·97 and obtain 1·446. Dividing the powers of 10 we have 10^{−6} ÷
+ 10^{−4} = 10^{−2}, so the decimal point is to be moved two places to
+ the left and the answer is read as 0·01446.
+
+
+Another method of dividing deserves mention as of special service when
+dividing a number of quantities by a _constant divisor_:—Set the index
+of C to the divisor on D and over any dividend on D, read the quotient
+on C.
+
+For the division of a _constant dividend_ by a variable divisor, set the
+cursor to the dividend on D and bring the divisor on C successively to
+the cursor, reading the corresponding quotients on D under the index of
+C. Another method which avoids moving the slide is explained in the
+section on “Multiplication and Division with the Slide Inverted.”
+
+CONTINUED DIVISION, if we can so call such an expression as
+
+ (3·14)/(785 × 0·00021 × 4·3 × 64·4) = 0·0688,
+
+may be worked by repeating as follows:—Set 7·85 on C to 3·14 on D, bring
+cursor to index of C, 2·1 on C to cursor, cursor to index, 4·3 to
+cursor, cursor to index, 6·44 to cursor, and under index of C read 688
+on D as the significant figures of the answer.
+
+For the number of figures in the result, we deduct the sum of the number
+of digits in the several factors and add 1 for each time the slide
+projects to the right, which in this case occurs once. There are 3 +
+(−3) + 1 + 2 = 3 denominator digits, 1 numerator digit, and 1 is to be
+added to the difference. Therefore there are 1 − 3 + 1 = −1 digits in
+the answer, which is therefore 0·0688. The foregoing method of working
+may confuse the beginner, who is apt to fall into the process of
+continued multiplication. For this reason, until familiarity with
+combined methods has been acquired, the product of the several
+denominators should be first found by the continued multiplication
+process, and the figures in this product determined. Then divide the
+numerator by this product to obtain the result.
+
+As the denominator product will be read on D, we may avoid resetting the
+slide by bringing the numerator on C to this product and reading the
+result on C _over_ the index of D. The slide and rule have here changed
+places; hence if rules are followed for the number of figures in the
+result, 1 must be added to the difference of digits, when the _rule
+projects_ to the _right of the slide_.
+
+The author’s method of recording the number of times division is
+performed with the slide to the right is by vertical memorandum marks,
+thus |. The full significance of these memo-marks will appear in the
+following section.
+
+For a rough calculation to fix the decimal point, in this example we
+move the decimal points in the factors, obtaining
+
+ (3)/(0·8 × 2 × 4 × 6) = (3)/(40) = 0·075.
+
+
+
+
+ THE USE OF THE UPPER SCALES FOR MULTIPLICATION AND DIVISION.
+
+
+Many prefer to use the upper scales A and B, in preference to C and D.
+The disadvantage is that as the scales are only one-half the length of C
+or D, the graduation does not permit of the same degree of accuracy
+being obtained as when working with the lower scales. But the result can
+always be read directly from the rule without ever having to change the
+position of the slide after it has been initially set. Hence, it
+obviates the uncertainty as to the direction in which the slide is to be
+moved in making a setting.
+
+When the A and B scales are employed, it is understood that the
+left-hand pair of scales are to be used in the same manner as C and D,
+and so far the rules relating to the latter are entirely applicable. But
+in this case the slide is always moved to the right, so that in
+multiplication the product is found either upon the left or right scales
+of A. If it is found on the left A scale, the rule for the number of
+digits in the product is found as for the C and D scales, and is equal
+to the _sum of the digits in the two factors, minus 1_; but if found on
+the right-hand A scale, the number of digits in the product is equal to
+the sum of the digits in the two factors.
+
+In division, similar modifications are necessary. If when moving the
+slide to the right the division can be completely effected by using the
+L.H. scale of A, the quotient (read on A above the L.H. of index B) has
+a number of digits equal to the number in the dividend, less the number
+in the divisor, _plus 1_. But if the division necessitates the use of
+both the A scales, the number of digits in the quotient equals the
+number in the dividend, less the number in the divisor.
+
+
+
+
+ RECIPROCALS.
+
+
+A special case of division to be considered is the determination of the
+_reciprocal_ of a number _n_, or (1)/(_n_). Following the ordinary rule
+for division, it is evident that setting _n_ on C to 1 on D, gives
+(1)/(_n_) on D under 1 on C. It is more important to observe that by
+inverting the operation—setting 1 (or 10) on C to _n_ on D—we can read
+(1)/(_n_) on C over 1 (or 10) on D. Hence whenever a result is read on D
+under an index of C, we can also read its reciprocal on C over whichever
+index of D is available.
+
+_The Number of Digits in a Reciprocal_ is obvious when _n_ = 10, 100, or
+any power (_p_) of 10. Thus (1)/(10) = 0·1; (1)/(100) = 0·01;
+(1)/(10^{_p_}) = 1 preceded by _p_ − 1 cyphers. For all other cases we
+have the rule:—_Subtract from 1 the number of digits in the number._
+
+EX.—(1)/(339) = 0·00295.
+
+There are 3 digits in the number; hence, there are 1 − 3 = −2 digits in
+the answer.
+
+EX.—(1)/(0·0000156) = 64,100.
+
+There are −4 digits in the number; hence, there are 1 − (−4) = 5 digits
+in the result.
+
+
+
+
+ CONTINUED MULTIPLICATION AND DIVISION.
+
+
+By combining the rules for multiplication and division, we can readily
+evaluate expressions of the form (_a_)/(_b_) × (_c_)/(_d_) × (_e_)/(_f_)
+× (_g_)/(_h_) = _x_. The simplest case, (_a_ × _c_)/(_b_) can be solved
+by one setting of the slide.[3] Take as an example, (14·45 × 60)/(8·5) =
+102. Setting 8·5 on C to 14·45 on D, we can, if desired, read 1·7 on D
+under 1 on C, as the quotient. However, we are not concerned with this,
+but require its multiplication by 60, and the slide being already set
+for this operation, we at once read under 60 on C the result, 102, on D.
+The figures in the answer are obvious.
+
+When there are more factors to take into account, we place the cursor
+over 102 on D, bring the next divisor on C to the cursor, move the
+cursor to the next multiplier on C, bring the next divisor on C to the
+cursor, and so on, until all the factors have been dealt with. Note that
+only the first factor and the result are read on D; also _that the
+cursor is moved for multiplying and the slide for dividing_.
+
+_Number of Digits in Result in Combined Multiplication and
+Division._—For those who use rules the author’s method of determining
+the decimal point in combined multiplication and division may be used.
+Each time _multiplication_ is performed with the slide projecting to the
+_right_, make a − mark; each time _division_ is effected with the slide
+to the right, make a | mark; _but allow the_ | _marks to cancel the_ −
+_marks as far as they will_. Subtract the sum of the digits in the
+denominator from the sum of digits in the numerator, and to this
+difference _add_ any uncancelled memo-marks, if of | character, or
+_subtract_ them if of − character.
+
+EX.—(43·5 × 29·4 × 51 × 32)/(27 × 3·83 × 10·5 × 1·31) = 1468.
+
+[Sidenote: ⵜ
+ ⵜ
+ ⵏ
+ ⵏ]
+
+Set 27 on C to 43·5 on D, and as with this _division_ the slide is to
+the right, make the first ⵏ mark. Bring cursor to 29·4 on C, and as in
+this _multiplication_ the slide is to the right, make the first − mark,
+cancelling as shown. Setting 3·83 on C to the cursor, requires the
+second ⵏ mark, which, however, is cancelled in turn by the
+multiplication by 51. The division by 10·5 requires the third ⵏ mark,
+and after multiplying by 32 (requiring no mark) the final division by
+1·31 requires the fourth ⵏ mark. Then, as there are 8 numerator digits,
+6 denominator, and 2 uncancelled memo-marks (which, being 1, are
+additive) we have
+
+ Number of digits in result = 8 − 6 + 2 = 4.
+
+Had the uncancelled marks been − in character, the number of digits
+would have been 8 − 6 − 2 = 0.
+
+For quantities less than 0·1 the digit place numbers will be _negative_.
+The troublesome addition of these may be avoided by transferring them to
+the opposite side and treating them as positive.
+
+ _2_ _4_
+ 0·00356 × 27·1 × 0·08375
+ Thus:— ───────────────────────── = 288
+ 0·1426 × 9·85 × 0·00002
+ _2_ _1_ _1_
+
+The first numerator, 0·00356, has −2 digits. Note this by placing 2
+_below the lower line_ as shown. 27·1 has 2 digits; place 2 over it.
+0·08375 has −1 digit; hence place 1 _below the lower line_. The first
+denominator has no digits; the second, 9·85, has 1 digit; hence place 1
+under it. 0·00002 has −4 digits; place 4 _above the upper line_. The sum
+of the top series is 2 + 4 = 6; of the bottom series 2 + 1 + 1 = 4.
+Subtracting the bottom from the top, we have 6 − 4 = 2 digits, to which
+1 has to be added for an uncancelled memo-mark, and the result is read
+as 288.
+
+Moving the decimal point often facilitates matters. Thus, (32·4 × 0·98 ×
+432 × 0·0217)/(4·71 × 0·175 × 0·00000621 × 412000) is much more
+conveniently dealt with when re-arranged as (32·4 × 9·8 × 432 ×
+2·17)/(4·71 × 17·5 × 6·21 × 4·12) = 141.
+
+To determine the number of figures in the result by rough cancelling and
+mental calculation, we note that 4·71 enters 432 about 100 times; 9·8
+enters 17·5 about 2; 6·21 into 32·4 about 5; and 2·17 into 4·12 about 2.
+This gives (500)/(4) = 125, showing that the result contains 3 digits.
+From the slide rule we read 141, which is therefore the result sought.
+
+The occasional traversing of the slide through the rule, to interchange
+the indices—a contingency which the use of the C and D scales always
+involves—may often be avoided by a very simple expedient. Such an
+example as (6·19 × 31·2 × 422)/(1120 × 8·86 × 2.09) = 3·93 is sometimes
+cited as a particularly difficult case. Working through the expression
+as given, two traversings of the slide are necessary; but by taking the
+factors in the slightly different order, (6·19 × 31·2 × 422)/(8·86 ×
+2·09 × 1120), _so that the significant figures of each pair are more
+nearly alike_, we not only avoid any traversing the slide, but we also
+reduce the extent to which the slide is moved to effect the several
+divisions.
+
+Such cases as (_a_ × _b_)/(_c_ × _d_ × _e_ × _f_ × _g_) or (_a_ × _b_ ×
+_c_ × _d_ × _e_)/(_f_ × _g_) really resolve themselves into (_a_ × _b_ ×
+1 × 1 × 1)/(_c_ × _d_ × _e_ × _f_ × _g_) and (_a_ × _b_ × _c_ × _d_ ×
+_e_)/(_f_ × _g_ × 1 × 1 × 1), but, of course, if rules are used to
+locate the decimal point, the 1’s so (mentally) introduced are not to be
+counted as additional figures in the factors.
+
+
+
+
+ MULTIPLICATION AND DIVISION WITH THE SLIDE INVERTED.
+
+
+If the slide be inverted in the rule but with the same face uppermost,
+so that the Ɔ scale lies adjacent to the A scale, and the right and left
+indices of the slide and rule are placed in coincidence, we find the
+product of any number on D by the coincident number on Ɔ (readily
+referred to each other by the cursor) is always 10. Hence, by reading
+the numbers on Ɔ as decimals, we have over any unit number on D, its
+_reciprocal_ on Ɔ. Thus 2 on D is found opposite 0·5 on Ɔ; 3 on D
+opposite to 0·333; while opposite 8 on Ɔ is 0·125 on D, etc. The reason
+of this is that the sum of the lengths of the slide and rule
+corresponding to the factors, is always equal to the length
+corresponding to the product—in this case, 10.
+
+It will be seen that if we attempt to apply the ordinary rule for
+multiplication, with the slide inverted, we shall actually be
+multiplying the one factor taken on D by the _reciprocal_ of the other
+taken on Ɔ. But multiplying by the _reciprocal of a number_ is
+equivalent to _dividing_ by that number, and _dividing_ a factor by the
+_reciprocal_ of a number is equivalent to _multiplying_ by that number.
+It follows that with the slide inverted the operations of multiplication
+and division are reversed, as are also the rules for the number of
+digits in the product and the position of the decimal point. Hence, in
+multiplying with the slide inverted, we place (by the aid of the cursor)
+one factor on Ɔ opposite the other factor on D, and read the result on D
+under either index of Ɔ. It follows that with the slide thus set, any
+pair of coinciding factors on Ɔ and D will give the same constant
+product found on D under the index of Ɔ. One useful application of this
+fact is found in selecting the scantlings of rectangular sections of
+given areas or in deciding upon the dimensions of rectangular sheets,
+plates, cisterns, etc. Thus by placing the index of Ɔ to 72 on D, it is
+readily seen that a plate having an area of 72 sq. ft. may have sides 8
+by 9 ft., 6 by 12, 5 by 14·4, 4 by 18, 3 by 24, 2 by 36, with
+innumerable intermediate values. Many other useful applications of a
+similar character will suggest themselves.
+
+
+
+
+ PROPORTION.
+
+
+With the slide in the ordinary position and with the indices of the C
+and D scales in exact agreement, the _ratio_ of the corresponding
+divisions of these scales is 1. If the slide is moved so that 1 on C
+agrees with 2 on D, we know that under any number _n_ on C is _n_ × 2 on
+D, so that if we read numerators on C and denominators on D we have
+
+ C 1 1·5 2 3 4
+ ─────────────────────────────────────────
+ D1 2 3 4 6 8.
+
+In other words, the numbers on D bear to the coinciding numbers on C a
+ratio of 2 to 1. Obviously the same condition will obtain no matter in
+what position the slide may be placed. The rule for proportion, which is
+apparent from the foregoing, may be expressed as follows:—
+
+RULE FOR PROPORTION.—_Set the first term of a proportion on the C scale
+to the second term on the D scale, and opposite the third term on the C
+scale read the fourth term on the D scale._
+
+
+ EX.—Find the 4th term in the proportion of 20 ∶ 27 ∷ 70 ∶ _x_. Set 20
+ on C to 27 on D, and opposite 70 on C read 94·5 on D. Thus
+
+ C 20 70
+ ─────────────────
+ D 27 94·5.
+
+
+It will be evident that this is merely a case of combined multiplication
+and division of the form, (20 × 70)/(27) = 94·5. Hence, given any three
+terms of a proportion, we set the 1st to the 2nd, or the 3rd to the 4th,
+as the case may be, and opposite the other given term read the term
+required.[4]
+
+Thus, in reducing vulgar fractions to decimals, the decimal equivalent
+of (3)/(16) is determined by placing 3 on C to 16 on D, when over the
+index or 1 of D we read 0·1875 on C. In this case the terms are
+3 ∶ 16 ∷ _x_ ∶ 1. For the inverse operation—to find a vulgar fraction
+equivalent to a given decimal—the given decimal fraction on C is set to
+the index of D, and then opposite any denominator on D is the
+corresponding numerator of the fraction on C.
+
+If the index of C be placed to agree with 3·1416 on D, it will be clear
+from what has been said that this ratio exists throughout between the
+numbers of the two scales. Therefore, against any _diameter_ of a circle
+on C will be found the corresponding _circumference_ on D. In the same
+way, by setting 1 on C to the appropriate conversion factor on D, we can
+convert a series of values in one denomination to their equivalents in
+another denomination. In this connection the following table of
+conversion factors will be found of service. If the A and B scales are
+used instead of the C and D scales, a complete set of conversions will
+be at once obtained. In this case, however, the left-hand A and B scales
+should be used for the initial setting, any values read on the
+right-hand A or B scales being read as of tenfold value. With the C and
+D scales a portion of the one scale will project beyond the other. To
+read this portion of the scale, the cursor or runner is brought to
+whichever index of the C scale falls within the rule, and the slide
+moved until the other index of the C scale coincides with the cursor,
+when the remainder of the equivalent values can then be read off. It
+must be remembered that if the slide is moved in the direction of
+notation (to the _right_), the values read thereon have a tenfold
+_greater_ value; if the slide is moved to the _left_, the readings
+thereon are _decreased_ in a tenfold degree. Although preferred by many,
+in the form given, the case is obviously one of multiplication, and is
+so treated in the Data Slips at the end of the book.
+
+ TABLE OF CONVERSION FACTORS.
+ ───────────────────────────────────────────────────────────────
+ GEOMETRICAL EQUIVALENTS.
+ ──────────────────────────┬──────────────────────────┬─────────
+ SCALE C. │ SCALE D. │If C = 1,
+ │ │ D =
+ ──────────────────────────┼──────────────────────────┼─────────
+ Diameter of circle │Circumference of circle │3·1416
+ „ „ │Side of inscribed square │0·707
+ „ „ │„ equal square │0·886
+ „ „ │„ „ equilateral │
+ │ triangle │1·346
+ Circum. of circle │„ inscribed square │0·225
+ „ „ │„ equal square │0·282
+ Side of square │Diagonal of square │1·414
+ Square inch │Circular inch │1·273
+ Area of circle │Area of inscribed square │0·636
+ ──────────────────────────┴──────────────────────────┴─────────
+ MEASURES OF LENGTH.
+ ──────────────────────────┬──────────────────────────┬─────────
+ Inches │Millimetres │25·40
+ „ │Centimetres │2·54
+ 8ths of an inch │Millimetres │3·175
+ 16ths „ „ │„ │1·587
+ 32nds „ „ │„ │0·794
+ 64ths „ „ │„ │0·397
+ Feet │Metres │0·3048
+ Yards │„ │0·9144
+ Chains │„ │20·116
+ Miles │Kilometres │1·609
+ ──────────────────────────┴──────────────────────────┴─────────
+ MEASURES OF AREA.
+ ──────────────────────────┬──────────────────────────┬─────────
+ Square inches │Square centimetres │6·46
+ Circular „ │„ „ │5·067
+ Square feet │„ metres │0·0929
+ „ yards │„ „ │0·836
+ „ miles │„ kilometres │2·59
+ „ „ │Hectares │259·00
+ Acres │„ │0·4046
+ ──────────────────────────┴──────────────────────────┴─────────
+ MEASURES OF CAPACITY.
+ ──────────────────────────┬──────────────────────────┬─────────
+ Cubic inches │Cubic centimetres │16·38
+ „ „ │Imperial gallons │0·00360
+ „ „ │U.S. gallons │0·00432
+ „ „ │Litres │0·01638
+ Cubic feet │Cubic metres │0·0283
+ „ „ │Imperial gallons │6·23
+ „ „ │U.S. gallons │7·48
+ „ „ │Litres │28·37
+ „ yards │Cubic metres │0·764
+ Imperial gallons │Litres │4·54
+ „ „ │U.S. gallons │1·200
+ Bushels │Cubic metres │0·0363
+ „ │„ feet │1·283
+ ──────────────────────────┴──────────────────────────┴─────────
+ MEASURES OF WEIGHT.
+ ──────────────────────────┬──────────────────────────┬─────────
+ Grains │Grammes │0·0648
+ Ounces (Troy) │„ │31·103
+ „ (Avoird.) │„ │28·35
+ „ „ │Kilogrammes │0·02835
+ Pounds (Troy) │„ │0·3732
+ „ (Avoird.) │„ │0·4536
+ Hundredweights │„ │50·802
+ Tons │„ │1016·4
+ „ │Metric tonnes │1·016
+ ──────────────────────────┴──────────────────────────┴─────────
+ COMPOUND FACTORS—VELOCITIES.
+ ──────────────────────────┬──────────────────────────┬─────────
+ Feet per second │Metres per second │0·3048
+ „ „ │„ minute │18·288
+ „ „ │Miles per hour │0.682
+ „ minute │Meters per second │0·00508
+ „ „ │„ minute │0·3048
+ „ „ │Miles per hour │0·01136
+ Yards per „ │„ „ │0·0341
+ Miles per hour │Metres per minute │26·82
+ Knots │„ „ │30·88
+ „ │Miles per hour │1·151
+ ──────────────────────────┴──────────────────────────┴─────────
+ COMPOUND FACTORS—PRESSURES.
+ ──────────────────────────┬──────────────────────────┬─────────
+ Pounds per sq. inch │Grammes per sq. mm. │0·7031
+ „ „ │Kilos. per sq. centimetre │0·0703
+ „ „ │Atmospheres │0·068
+ „ „ │Head of water in inches │27·71
+ „ „ │„ „ feet │2·309
+ „ „ │„ „ metres │0·757
+ „ „ │Inches of Mercury │2·04
+ Inches of water │Pounds per square inch │0·0361
+ „ „ │Inches of mercury │0·0714
+ „ „ │Pounds per square foot │5·20
+ Inches of mercury │Atmospheres │0·0333
+ Atmospheres │Metres of water │10·34
+ „ │Kilos. per sq. cm. │1·033
+ Feet of water │Pounds per square foot │62·35
+ „ „ │Atmospheres │0·0294
+ „ „ │Inches of mercury │0·883
+ Pounds per sq. foot │„ „ │0·01417
+ „ „ │Kilos. per square metre │4·883
+ „ „ │Atmospheres │0·000472
+ Pounds per sq. yard │Kilos. per square metre │0·5425
+ Tons per sq. inch │„ square mm. │1·575
+ „ sq. foot │Tonnes per square metre │10·936
+ ──────────────────────────┴──────────────────────────┴─────────
+ COMPOUND FACTORS—WEIGHTS, CAPACITIES, ETC.
+ ──────────────────────────┬──────────────────────────┬─────────
+ Pounds per lineal ft. │Kilos. per lineal metre │1·488
+ „ per lineal yd. │„ „ „ │0·496
+ „ per lineal mile │Kilos. per kilometre │0·2818
+ Tons „ „ │Tonnes „ │0·6313
+ Feet „ „ │Metres „ │1·894
+ Pounds per cubic in. │Grammes per cubic cm. │27·68
+ „ per cubic ft. │Kilos. per cubic metre │16·02
+ „ per cubic yd. │„ „ „ │0·593
+ Tons per cubic yard │Tonnes „ „ │1·329
+ Cubic yds. per pound │Cubic metres per kilo. │1·685
+ „ per ton │„ „ per tonne │0·7525
+ Cubic inch of water │Weight in pounds │0·03608
+ Cubic feet of water │„ „ │62·35
+ „ „ │„ kilos │28·23
+ „ „ │Imperial gallons │6·235
+ „ „ │U.S. gallons │7·48
+ Litre of water │Cubic inches │61·025
+ Gallons of water │Weight in kilos │4·54
+ Pounds of fresh water │Pounds of sea water │1·026
+ Grains per gallon │Grammes per litre │0·01426
+ Pounds per gallon │Kilos. per litre │0·0998
+ „ per U.S. gal. │„ „ │0·115
+ ──────────────────────────┴──────────────────────────┴─────────
+ COMPOUND FACTORS—POWER UNITS, ETC.
+ ──────────────────────────┬──────────────────────────┬─────────
+ British Ther. Units. │Kilogrammetres. │108
+ „ „ │Joules │1058
+ „ „ │Calories (Fr. Ther. units)│0·252
+ „ „ per sq. ft. │„ per square metre │2·713
+ „ „ per pound │„ per kilogramme │0·555
+ Pounds per sq. ft. │Dynes, per sq. cm. │479
+ Foot-pounds │Kilogrammetres │0·1382
+ „ „ │Joules │1·356
+ „ „ │Thermal Units │0·00129
+ „ „ │Calorie │0·000324
+ Foot-tons │Tonne-metres │0·333
+ Horse-power │Force decheval (Fr.H.P.) │1·014
+ „ „ │Kilowatts │0·746
+ Pounds per H.P. │Kilos. per cheval │0·447
+ Square feet per H. P. │Square metres per cheval │0·0196
+ Cubic „ „ │Cubic „ „ │0·0279
+ Watts │Ther. Units per hour │3·44
+ „ │Foot-pounds per second │0·73
+ „ │„ per minute │44·24
+ Watt-hours │Kilogrammetres │367
+ „ „ │Joules │3600
+ Kilogrammetres │„ │9·806
+ ──────────────────────────┴──────────────────────────┴─────────
+
+_Inverse Proportion._—If “more” requires “less,” or “less” requires
+“more,” the case is one of _inverse_ proportion, and although it will be
+seen that this form of proportion is quite readily dealt with by the
+preceding method, the working is simplified to some extent by inverting
+the slide so that the C scale is adjacent to the A scale. By the aid of
+the cursor, the values on the inverted C (or Ɔ) scale, and on the D
+scale, can be then read off. These will now constitute a series of
+inverse ratios. For example, in the proportion
+
+ ───────────
+ Ɔ 8 4
+ ───────────
+ D 1·5 3
+
+the 4 on the Ɔ scale is brought opposite 3 on D, when under 8 on Ɔ is
+found 1·5 on D.[5]
+
+
+ GENERAL HINTS ON THE ELEMENTARY USES OF THE SLIDE RULE.
+
+Before the more complex operations of involution, evolution, etc., are
+considered, a few general hints on the use of the slide rule for
+elementary operations may be of service, especially as these will serve
+to enforce some of the more important points brought out in the
+preceding sections.
+
+Always use the slide rule in as _direct_ a light as possible.
+
+Study the manner in which the scales are divided. Follow the graduations
+of the C and D scales from 1 to 10, noting the values given by each
+successive graduation and how these values change as we follow along to
+the right. Do the same with the two halves of the A and B scales and
+note the difference in the value of the subdivisions, due to the shorter
+scale-lengths.
+
+Practise reading values by setting 1 on C to some value on D and reading
+under 2, 3, 4, etc., on C, checking the readings by mental arithmetic.
+To the same end, find squares, square roots, etc., comparing the results
+with the actual values as given in tables. Practise setting both slide
+and cursor to values taken at random. Aim at accuracy; speed will come
+with practice.
+
+When in doubt as to any method of working, verify by making a simple
+calculation of the same form.
+
+Follow the orthodox methods of working until entirely confident in the
+use of the instrument, and even then do not readily make a change. If
+any altered procedure is adopted, first work a simple case and guard
+carefully against unconsciously lapsing into the usual method during the
+operation.
+
+Unless the calculation is of a straightforward character, time taken in
+considering how best to attack it (rearranging the expression if
+desirable) is generally time well spent.
+
+In setting two values together, set the cursor to one of them on the
+rule, and bring the other, on the slide, to the cursor line.
+
+In multiplying factors, as 57 × 0·1256, take the fractional value first.
+It is easier to set 1 on C to 1256 on D and read under 57 on C, than to
+reverse the procedure. When both values are eye-estimated, set the
+cursor to the second factor on C and read the result on D, under the
+cursor line.
+
+In continuous operations avoid moving the slide further than necessary,
+by taking the factors in that order which will keep the scale readings
+as close together as possible.
+
+
+ SQUARES AND SQUARE ROOTS.
+
+We have seen that the relation which the upper scales bear to the lower
+set is such that over any number on D is its square on A, and,
+conversely, under any number on A is its square root on D, the same
+remarks applying to the C and B scales on the slide. Taking the values
+engraved on the rule, we have on D, numbers lying between 1 and 10, and
+on A the corresponding squares extending from 1 to 100. Hence the
+squares of numbers between 1 and 10, or the roots of numbers between 1
+and 100, can be read off on the rule by the aid of the cursor. All other
+cases are brought within these ranges of values by factorising with
+powers of 10, as before explained.
+
+The more practical rule is the following:—
+
+_To Find the Square of a Number_, set the cursor to the number on D and
+read the required square on A under the cursor. The rule for
+
+_The Number of Digits in a Square_ is easily deducible from the rule for
+multiplication. If the square is read on the _left_ scale of A, it will
+contain _twice_ the number of digits in the original number _less_ 1; if
+it is read on the _right_ scale of A, it will contain _twice_ the number
+of digits in the original number.
+
+
+ EX.—Find the square of 114.
+
+ Placing the cursor to 114 on D, it is seen that the coinciding number
+ on A is 13. As the result is read off on the _left_ scale of A, the
+ number of digits will be (3 × 2) − 1 = 5, and the answer is read as
+ 13,000. The true result is 12,996.
+
+ EX.—Find the square of 0·0093.
+
+ The cursor being placed to 93 on D, the number on A is found to be
+ 865. The result is read on the _right_ scale of A, so the number of
+ digits = −2 × 2 = −4, and the answer is read as 0·0000865
+ [0·00008649].
+
+
+_Square Root._—The foregoing rules suggest the method of procedure in
+the inverse operation of extracting the square root of a given number,
+which will be found on the D scale opposite the number on the A scale.
+It is necessary to observe, however, that if the number consists of an
+_odd_ number of digits, it is to be taken on the _left-hand_ portion of
+the A scale, and the number of digits in the root = (N + 1)/(2), N being
+the number of digits in the original number. When there is an even
+number of digits in the number, it is to be taken on the _right-hand_
+portion of the A scale, and the root contains _one-half_ the number of
+digits in the original number.
+
+
+ EX.—Find the square root of 36,500.
+
+ As there is an _odd_ number of digits, placing the cursor to 365 on
+ the L.H. A scale gives 191 on D. By the rule there are (N + 1)/(2) =
+ (5 + 1)/(2) = 3 digits in the required root, which is therefore read
+ as 191 [191·05].
+
+ EX.—Find √(0·0098.)
+
+ Placing the cursor to 98 on the right-hand scale of A (since −2 is an
+ _even_ number of digits), it is seen that the coinciding number on D
+ is 99. As the number of digits in the number is −2, the number of
+ digits in the root will be (−2)/(2) = −1. It will therefore be read as
+ 0·099 [0·09899+].
+
+ EX.—Find √(0·098).
+
+ The number of digits is −1, so under 98 on the left scale of A, we
+ find 313 on D. By the rule the number in the root will be (−1 +1)/(2)
+ = 0, and the root is therefore read as 0·313 [0·313049+].
+
+ EX.—Find √(0·149.)
+
+ As the number of digits (0) is _even_, the cursor is set to 149 on the
+ right-hand scale of A, giving 386 on D. By the rule, the number of
+ digits in the root will be (0)/(2) = 0, and the root will be read as
+ 0·386 [0·38605+].
+
+
+Another method of extracting the square root, by which more accurate
+readings may generally be obtained, is by using the C and D scales only,
+with the slide inverted. If there is an _odd_ number of digits in the
+number, the _right_ index, or if an even number of digits the _left_
+index, of the inverted scale Ɔ is placed so as to coincide with the
+number on D of which the root is sought. Then with the cursor, the
+number is found on D which coincides with the same number on Ɔ, which
+number is the root sought.
+
+
+ EX.—Find √(22·2.)
+
+ Placing the left index of Ɔ to 222 on D, the two equal coinciding
+ numbers on Ɔ and D are found to be 4·71.
+
+
+Note that under the cursor line we have the original number, 22·2, on A,
+and from this the number of digits in the root is determined as before.
+
+The plan of finding the square of a number by ordinary multiplication is
+often very convenient. The inverse process of finding a square root by
+trial division is not to be recommended.
+
+To obtain a close value of a root or to verify one found in the usual
+way, the author has, on occasion, adopted the following plan:—Set 1 (or
+10) on B to the number on the A scale (L.H. or R.H. as the case may
+require), and bring the cursor to the number on D. If the root found is
+correct, the readings on C under the cursor and on D under the index of
+C, will be in exact agreement.
+
+If 1 on B is placed to a number _n_ on the L.H. A scale, the student
+will note that while root _n_ is read on D under 1 on C, the root of 10
+_n_ is read on D under 10 on B. Hence, if preferred, the number can be
+taken always on the first scale of A and the root read under 1 or 10 on
+B, according to whether there is an odd or even number of digits in the
+number. Obviously the second root is the first multiplied by √(10).
+
+
+ CUBES AND CUBE ROOTS.
+
+In raising a number to the third power, a combination of the preceding
+method and ordinary multiplication is employed.
+
+TO FIND THE CUBE OF A NUMBER.—_Set the_ L.H. _or_ R.H. _index of C to
+the number on D, and opposite the number_ ON THE LEFT-HAND _scale of B
+read the cube on the_ L.H. _or_ R.H. _scale of A_.
+
+By this rule four scales are brought into requisition. Of these, the D
+scale and the L.H. B scale are _always_ employed, and are to be read as
+of equal denomination. The values assigned to the L.H. and R.H. scales
+of A will be apparent from the following considerations.
+
+Commencing with the indices of C and D coinciding, and moving the slide
+to the right, it will be seen that, working in accordance with the above
+rule, the cubes of numbers from 1 to 2·154 (= ∛(10)) will be found on
+the first or L.H. scale of A. Moving the slide still farther to the
+right, we obtain _on the_ R.H. _A scale_ cubes of numbers from 2·154 to
+4·641 (or ∛(10) to ∛(100)). Had we a _third_ repetition of the L.H. A
+scale, the L.H. index of C could be still further traversed to the
+right, and the cubes of numbers from 4·641 to 10 read off on this
+prolongation of A. But the same end can be attained by making use of the
+R.H. index of C, when, traversing the slide to the right as before, the
+cubes of numbers from 4·641 to 10 on D can be read off _on the_ L.H. _A
+scale_ over the corresponding numbers on the L.H. B scale. Hence, using
+the L.H. index of C, the readings on the L.H. A scale may be regarded
+comparatively as units, those on the R.H. A scale as tens; while for the
+hundreds we again make use of the L.H. A scale in conjunction with the
+_right-hand_ index of C.
+
+By keeping these points in view, the number of digits in the cube (N) of
+a given number (_n_) are readily deduced. Thus, if the units scale is
+used, N = 3_n_ − 2; if the tens scale, N = 3_n_ − 1; while if the
+hundreds scale be used, N = 3_n_. Placed in the form of rules:—
+
+N = 3_n_ − 2 when the product is read on the L.H. scale of A with the
+slide to the _right_ (units scale).
+
+N = 3_n_ − 1 when the product is read on the R.H. scale of A; slide to
+the _right_ (tens scale).
+
+N = 3_n_ when the product is read on the L.H. scale of A with the slide
+to the _left_ (hundreds scale).
+
+With decimals the same rule applies, but, as before, the number of
+digits must be read as −1, −2, etc., when one, two, etc., cyphers follow
+immediately after the decimal point.
+
+EX.—Find the value of 1·4^3.
+
+Placing the L.H. index of C to 1·4 on D, the reading on A opposite 1·4
+on the L.H. scale of B is found to be about 2·745 [2·744].
+
+EX.—Find the value of 26·4^3.
+
+Placing the L.H. index of C to 26·4 on D, the reading on A opposite 26·4
+on the L.H. scale of B is found to be about 18,400 [18,399·744].
+
+EX.—Find the value of 7·3^3.
+
+In this case it becomes necessary to use the R.H. index of C, which is
+set to 7·3 on D, when opposite 7·3 on the L.H. scale of B is read 389
+[389·017] on A.
+
+EX.—Find the value of 0·073^3.
+
+From the setting as before it is seen that the number of digits in the
+number must be multiplied by 3. Hence, as there is −1 digit in 0·073,
+there will be −3 in the cube, which is therefore read 0·000389.
+
+The last two examples serve to illustrate the principle of factorising
+with powers of 10. Thus
+
+ 0·073 = 7·3 × 10^{−2}; 0·073^3 = 7·3^3 × (10^{−2})^3 = 389 × 10^{−6} =
+ 0·000389.
+
+_Cube Root_ (_Direct Method_).—One method of extracting the cube root of
+a number is by an inversion of the foregoing operation. Using the same
+scales, _the slide is moved either to the right or left until under the
+given number on A is found a number on the_ L.H. _B scale, identical
+with the number simultaneously found on D under the right or left index
+of C_. This number is the required cube root.
+
+From what has already been said regarding the combined use of these
+scales in cubing, it will be evident that in extracting the cube root of
+a number, it is necessary, in order to decide which scales are to be
+used, to know the number of figures to be dealt with. We therefore (as
+in the arithmetical method of extraction) point off the given number
+into sections of three figures each, commencing at the decimal point,
+and proceeding to the left for numbers greater than unity, and to the
+right for numbers less than unity. Then if the first section of figures
+on the left consists of—
+
+1 figure, the number will evidently require to be taken on what we have
+called the “units” scale—_i.e._, on the L.H. scale of A, using the L.H.
+index of C.
+
+If of 2 figures, the number will be taken on the “tens” scale—_i.e._, on
+the R.H. scale of A, using the L.H. index of C.
+
+If of 3 figures, the number will be taken on the “hundreds”
+scale—_i.e._, on the L.H. scale of A, using the R.H. index of C.
+
+To determine the number of digits in cube roots it is only necessary to
+note that when the number is pointed off into sections as directed,
+there will be one figure in the root for every section into which the
+number is so divided, whether the _first_ section consists of 1, 2, or 3
+digits.
+
+Of numbers wholly decimal, the cube roots will be decimal, and for every
+group of _three_ 0s immediately following the decimal point, _one_ 0
+will follow the decimal point in the root. If necessary, 0s must be
+added so as to make up complete multiples of 3 figures before proceeding
+to extract the root. Thus 0·8 is to be regarded as 0·800, and 0·00008 as
+0·000080 in extracting cube roots.
+
+EX.—Find ∛(14,000.)
+
+Pointing the number off in the manner described, it is seen that there
+are _two_ figures in the first section—viz., 14. Setting the cursor to
+14 on the R.H. scale of A, the slide is moved to the right until it is
+seen that 241 on the L.H. scale of B falls under the cursor, when 241 on
+D is under the L.H. index of C. Pointing 14,000 off into sections we
+have 14 000—that is, _two_ sections. Therefore, there are two digits in
+the root, which in consequence will be read 24·1 [24·1014+].
+
+EX.—Find ∛(0·162.)
+
+As the divisional section consists of _three_ figures, we use the
+“hundreds” scale. Setting the cursor to 0·162 on the L.H. A scale, and
+using the R.H. index of C, we move the slide to the left until under the
+cursor 0·545 is found on the L.H. B scale, while the R.H. index of C
+points to 0·545 on D, which is therefore the cube root of 0·162.
+
+EX.—Find ∛(0·0002.)
+
+To make even multiples of 3 figures requires the addition of 00; we have
+then 200, the cube root of which is found to be about 5·85. Then, since
+the first divisional group consists of 0s, one 0 will follow the decimal
+point, giving ∛(0·0002) = 0·0585 [0·05848].
+
+_Cube Root (Inverted Slide Method)._—Another method of extracting the
+cube root involves the use of the inverted slide. Several methods are
+used, but the following is to be preferred:—_Set the_ L.H. _or_ R.H.
+_index of the slide to the number on A, and the number on ᗺ (i.e., B
+inverted), which coincides with the same number on D, is the required
+root._
+
+Setting the slide as directed, and using first the L.H. index of the
+slide and then the R.H. index, it is always possible to find _three_
+pairs of coincident values. To determine which of the three is the
+required result is best shown by an example.
+
+
+ EX.—Find ∛(5,) ∛(50,) and ∛(500.)
+
+ Setting the R.H. index of the slide to 5 on A, it is seen that 1·71 on
+ D coincides with 1·71 on ᗺ. Then setting the L.H. index to 5 on A,
+ further coincidences are found at 3·68 and at 7·93, the three values
+ thus found being the required roots. Note that the first root was
+ found on that portion of the D scale lying under 1 to 5 on A; the
+ second root on that portion lying under 5 to 50 on A; and the third
+ root on that portion of D lying under 50 to 100 on A. In this
+ connection, therefore, scale A may always be considered to be divided
+ into three sections—viz., 1 to _n_, _n_ to 10_n_, and 10_n_ to 100.
+ For all numbers consisting of 1, 1 + 3, 1 + 6, 1 + 9—_i.e._, of 1, 4,
+ 7, 10, or −2, −5, etc., figures—the coincidence under the first
+ section is the one required. If the number has 2, 5, 8, or −1, −4, −7,
+ etc., figures, the coincidence under the second section is correct,
+ while if the number has 3, 6, 9, or 0, −3, etc., figures, the
+ coincidence under the last section is that required. The number of
+ digits in the root is determined by marking off the number into
+ sections, as already explained.
+
+
+_Cube Root (Pickworth’s Method)._—One of the principal objections to the
+two methods described is the difficulty of recollecting which scales are
+to be employed and with which index of the slide they are to be used.
+With the direct method another objection is that the readings to be
+compared are often some distance apart, the maximum distance intervening
+being _two-thirds_ of the length of the rule. To carry the eye from one
+to another is troublesome and time-taking. With the inverted scale
+method the reading of a scale reversed in direction and with the figures
+inverted is also objectionable.
+
+With the author’s method these objections are entirely obviated. The
+_same scales and index are always used_, and are read in their normal
+position. The three roots of _n_, 10_n_ and 100_n_ (_n_ being less than
+10 and not less than 1) are given with one setting and appear in their
+natural sequence, no traversing of the slide being needed. The readings
+to be compared are always close together, the maximum distance between
+them being _one-sixth_ of the length of the rule. The setting is always
+made in the earlier part of the scales where closer readings can be
+obtained, and finally, if desired, the result may be readily verified on
+the lower scales by successive multiplication.
+
+For this method two gauge points are required on C. To conveniently
+locate these, set 53 on C to 246 on D; join 1 on D to 1 on A with a
+straight-edge and with a needle point draw a short fine line on C. Set
+246 on C to 53 on D, and repeat the process at the other end of the
+rule. The gauge points thus obtained (dividing C into three equal parts)
+will be at 2·154 and 4·641, and should be marked ∛(10) and ∛(100)
+respectively.[6]
+
+
+ EX.—Find ∛(2·86,) ∛(28·6) and ∛(286).
+
+ Set cursor to 2·86 on A and drawing the slide to the right find 1·42
+ under 1 on C, when 1·42 on B is under the cursor. Then reading under
+ 1, ∛(10) and ∛(100,) we have
+
+ ∛(2·86) = 1·42; ∛(28·6) = 3·06 and ∛(286) = 6·59.
+
+
+It will be seen that factorising with powers of 10, we multiply the
+initial root by ∛(10) and ∛(100). Obviously the three roots will always
+be found on D, in their natural order and at intervals of one-third the
+length of the rule. The number of digits in the roots of numbers which
+do not lie between 1 and 1000, is found as before explained.
+
+In any method of extracting cube roots in which the slide has to be
+adjusted to give equal readings on B and D, the author has found it of
+advantage to adopt the following plan:—The cursor being set to, say, 4·8
+on A, bring a near _main_ division line on B, as 1·7, to the cursor;
+then 1 on C is at 1·68 on D. The difference in the readings is two small
+divisions on D, and moving the slide forward by _one-third the space
+representing this difference_, we obtain 1·687 as the root required.
+With a little practice it is possible to obtain more accurate results by
+this method than by comparing the reading on D with that on the less
+finely-graded B scale.
+
+
+ MISCELLANEOUS POWERS AND ROOTS.
+
+In addition to squares and cubes, certain other powers and roots may be
+readily obtained with the slide rule.
+
+_Two-thirds Power._—The value of N^⅔ is found on A over ∛̅N on D. The
+number of digits is decided by the rule for squares, working from the
+number of digits in the cube root. It will often be found preferable to
+treat N^⅔ as N ÷ ∛̅N, as in this way the magnitude of the result is much
+more readily appreciated.
+
+_Three-two Power._—N^{³⁄₂} can be obtained by cubing the square root,
+deciding the number of digits in each process. For the reason just
+given, it is preferable to regard N^{³⁄₂} as N × √̅N.
+
+_Fourth Power._—For N^4 set the index of C to N on D and over N on C
+read N^4 on A; or find the square of the square of N, deciding the
+number of digits at each step.
+
+_Fourth Root._—Similarly for ∜̅N, take the square root of the square
+root.
+
+_Four-third Power._—N^{⁴⁄₃} = N^{1·33} (useful in gas-engine diagram
+calculations) is best treated as N × ∛̅N.
+
+Other powers can be found by repeated multiplication. Thus setting 1 on
+B to N on A, we have on A, N^2 over N; N^3 over N^2; N^4 over N^3; N^5
+over N^4, etc. In the same way, setting N on B to N on D, we can read
+such values as N^¾, N^⅞, etc.
+
+
+ POWERS AND ROOTS BY LOGARITHMS.
+
+For powers or roots other than those of the simple forms already
+discussed, it is necessary to employ the usual logarithmic process. Thus
+to find _a^n_ = _x_, we multiply the logarithm of _a_ by _n_, and find
+the number _x_ corresponding to the logarithm so obtained. Similarly, to
+find _ⁿ√̅a_ = _x_ we divide the logarithm of _a_ by _n_, and find the
+number _x_ corresponding to the resulting logarithm.
+
+_The Scale of Logarithms._—Upon the back of the slide of the Gravêt and
+similar slide rules there will be found three scales. One of
+these—usually the centre one—is divided equally throughout its entire
+length, and figured from right to left. It is sometimes marked L,
+indicating that it is a scale giving logarithms. The whole scale is
+divided primarily into ten equal parts, and each of these subdivided
+into 50 equal parts. In the recess or notch in the right-hand end of the
+rule is a reference mark, to which any of the divisions of this
+evenly-divided scale can be set.
+
+As this decimally-divided scale is equal in length to the logarithmic
+scale D, and is figured in the reverse direction, it results that when
+the slide is drawn to the right so that the L.H. index of C coincides
+with any number on D, the reading on the equally-divided scale will give
+the decimal part of the logarithm of the number taken on D. Thus if the
+L.H. index of C is placed to agree with 2 on D, the reading of the back
+scale, taken at the reference mark, will be found to be 0·301, the
+logarithm of 2. It must be distinctly borne in mind that the number so
+obtained is the _decimal part_ or _mantissa_ of the logarithm of the
+number, and that to this the characteristic must be prefixed in
+accordance with the usual rule—viz., _The integral part, or
+characteristic of a logarithm is equal to the number of digits in the
+number, minus 1. If the number is wholly decimal, the characteristic is
+equal to the number of cyphers following the decimal point, plus 1._ In
+the latter case the characteristic is negative, and is so indicated by
+having the minus sign written _over_ it.
+
+To obtain any given power or root of a number, the operation is as
+follows:—Set the L.H. index of C to the given number on D, and turning
+the rule over, read opposite the mark in the notch at the right-hand end
+of the rule, the decimal part of the logarithm of the number. Add the
+characteristic according to the above rule, and multiply by the exponent
+of the power, or divide by the exponent of the root. Place the _decimal
+part_ of the resultant reading, taken on the scale of equal parts,
+opposite the mark in the aperture of the rule, and read the answer on D
+under the L.H. index of C, pointing off the number of digits in the
+answer in accordance with the number of the characteristic of the
+resultant.
+
+
+ EX.—Evaluate 36^{1·414}.
+
+ Set 1 on C to 36 on D and read the decimal part of log. 36 on the
+ scale of logarithms on the back of the slide. This value is found to
+ be 0·556. As there are two digits in the number, the characteristic
+ will be 1; hence log. 36 = 1·556. Multiply by 1·414, using the C and D
+ scales, and obtain 2·2 as the log. of the result. Set the decimal
+ part, 0·2, on the log. scale to the mark in the notch at the end of
+ the rule and read 1585 on D under 1 on C. Since the log. of the result
+ has a characteristic 2, there will be 3 digits in the result, which is
+ therefore read as 158·5.
+
+
+This example will suffice to show the method of obtaining the nth power
+or the _n_th root of _any_ number.
+
+
+
+
+ OTHER METHODS OF OBTAINING POWERS AND ROOTS.
+
+
+A simple method of obtaining powers and roots, which may serve on
+occasion, is by scaling off proportional lengths on the D scale (or the
+A scale) of the ordinary rule. Thus, to determine the value of
+1·25^{1·67} we take the actual length 1–1·25 on D scale, and increase it
+by any convenient means in the proportion of 1 ∶ 1·67. Then with a pair
+of dividers we set off this new length from 1, and obtain 1·44 as the
+result. One convenient method of obtaining the desired ratio is by a
+pair of proportional compasses. Thus to obtain 1·52^{¹⁷⁄₁₆}, the
+compasses would be set in the ratio of 16 to 17, and the smaller end
+opened out to include 1–1·52 on the D scale; the opening in the large
+end of the compasses will then be such that setting it off from 1 we
+obtain 1·56 on D as the result sought.
+
+[Illustration: FIG. 11.]
+
+The converse procedure for obtaining the _n_th root of a number N will
+obviously resolve itself into obtaining (1)/(_n_)th of the scale length
+1-N, and need not be further considered.
+
+Simple geometrical constructions are also used for obtaining scale
+lengths in the required ratio. A series of parallel lines ruled on
+transparent celluloid or stout tracing paper may be placed in an
+inclined position on the face of the rule and adjusted so as to divide
+the scale as desired. When much work is to be done which requires values
+to be raised to some constant but comparatively low power, _n_, the
+author has found the following device of assistance:—On a piece of thin
+transparent celluloid a line OC is drawn (Fig. 11) and in this a point B
+is taken such that (OC)/(OB) is the desired ratio. It is convenient to
+make OB = 1–10 on the A scale, so that assuming we require a series of
+values of _v_^{1·35}, OB would be 12·5 cm. and OC, 16·875 cm. On these
+lines semi-circles are drawn as shown, both passing through the point O.
+
+Applying this cursor to the upper scales so that the point O is on 1 and
+the semi-circle O M B passes through _v_ on A, the larger semi-circle
+will give on A the value of _v^n_. Thus for _p_ _v^n_ = 39·5 ×
+4·9^{1·35}, set 1 on B to 39·5 on A (Fig. 12) and apply the cursor to
+the working edge of B, so that O agrees with 1 and O M B passes through
+4·9 on B. The larger semi-circle then cuts the edge of the slide on a
+point, giving 337 on A as the result required.
+
+Of course any number of semi-circles may be drawn, giving different
+ratios. If a number of evenly-spaced divisions are used as bases, the
+device affords a simple means of obtaining a succession of small powers
+or roots, while it also finds a use in determining a number of geometric
+means between two values as is required in arranging the speed gears of
+machine tools, etc. The converse operation of finding roots will be
+evident as will also many other uses for which the device is of service.
+
+[Illustration: FIG. 12.]
+
+The lines should be drawn in Indian ink with a very sharp pen and on the
+_under_ side of the celluloid so that the lines lie in close contact
+with the face of the rule.
+
+_The Radial Cursor_, another device for the same purpose, is always used
+in conjunction with the upper scales. As will be seen from Fig. 13, the
+body of the cursor P carries a graduated bar S which can be removed in a
+direction transverse to the rule, and adjusted to any desired position.
+Pivoted to the lower end of S is a radial arm R of transparent celluloid
+on which a centre line is engraved.
+
+A reference to the illustration will show that the principle involved is
+that of similar triangles, the width of the slide being used as one of
+the elements. Thus, to take a simple case, if 2 on S is set to the index
+on P, and 1 on B is brought to N on A, then by swinging the radial arm
+until its centre line agrees with 1 on C, we can read N^2 on A.
+Evidently, since in the two similar triangles A O N^2 and N _t_ N^2 the
+length of A O is twice that of N _t_, it results that A N^2 = 2 A N. In
+general, then, to find the _n_th power of a number, we set the cursor to
+1 or 10 on A, bring _n_ on the cross bar S to the index on the cursor,
+and 1 on B to N on A. Then to 1 on C we set the line on the radial arm,
+and under the latter read N^{_n_} on A. The inverse proceeding for
+finding the _n_th root will be obvious.
+
+[Illustration: FIG. 13.]
+
+An advantage offered by this and analogous methods of obtaining powers
+and roots is that the result is obtained on the ordinary scale of the
+rule, and hence it can be taken directly into any further calculation
+which may be necessary.
+
+
+ COMBINED OPERATIONS.
+
+Thus far the various operations have been separately considered, and we
+now pass on to a consideration of the methods of working for solving the
+various formulæ met with in technical calculations. We propose to
+explain the methods of dealing with a few of the more generally used
+expressions, as this will suffice to suggest the procedure in dealing
+with other and more intricate calculations. In solving the following
+problems, both the upper and lower scales are used, and the relative
+value of the several scales must be observed throughout. Thus, in
+solving such an expression as √((74·5)/(15·8)) = 6·86, the division is
+first effected by setting 15·8 on B to 745 on A. From the relation of
+the two parts of the upper scales (page 37) we know that such values as
+7·45, 745, etc., will be taken on the _left-hand_ A and B scales, while
+values as 15·8, 1580, etc., will be taken on the _right-hand_ A and B
+scales. Hence, 15·8 on the R.H. B scale is set to 745 on the L.H. A
+scale, and the result read on D under the index of C. Had both values
+been taken on the L.H. A and B scales, or both on the R.H. A and B
+scales, the results would have corresponded to _x_ = √((7·45)/(1·58)) =
+2·17, or to _x_ =√((74·5)/(15·8)) = 2·17, _i.e_., to (6·86)/(√(10)).
+Hence if a wrong choice of scales has been made, we can correct the
+result by multiplying or dividing by √(10) as the case may require. If
+the result is read on D, set to it the centre index (10) of B and read
+the corrected result under the index of C.
+
+To solve _a_ × _b_^2 = _x_. Set the index of C to _b_ on D, and over _a_
+on B read _x_ on A.
+
+To solve (_a_^2)/(_b_) = _x_. Set _b_ on B to _a_ on D by using the
+cursor, and over index of B read _x_ on A.
+
+To solve (_b_)/(_a_^2) = _x_. Set _a_ on C to _b_ on A, and over 1 on B
+read _x_ on A.
+
+To solve (_a_ × _b_^2)/(_c_) = _x_. Set _c_ on B to _b_ on D, and over
+_a_ on B read _x_ on A.
+
+To solve (_a_ × _b_)^2 = _x_. Set 1 on C to _a_ on D, and over _b_ on C
+read _x_ on A.
+
+To solve ((_a_)/(_b_))^2 = _x_. Set _b_ on C to _a_ on D, and over 1 on
+C read _x_ on A.
+
+To solve √(_a_ × _b_) = _x_. Set 1 on B to _a_ on A, and under _b_ on B
+read _x_ on D.
+
+To solve √((_a_)/(_b_)) = _x_. Set _b_ on B to _a_ on A, and under 1 on
+C read _x_ on D.
+
+To solve _a_ (_b_)/(_c_^2) = _x_. Set _b_ on C to _c_ on D and over _a_
+on B read _x_ on A.
+
+To solve _c_√((_a_)/(_b_)) = _x_. Set _b_ on B to _a_ on A, and under
+_c_ on C read _x_ on D.
+
+To solve (√_̅a_)/(_b_) = _x_. Set _b_ on C to _a_ on A, and under 1 on C
+read _x_ on D.
+
+To solve (_a_)/(√_̅b_) = _x_. Set _b_ on B to _a_ on D, and under 1 on C
+read _x_ on D.
+
+To solve _b_√_̅a_ = _x_. Set 1 on C to _b_ on D, and under _a_ on B read
+_x_ on D.
+
+To solve √(_a_^3) = _x_. Treat as _a_√_̅a_.
+
+To solve _a_√(_b_^3) = _x_. Treat as _a_√_̅b_ × _b_.
+
+To solve (√_̅a_^3)/(_b_) = _x_. Treat as (√_̅a_ × _a_)/(_b_).
+
+To solve √((_a_^3)/(_b_)) = _x_. Treat as (√_̅a_ × _a_)/(√_̅b_) =
+√((_a_)/(_b_)) × _a_.
+
+To solve √((_a_ × _b_)/(_c_)) = _x_. Set _c_ on B to _a_ on A, and under
+_b_ on B read _x_ on D.
+
+To solve (_a_ × _b_)/(√_̅c_) = _x_. Set _c_ on B to _b_ an D, and under
+_a_ on C read _x_ on D.
+
+To solve √((_a_^2 × _b_)/(_c_)) = _x_. Set _c_ on B to _a_ on D, and
+under _b_ on B read _x_ on D.
+
+To solve (_a_^2 × _b_^2)/(_c_) = _x_. Set _c_ on B to _a_ on D, and over
+_b_ on C read _x_ on A.
+
+To solve (_a_√_̅b_)/(_c_) = _x_. Set _c_ on C to _b_ on A, and under _a_
+on C read _x_ on D.
+
+To solve ((_a_ × √_̅b_)/(_c_))^2 = _x_. Set _c_ on C to _a_ on D,
+and over _b_ on B read _x_ on A.
+
+
+ HINTS ON EVALUATING EXPRESSIONS.
+
+As a general rule, the use of cubes and higher powers should be avoided
+whenever possible. Thus, in the foregoing section, we recommend treating
+an expression of the form _a_√(_b_^3) as _a_ × _b_ × √_̅b_; the
+magnitudes of the values thus met with are more easily appreciated by
+the beginner, and mistakes in estimating the large numbers involved in
+cubing are avoided.
+
+
+ EX.—7·3 × √(57^3) = 3140.
+
+ Set 1 on C to 57 on D; bring cursor to 57 on B (R.H., since 57 has an
+ _even_ number of digits); bring 1 on C to cursor, and under 7·3 on C
+ read 3140 on D. As a rough estimate we have √(57), about 8; 8 × 57,
+ about 400; 400 × 7, gives 2800, showing the result consists of 4
+ figures.
+
+
+An expression of the form _a_∛(_b_^2), or _a_ _b_^⅔, is better dealt
+with by rearranging as _a_ × (_b_)/(∛_b_).
+
+
+ EX.—3·64∛(4·32^2) = 9·65.
+
+ Set cursor to 4·32 on A, and move the slide until 1·63 is found
+ simultaneously under the cursor on B and on D under 1 on C; bring
+ cursor to 1 on C; 4·32 on C to cursor, and _over_ 3·64 on D read 9·65
+ on C. (Note that in this case it is convenient to read the answer on
+ the _slide_; see page 22). From the slide rule we know ∛(4·32) = about
+ 1·6; this into 4·32 is roughly 3; 3·64 × 3 is about 10, showing the
+ answer to be 9·65.
+
+
+Similarly products of the form _a_ × _b_^{⁴⁄₃} are best dealt with as
+_a_ × _b_ × ∛_b_.
+
+Factorising expressions sometimes simplifies matters, as, for instance,
+in _x_^4 − _y_^4 = (_x_^2 + _y_^2)(_x_^2 − _y_^2). Here, working with
+the fourth powers involves large numbers and the troublesome
+determination of the number of digits in each factor; but squares are
+read on the rule at once, the number of digits is obvious, and, in
+general, the method should give a more accurate result. Take the
+expression, D_{1} = ∛((D^4 − _d_^4)/(D)) giving the diameter D_{1} of a
+solid shaft equal in torsional strength to a hollow shaft whose external
+and internal diameters are D and _d_ respectively. Rearranging as D_{1}
+= ∛(((D^2 + _d_^2)(D^2 − _d_^2))/(D)) and taking, as an example, D = 15
+in. and _d_ = 7 in., we have D^2 + _d_^2 = 274 and D^2 − _d_^2 = 176;
+hence D_1 = ∛((274 × 176)/(15)) = ∛(3210) = 14·75 in.
+
+_Reversed Scale Notation._—With expressions of the form 1 − _x_, or 100
+− _x_, it is often convenient to regard the scales as having their
+notation reversed, _i.e._, to read the scale backwards. When this is
+done the D scale is read as shown on the lower line—
+
+ Direct Notation 1 2 3 4 5 6 7 8 9 10
+ D Scale
+ Reversed Notation 9 8 7 6 5 4 3 2 1 0
+
+The new reading can be found by subtracting the ordinary reading from 1,
+10, 100, etc., according to the value assigned to the R.H. index, but
+actually it is unnecessary to make this calculation, as with a little
+practice it is quite an easy matter to read both the main and
+subdivisions in the reversed order. Applications are found in plotting
+curves, trigonometrical formulæ, etc.
+
+
+ EX.—Find the per cent. of slip of a screw propeller from
+
+ 100 − S = (10133V)/(PR)
+
+ taking the speed, V, as 15 knots, the pitch of the propeller, P, as 27
+ ft. 6 in., and the revolutions per minute, R, as 60.
+
+ Set 27·5 on B to 10133 on A (N.B.—Take the setting near the _centre_
+ index of A); bring the cursor to 15 on B and 60 on B to cursor.
+ Reading the L.H. A scale backwards, the slip, S, = 8 per cent. is
+ found on A over 10 on B.
+
+
+_Percentage Calculations._—To increase a quantity by _x_ per cent. we
+multiply by 100 + _x_; to diminish a quantity by _x_ per cent. we
+multiply by 100 − _x_. Hence, to add _x_ per cent., set 100 + _x_ on C
+to 1 on D and read new values on D under original values on C. To deduct
+_x_ per cent. read the D scale backwards from 10 and set R.H. index of C
+to _x_ per cent. so read. Then read as before.
+
+
+ GAUGE POINTS.
+
+Special graduations, marking the position of constant factors which
+frequently enter into engineering calculations, are found on most slide
+rules. Usually the values of π = 3·1416 and (π)/(4) = 0·7854—the “gauge
+points” for calculating the circumference and area of a circle—are
+marked on the upper scales. The first should be given on the lower
+scales also. Marks _c_ and _c_^1 are sometimes found on the lower scales
+at 1·128 = √((4)/(π)) and at 3·568 = √((40)/(π)). These are useful in
+calculating the contents of cylinders and are thus derived:—Cubic
+contents of cylinder of diameter _d_ and length _l_ = (π)/(4)_d_^2_l_;
+substituting for (π)/(4) its reciprocal (4)/(π), the formula becomes
+(_d_^2)/(1·273 × _l_), and by taking the square root of the fractional
+part we have (_d_)/(1·128)^2 × _l_. This is now in a very convenient
+form, since by setting the gauge point _c_ on C to _d_ on D, we can read
+over _l_ on B the cubic contents on A. This example indicates the
+principle to be followed in arranging gauge points. Successive
+multiplication is avoided by substituting the reciprocal of the
+constant, thus bringing the expression into the form (_a_ × _b_)/(_c_),
+which, as we know, can be resolved by one setting of the slide. The
+advantage of dividing _d_ before squaring is also evident. The mark
+_c_^1 = _c_ × √(10) is used if it is necessary to draw the slide more
+than one-half its length to the right.
+
+A gauge point, M, at 31·83 = (100)/(π) is found on the upper scales of
+some rules. Setting this point on B to the diameter of a cylinder on A,
+the circumference is read over 1 or 100 on B or the area of the curved
+surface over the length on B.
+
+As another example of establishing a gauge point, we will take the
+formula for the theoretical delivery of pumps. If _d_ is the diameter of
+the plunger in inches, _l_ the length of stroke in feet, and Q the
+delivery in gallons, we have
+
+Q = _d_^2 × (π)/(4) × _l_ × (12)/(277). (N.B.—277 cubic inches = 1
+gallon.)
+
+Multiplying out the constant quantities and taking its reciprocal, we
+readily transform the statement into Q = (_d_^2_l_)/(29·4) or
+((_d_)/(5·42))^2 × _l_. Hence set gauge point 5·42 on C to _d_ on
+D and over length of stroke in feet on B, read delivery in gallons per
+stroke on A; or over piston speed in feet per minute on B, read
+theoretical delivery in gallons per minute on A.
+
+Several examples of gauge points will be found in the section on
+calculating the weights of metal (see pages 59 and 60). In most cases
+their derivation will be evident from what has been said above. In the
+case of the weight of spheres, we have Vol. = 0·5236_d_^3, and this
+multiplied by the weight of 1 cubic inch of the material will give the
+weight W in lb. Hence for cast-iron, W = 0·5236 × _d_^3 × 0·26, which is
+conveniently transformed into W = (_d_ × _d_^2)/(7·35) as in the example
+on page 60.
+
+With these examples no difficulty should be experienced in establishing
+gauge points for any calculation in which constant factors recur.
+
+_Marking Gauge Points._—The practice of marking gauge points by lines
+extending to the working edge of the scale is not to be recommended, as
+it confuses the ordinary reading of the scales. Generally speaking,
+gauge points are only required occasionally, and if they are placed
+clear of the scale to which they pertain, but near enough to show the
+connection, they can be brought readily into a calculation by means of
+the cursor. Usually there is sufficient margin above the A scale and
+below the D scale for various gauge points to be marked. Another plan
+consists in cutting two nicks in the upper and lower edges of the cursor
+near the centre and about ⅛ in. apart. These centre pieces, when bent
+out, form a tongue, which are in line with the cursor line and run
+nearly in contact with the square and bevelled edges of the rule
+respectively. A fine line in the tongue can then be set to gauge points
+marked on these two edge strips, the ordinary measuring graduations
+being removed, if desired, by a piece of fine sand-paper.
+
+For gauge points marked on the face of the rule, the author prefers two
+fine lines drawn at 45°—thus, ✕—and crossing in the exact point which it
+is required to indicate. With the “cross” gauge point the meeting lines
+facilitate the placing of the cursor, and an exact setting is readily
+made.[7] All lines should be drawn in Indian ink with a very sharp
+drawing pen. For a more permanent marking the Indian ink may be rubbed
+up in glacial acetic acid or the special ink for celluloid may be used.
+If any difficulty is found in writing the distinguishing signs against
+the gauge point, the inscription may be formed by a succession of small
+dots made with a sharp pricker.
+
+
+ EXAMPLES IN TECHNICAL CALCULATIONS.
+
+In order to illustrate the practical value of the slide rule, we now
+give a number of examples which will doubtless be sufficient to suggest
+the methods of working with other formulæ. A few of the rules give
+results which are approximate only, but in all cases the degree of
+accuracy obtained is well within the possible reading of the scales. In
+many cases the rules given may be modified, if desired, by varying the
+constants. In most of the examples the particular formula employed will
+be evident from the solution, but in a few of the more complicated cases
+a separate statement has been given.
+
+
+ MENSURATION, ETC.
+
+Given the chord _c_ of a circular arc, and the vertical height _h_, to
+find the diameter _d_ of the circle.
+
+Set the height _h_ on B to half the chord on D, and over 1 on B read _x_
+on A. Then _x_ + _h_ = _d_.
+
+
+ EX.—_c_ = 6; _h_ = 2; find _d_. Set 2 on B to 3 on D, and over 1 on B
+ read 4·5 on A. Then 4·5 + 2 = 6·5 = _d_.
+
+
+Given the radius of a circle _r_, and the number of degrees _n_ in an
+arc, to find the length _l_ of the arc.
+
+Set _r_ on C to 57·3 on D, and over any number of degrees _n_ on D read
+the (approximate) length of the arc on C.
+
+
+ EX.—_r_ = 24; _n_ = 30; find _l_.
+
+ Set 24 on C to 57·3 on D, and over 30 on D read 12·56 = _l_ on C.
+
+
+Given the diameter _d_ of a circle in _inches_, to find the
+circumference _c_ in _feet_.
+
+Set 191 on C to 50 on D, and under any diameter in inches on C read
+circumference _c_, in feet on D.
+
+
+ EX.—Find the circumference in feet of a pulley 17 in. in diameter. Set
+ 191 on C to 50 on D, and under 17 on C read 4·45 ft. on D.
+
+
+Given the diameter of a circle, to find its area.
+
+Set 0·7854 on B to 10 (centre index) on A and over any diameter on D
+read area on B.
+
+When the rule has a special graduation line = 0·7854, on the right-hand
+scale of B, set this line to the R.H. index of A and read off as above.
+If only π is marked, set this special graduation on B to 4 on A.
+
+On the C and D scales of some rules a gauge point marked _c_ will be
+found indicating √((4)/(π)) = 1·1286. In this case, therefore, set 1 on
+C to gauge point _c_ on D, and read area on A as above. If the gauge
+point _c_′ is used, divide the result by 10. Or set _c_ on C, to
+diameter on D, and over index of B read area on A. Cursors are supplied,
+having _two_ lines ruled on the glass, the interval between them being
+equal to (4)/(π) = 1·273 on the A scale. In this case, if the right hand
+of the two cursor lines be set to the diameter on D, the _area_ will be
+read on A under the _left_-hand cursor line. For diameters less than
+1·11 it is necessary to set the middle index of B to the L.H. index of
+A, reading the areas on the L.H. B scale. The confusion which in general
+work is sometimes caused by the use of two cursor lines might be
+obviated by making the left-hand line in two short lengths, each only
+just covering the scales.
+
+Given diameter of circle _d_ in _inches_, to find area _a_ in square
+_feet_.
+
+Set 6 on B to 11 on A, and over diameter in inches on D read area in
+square feet on B.
+
+To find the surface in square feet of boiler flues, condenser tubes,
+heating pipes, etc., having given the diameter in inches and length in
+feet.
+
+Find the circumference in feet as above and multiply by the length in
+feet.
+
+
+ EX.—Find the heating surface afforded by 160 locomotive boiler tubes
+ 1¾in. in diameter and 12 ft. long.
+
+ Set 191 on C to 50 on D; bring cursor 1·75 on C, L.H. index of C to
+ cursor; cursor to 12 on C; 1 on C to cursor; and under 160 on C read
+ 880 sq. ft. of heating surface on D.
+
+
+If the dimensions are in the same denomination and the rule has a gauge
+point M at 31·83 (= (100)/(π)), set this mark on B to diameter of
+cylinder on A, and read cylindrical surface on A over length on B.
+
+To find the side _s_ of a square, equal in area to a given rectangle of
+length _l_ and breadth _b_.
+
+Set R.H. or L.H. index of B to _l_ on A, and under _b_ on B read _s_ on
+D.
+
+
+ EX.—Find the side of a square equal in area to a rectangle in which
+ _l_ = 31 ft. and _b_ = 5 ft.
+
+ Set the (R.H.) index of B to 31 on A, and under 5 on B read 12·45 ft.
+ on D.
+
+
+To find various lengths _l_ and breadths _b_ of a rectangle, to give a
+constant area _a_.
+
+Invert the slide and set the index of Ɔ to the given area on D. Then
+opposite any length _l_ on Ɔ find the corresponding breadth _b_ on D.
+
+
+ EX.—Find the corresponding breadths of rectangular sheets, 16, 18, 24,
+ 36, and 60 ft. long, to give a constant area of 72 sq. ft.
+
+ Set the R.H. index of Ɔ to 72 on D, and opposite 16, 18, 24, 36, and
+ 60 on Ɔ read 4·5, 4, 3, 2, and 1·2 ft., the corresponding breadths on
+ D.
+
+
+To find the contents in cubic feet of a cylinder of diameter _d_ in
+inches and length _l_ in feet.
+
+Find area in feet as before, and multiply by the length.
+
+If dimensions are all in inches or feet, set the mark _c_ (= 1·128) on C
+to diameter on D and over length on B, read cubic contents on A.
+
+To find the area of an ellipse.
+
+Set 205 on C to 161 on D; bring cursor to length of major axis on C, 1
+on C to cursor, and under length of minor axis on C read area on D.
+
+
+ EX.—Find the area of an ellipse the major and minor axes of which are
+ 16 in. and 12 in. in length respectively.
+
+ Set 205 on C to 161 on D; bring cursor to 16 on C, 1 on C to cursor,
+ and under 12 on C read 150·8 in. on D.
+
+
+To find the surface of spheres.
+
+Set 3·1416 on B to R.H. or L.H. index of A, and over diameter on D read
+by the aid of the cursor, the convex surface on B.
+
+To find the cubic contents of spheres.
+
+Set 1·91 on B to diameter on A, and over diameter on C read cubic
+contents on A.
+
+
+ WEIGHTS OF METALS.
+
+To find the weight in lb. per lineal foot of square bars of metal.
+
+Set index of B to weight of 12 cubic inches of the metal (_i.e._, one
+lineal foot, 1 square inch in section) on A, and over the side of the
+square in inches on C read weight in lb. on A.
+
+
+ EX.—Find the weight per foot length of 4½in. square wrought-iron bars.
+
+ Set middle index of B to 3·33 on A, and over 4½ on C read 67·5 lb. on
+ A.
+
+
+(N.B.—For other metals use the corresponding constant in column (2),
+below).
+
+To find the weight in lb. per lineal foot of round bars.
+
+Set R.H. or L.H. index of B to weight of 12 cylindrical inches of the
+metal on A (column (4), below), and opposite the diameter of the bar in
+inches on C, read weight in lb. per lineal foot on A.
+
+
+ EX.—Find the weight of 1 lineal foot of 2 in. round cast steel.
+
+ Set L.H. index of B to 2·68 on A, and over 2 on C read 10·7 lb. on A.
+
+
+To find the weight of flat bars in lb. per lineal foot.
+
+Set the breadth in inches on C to (1)/(weight of 12 cub. in.) of the
+metal (column (3), below) on D, and above the thickness on D read weight
+in lb. per lineal foot on C.
+
+
+ EX.—Find the weight per lineal foot of bar steel, 4½in. wide and ⅝in.
+ thick.
+
+ Set 4·5 on C to 0·294 on D, and over 0·625 on D read 9·56 lb. per
+ lineal foot on C.
+
+
+To find the weight per square foot of sheet metal, set the weight per
+cubic foot of the metal (col. 1) on C to 12 on D, and
+
+ ────────────┬──────────┬──────────┬──────────┬───────────
+ │ (1) │(2) │ (3) │ (4)
+ │Weight in │Weight of │ (1)/(Wt. │ Weight of
+ Metals. │ lb. per │12 cubic │of 12 cub.│ 12
+ │cubic ft. │in. │ in.) │cylindrical
+ │ │ │ │ in.
+ ────────────┼──────────┼──────────┼──────────┼───────────
+ Wrought iron│480 │3·33 │0·300 │2·62
+ Cast iron │450 │3·125 │0·320 │2·45
+ Cast steel │490 │3·40 │0·294 │2·68
+ Copper │550 │3·82 │0·262 │3·00
+ Aluminium │168 │1·166 │0·085 │0·915
+ Brass │520 │3·61 │0·277 │2·83
+ Lead │710 │4·93 │0·203 │3·87
+ Tin │462 │3·21 │0·312 │2·52
+ Zinc (cast) │430 │2·98 │0·335 │2·34
+ „ (sheet) │450 │3·125 │0·320 │2·45
+ ────────────┴──────────┴──────────┴──────────┴───────────
+
+above the thickness of the plate in inches on D read weight in lb. per
+square foot on C.
+
+
+ EX.—Find the weight in lb. per square foot of aluminium sheet ⅜in.
+ thick.
+
+ Set 168 on C to 12 on D, and over 0·375 on D read 5·25 lb. on C.
+
+
+To find the weight of pipes in lb. per lineal foot.
+
+Set mean diameter of the pipe in inches (_i.e._, internal diameter
+_plus_ the thickness, or external diameter _minus_ the thickness) on C
+to the constant given below on D, and over the thickness on D read
+weight in lb. per lineal foot on C.
+
+ ┌────────────┬─────────────────────┬─────────────────────┐
+ │ Metals. │ Constant for Pipes. │Constant for Spheres.│
+ ├────────────┼─────────────────────┼─────────────────────┤
+ │Wrought iron│ 0·0955 │ 6·87 │
+ │Cast iron │ 0·1020 │ 7·35 │
+ │Steel │ 0·0936 │ 6·73 │
+ │Brass │ 0·0882 │ 6·35 │
+ │Copper │ 0·0834 │ 6·00 │
+ │Lead │ 0·0646 │ 4·65 │
+ └────────────┴─────────────────────┴─────────────────────┘
+
+
+ EX.—Find the weight per foot of cast-iron piping 4 in. internal
+ diameter and ½in. thick.
+
+ Set 4·5 on C to 0·102 on D, and over 0·5 on D read 22·1 lb. on C, the
+ required weight.
+
+
+To find the weight in lb. of spheres or balls, given the diameter in
+inches. (W = 0·5236_d_^3 × wt. of 1 cub. in. of material).
+
+Set the constant for spheres (given above) on B to diameter in inches on
+A, and over diameter on C read weight in lb. on A.
+
+
+ EX.—Find the weight of a cast-iron ball 7½in. in diameter.
+
+ Set 7·35 on B to 7·5 on A, and over 7·5 on C read 57·7 lb. on A.
+
+
+To find diameter in inches of a sphere of given weight.
+
+Set the cursor to the given weight in lb. on A, and move the slide until
+the same number is found on C under the cursor that is simultaneously
+found on A over the constant for the sphere on B.
+
+
+ EX.—Find diameter in inches of a sphere of cast-iron to weigh 7½lb.
+
+ Setting the cursor to 7·5 on A, and moving the slide, it is found that
+ when 3·8 on C falls under the cursor, 3·8 on A is simultaneously found
+ over 7·35 on B. The required diameter is therefore 3·8 in.
+
+
+The rules for cubes and cube roots (page 40) should be kept in view in
+solving the last two examples.
+
+
+ FALLING BODIES.
+
+To find velocity in feet per second of a falling body, given the time of
+fall in seconds.
+
+Set index on C to time of fall on D, and under 32·2 on C read velocity
+in feet per second on D.
+
+To find velocity in feet per second, given distance fallen through in
+feet.
+
+Set 1 on C to distance fallen through on A, and under 64·4 on B read
+velocity in feet per second on D.
+
+
+ EX.—Find velocity acquired by falling through 14 ft.
+
+ Set (R.H.) index of C to 14 on A, and under 64·4 on B read 30 ft. per
+ second on D.
+
+
+To find distance fallen through in feet in a given time.
+
+Set index of C to time in seconds on D, and over 16·1 on B read distance
+fallen through in feet on A.
+
+
+ CENTRIFUGAL FORCE.
+
+To find the centrifugal force of a revolving mass in lb.
+
+Set 2940 on B to revolutions per minute on D; bring cursor to weight in
+lb. on B; index of B to cursor, and over radius in feet on B read
+centrifugal force in lb. on A.
+
+To find the centrifugal stress in lb. per square inch, in rims of
+revolving wheels of cast iron.
+
+Set 61·3 on C to the mean diameter of the wheel in feet on D, and over
+revolutions per minute on C read stress per square inch on A.
+
+
+ EX.—Find the stress per square inch in a cast-iron fly-wheel rim 8 ft.
+ in diameter and running at 120 revolutions per minute.
+
+ Set 61·3 on C to 8 on D, and over 120 on C read 245 lb. per square
+ inch on A.
+
+
+ THE STEAM ENGINE.
+
+Given the stroke and number of revolutions per minute, to find the
+piston speed.
+
+Set stroke in inches on C to 6 on D, and over number of revolutions on D
+read piston speed in feet per minute on C.
+
+To find cubic feet of steam in a cylinder at cut-off, given diameter of
+cylinder and period of admission in inches.
+
+Set 2200 on B to cylinder diameter on D, and over period of admission on
+B read cubic feet of steam on A.
+
+
+ EX.—Cylinder diameter 26 in., stroke 40 in., cut-off at ⅝ of stroke.
+ Find cubic feet of steam used (theoretically) per stroke.
+
+ Set 2200 on B to 26 on D, and over 40 × ⅝ or 25 in. on B, read 7·68
+ cub. ft. on A, as the number of cubic feet of steam used per stroke.
+
+
+Given the diameter of a cylinder in inches, and the pressure in lb. per
+square inch, to find the load on the piston in tons.
+
+Set pressure in lb. per square inch on B to 2852 on A, and over cylinder
+diameter in inches on D read load on piston in tons on B.
+
+
+ EX.—Steam pressure 180 lb. per square inch; cylinder diameter, 42 in.
+ Find load in tons on piston.
+
+ Set 180 on B to 2852 on A, and over 42 on D read 111 tons, the gross
+ load, on B.
+
+
+Given admission period and absolute initial pressure of steam in a
+cylinder, to find the pressure at various points in the expansion period
+(isothermal expansion).
+
+Invert the slide and set the admission period, in inches, on Ɔ to the
+initial pressure on D; then under any point in the expansion stroke on Ɔ
+find the corresponding pressure on D.
+
+
+ EX.—Admission period 12 in., stroke 42 in., initial pressure 80 lb.
+ per square inch. Find pressure at successive fifths of the expansion
+ period.
+
+ Set 12 on Ɔ to 80 on D, and opposite 18, 24, 30, 36 and 42 in. of the
+ whole stroke on Ɔ find the corresponding pressures on D:—53·3, 40, 32,
+ 26·6 and 22·8 lb. per square inch.
+
+
+To find the mean pressure constant for isothermally expanding steam,
+given the cut-off as a fraction of the stroke.
+
+Find the logarithm of the ratio of the expansion _r_, by the method
+previously explained (page 46). Prefix the characteristic and to the
+number thus obtained, on D, set 1 on C. Then under 2·302 on C read _x_
+on D. To _x_ + 1 on D set _r_ on C, and under index of C read mean
+pressure constant on D. The latter, multiplied by the initial pressure,
+gives the mean forward pressure throughout the stroke. (N.B.—Common log.
+× 2·302 = hyperbolic log.)
+
+
+ EX.—Find the mean pressure constant for a cut-off of ¼th, or a ratio
+ of expansion of 4.
+
+ Set (L.H.) index of C to 4 on D, and on the reverse side of the slide
+ read 0·602 on the logarithmic scale. The characteristic = 0; hence to
+ 0·602 on D set (R.H.) index of C, and under 2·302 on C read 1·384 on
+ D. Add 1, and to 2·384 thus obtained on D set _r_ (= 4) on C, and
+ under 1 on C read 0·596, the mean pressure constant required.
+
+
+Mean pressure constants for the most usual degrees of cut-off are given
+below:—
+
+ Cut-off in fractions of stroke Mean pressure constant
+ ¾ 0·968
+ ⁷⁄₁₀ 0·952
+ ⅔ 0·934
+ ⅝ 0·919
+ ⅗ 0·913
+ ½ 0·846
+ ⅖ 0·766
+ ⅜ 0·750
+ ⅓ 0·699
+ ³⁄₁₀ 0·664
+ ¼ 0·596
+ ⅕ 0·522
+ ⅙ 0·465
+ ⅐ 0·421
+ ⅛ 0·385
+ ⅑ 0·355
+ ⅒ 0·330
+ ¹⁄₁₁ 0·309
+ ¹⁄₁₂ 0·290
+ ¹⁄₁₃ 0·274
+ ¹⁄₁₄ 0·260
+ ¹⁄₁₅ 0·247
+ ¹⁄₁₆ 0·236
+
+To find mean pressure:—Set 1 on C to constant on D, and under initial
+pressure on C read mean pressure on D.
+
+Given the absolute initial pressure, length of stroke, and admission
+period, to find the absolute pressure at any point in the expansion
+period, it being assumed that the steam expands adiabatically. (P_{2} =
+(P_{1})/(R^{¹⁰⁄₉}) in which P_{1} = initial pressure and P_{2} the
+pressure corresponding to a ratio of expansion R.)
+
+Set L.H. index of C to ratio of expansion on D, and read on the back of
+the slide the decimal of the logarithm. Add the characteristic, and to
+the number thus obtained on D set 9 on C, and read off the value found
+on D under the index of C. Set this number on the logarithmic scale to
+the index mark, in the opening on the back of the rule, and under L.H.
+index of C read the value of R^{¹⁰⁄₉} on D. The initial pressure divided
+by this value gives the corresponding pressure due to the expansion.
+
+
+ EX.—Absolute initial pressure 120 lb. per square inch; stroke, 4 ft.;
+ cut-off ¼. Find the respective pressures when ½ and ¾ths of the stroke
+ have been completed.
+
+ In the first case R = 2. Therefore setting the L.H. index of C to 2 on
+ D, we find the decimal of the logarithm on the back of the slide to be
+ 0·301. The characteristic is 0, so placing 9 on C to 0·301 on D, we
+ read 0·334 as the value under the R.H. index of C. (N.B.—In locating
+ the decimal point it is to be observed that the log. of R has been
+ multiplied by 10, in accordance with the terms of the above
+ expression.) Setting this number on the logarithmic scale to the back
+ index, the value of R^{¹⁰⁄₉} is found on D, under the L.H. index of C,
+ to be 2·16. Setting 120 on C to this value, it is found that the
+ pressure at ½ stroke, read on C over the R.H. index of D, is 55·5 lb.
+ per square inch. In a similar manner, the pressure when ¾ths of the
+ stroke is completed is found to be 35·4 lb. per square inch.
+
+
+For other conditions of expanding steam, or for gas or air, the method
+of procedure is similar to the above.
+
+To find the horse-power of an engine, having given the mean _effective_
+pressure, the cylinder diameter, stroke, and number of revolutions per
+minute.
+
+To cylinder diameter on D set 145 on C; bring cursor to stroke in feet
+on B, 1 on B to cursor, cursor to number of revolutions on B, 1 on B to
+cursor, and over mean effective pressure on B find horse-power on A.
+
+(N.B.—If stroke is in inches, use 502 in place of 145 given above.)
+
+
+ EX.—Find the indicated horse-power, given cylinder diameter 27 in.,
+ mean effective pressure 38 lb. per square inch, stroke 32 in.,
+ revolutions 57 per minute.
+
+ Set 502 on C to 27 on D, bring cursor to 32 on B, 1 on B to cursor,
+ cursor to 57 on B, 1 on B to cursor, and over 38 on B read 200 I.H.P.
+ on A.
+
+
+To determine the horse-power of a compound engine, invert the slide and
+set the diameter of the _high_-pressure cylinder on Ɔ to the cut-off in
+that cylinder on A. Use the number then found on A over the diameter of
+the _low_-pressure cylinder on Ɔ as the cut-off in that cylinder,
+working with the same pressure and piston speed, and calculate the
+horse-power as for a single cylinder.
+
+To find the cylinder ratio in compound engines, invert the slide and set
+index of Ɔ to diameter of the low-pressure cylinder on D. Then over the
+diameter of the high-pressure cylinder on C, read cylinder ratio on A.
+
+
+ EX.—Diameter of high-pressure cylinder 7¾in., low-pressure 15 in. Find
+ cylinder ratio.
+
+ Set index on Ɔ to 15 on D, and over 7·75 on Ɔ read 3·75, the required
+ ratio, on A.
+
+
+The cylinder ratios of triple or quadruple-expansion engines may be
+similarly determined.
+
+
+ EX.—In a quadruple-expansion engine, the cylinders are 18, 26, 37, and
+ 54 inches in diameter. Find the respective ratios of the high, first
+ intermediate, and second intermediate cylinders to the low-pressure.
+
+ Set (R.H.) index of Ɔ to 54 on D, and over 18, 26, and 37 on Ɔ read 9,
+ 4·31, and 2·13, the required ratios, on A.
+
+
+Given the mean effective pressures in lb. per square inch in each of the
+three cylinders of a triple-expansion engine, the I.H.P. to be developed
+in each cylinder, and the piston speed, to find the respective cylinder
+diameters.
+
+Set 42,000 on B to piston speed on A; bring cursor to mean effective
+pressure in low-pressure cylinder on B, index of B to cursor, and under
+I.H.P. on A read low-pressure cylinder diameter on C. To find the
+diameters of the high-pressure and intermediate-pressure cylinders,
+invert the slide and place the mean pressure in the low-pressure
+cylinder on ᗺ to the diameter of that cylinder on D. Then under the
+respective mean pressures on ᗺ read corresponding cylinder diameters on
+D.
+
+
+ EX.—The mean effective pressures in the cylinders of a
+ triple-expansion engine are:—L.P., 10·32; I.M.P., 27·5; and H.P., 77·5
+ lb. per square inch. The piston speed is 650 ft. per minute, and the
+ I.H.P. developed in each cylinder, 750. Find the cylinder diameters.
+
+ Set 42,000 on B to 650 on A, and bring cursor to 10·32 on B. Bring
+ index of B to cursor, and under 750 on A read 68·5 in. on C, the L.P.
+ cylinder diameter. Invert the slide, and placing 10·32 on ᗺ to 68·5 on
+ D, read, under 27·5 on ᗺ, the I.M.P. cylinder diameter = 42 in., on D;
+ also under 77·5 on ᗺ read the H.P. cylinder diameter = 25 in., on D.
+
+
+To compute brake or dynamometrical horse-power.
+
+Set 525 on C to the total weight in lb. acting at the end of the lever
+(or pull of spring balance in lb.) on D; set cursor to length of lever
+in feet on C, bring 1 on C to cursor, and under number of revolutions
+per minute on C find brake horse-power on D.
+
+Given cylinder diameter and piston speed in feet per minute, to find
+diameter of steam pipe, assuming the maximum velocity of the steam to be
+6000 ft. per minute.
+
+Set 6000 on B to cylinder diameter on D, and under piston speed on B
+read steam pipe diameter on D.
+
+Given the number of revolutions per minute of a Watt governor, to find
+the vertical height in inches, from the plane of revolution of the balls
+to the point of suspension.
+
+Set revolutions per minute on C to 35,200 on A, and over index of B read
+height on A.
+
+Given the weight in lb. of the rim of a cast-iron fly-wheel, to find the
+sectional area of the rim in square inches.
+
+Set the mean diameter of the wheel in feet on C to 0·102 on D, and under
+weight of rim on C find area on D.
+
+Given the consumption of coal in tons per week of 56 hours, and the
+I.H.P., to find the coal consumed per I.H.P. per hour.
+
+Set I.H.P. on C to 40 on D, and under weekly consumption on C read lb.
+of coal per I.H.P., per hour on D.
+
+
+ EX.—Find coal used per I.H.P. per hour, when 24 tons is the weekly
+ consumption for 300 I.H.P.
+
+ Set 300 on C to 40 on D, and under 24 on C read 3·2 lb. per I.H.P. per
+ hour on D.
+
+
+(N.B.—For any other number of working hours per week divide 2240 by the
+number of working hours, and use the quotient in place of 40 as above.)
+
+To find the tractive force of a locomotive.
+
+Set diameter of driving wheel in inches on B to diameter of cylinder in
+inches on D, and over the stroke in inches on B read on A, tractive
+force in lb. for each lb. of effective pressure on the piston.
+
+
+ STEAM BOILERS.
+
+To find the bursting pressure of a cylindrical boiler shell, having
+given the diameter of shell and the thickness and ultimate strength of
+the material.
+
+Set the diameter of the shell in inches on C to twice the thickness of
+the plate on D, and under strength of material per square inch on C read
+bursting pressure in lb. per square inch on D.
+
+
+ EX.—Find the bursting pressure of a cylindrical boiler shell 7 ft. 6
+ in. in diameter, with plates ½in. thick, assuming an ultimate strength
+ of 50,000 lb. per square inch.
+
+ Set 90 on C to 1·0 on D, and under 50,000 on C find 555 lb. on D.
+
+
+To find working pressure for Fox’s corrugated furnaces by Board of Trade
+rule.
+
+Set the least outside diameter in inches on C to 14,000 on D, and under
+thickness in inches on C read working pressure on D in lb. per square
+inch.
+
+To find diameter _d_ in inches, of round steel for safety valve springs
+by Board of Trade rule.
+
+Set 8000 on C to load on spring in lb. on D, and under the mean diameter
+of the spring in inches on C read _d_^3 on D. Then extract the cube root
+as per rule.
+
+
+ SPEED RATIOS OF PULLEYS, ETC.
+
+Given the diameter of a pulley and its number of revolutions per minute,
+to find the circumferential velocity of the pulley or the speed of
+ropes, belts, etc., driven thereby.
+
+Set diameter of pulley in inches on C to 3·82 on D, and over revolutions
+per minute on D read speed in feet per minute on C.
+
+
+ EX.—Find the speed of a belt driven by a pulley 53 in. in diameter and
+ running at 180 revolutions per minute.
+
+ Set 53 on C to 3·82 on D, and over 180 on D read 2500 ft. per minute
+ on C.
+
+ EX.—Find the speed of the pitch line of a spur wheel 3 ft. 6 in. in
+ diameter running at 60 revolutions per minute.
+
+ Set 42 in. on C to 3·82 on D, and over 60 on D read 660 ft. per minute
+ on C.
+
+
+Given diameter and number of revolutions per minute of a driving pulley,
+and the diameter of the driven pulley, to find the number of revolutions
+of the latter.
+
+Invert the slide and set diameter of driving pulley on Ɔ to given number
+of its revolutions on D; then opposite diameter of any driven pulley on
+Ɔ read its number of revolutions on D.
+
+
+ EX.—Diameter of driving pulley 10 ft.; revolutions per minute 55;
+ diameter of driven pulley 2 ft. 9 in. Find number of revolutions per
+ minute of latter.
+
+ Set 10 on Ɔ to 55 on D, and opposite 2·75 on Ɔ read 200 revolutions on
+ D.
+
+
+ BELTS AND ROPES.
+
+To find the ratio of tensions in the two sides of a belt, given the
+coefficient of friction between belt and pulley μ and the number of
+degrees θ in the arc of contact (log. R = (μθ)/(132)).
+
+Set 132 on C to the coefficient of friction on D, and read off the value
+found on D under the number of degrees in the arc of contact on C. Place
+this value on the scale of equal parts on the back of the slide, to the
+index mark in the aperture, and read the required ratio on D under the
+L.H. index of C.
+
+
+ EX.—Find the tension ratio in a belt, assuming a coefficient of
+ friction of 0·3 and an arc of contact of 120 degrees.
+
+ Set 132 on C to 0·3 on D, and under 120 on C read 0·273. Place this on
+ the scale to the index on the back of the rule, and under the L.H.
+ index C read 1·875 on D, the required ratio.
+
+
+Given belt velocity and horse-power to be transmitted, to find the
+requisite width of belt, taking the effective tension at 50 lb. per inch
+of width.
+
+Set 660 on C to velocity in feet per minute on D, and opposite
+horse-power on D find width of belt in inches on C.
+
+Given velocity and width of belt, to find horse-power transmitted.
+
+Set 660 on C to velocity on D, and under width on C find horse-power
+transmitted on D.
+
+(N.B.—For any other effective tension, instead of 660 use as a gauge
+point:—33,000 ÷ tension.)
+
+Given speed and diameter of a cotton driving rope, to find power
+transmitted, disregarding centrifugal action, and assuming an effective
+working tension of 200 lb. per square inch of rope.
+
+Set 210 on B to 1·75 on D, and over speed in feet per minute on B read
+horse-power on A.
+
+
+ EX.—Find the power transmitted by a 1¾in. rope running at 4000 ft. per
+ minute.
+
+ Set 210 on B to 1·75 on D, and over 4000 on B read 58·3 horse-power
+ on A.
+
+
+Find the “centrifugal tension” in the previous example, taking the
+weight per foot of the rope as = 0·27_d_^2.
+
+Set 655 on C to the diameter, 1·75 in., on D, and over the speed, 4000
+ft. on C, read centrifugal tension = 114 lb. on A.
+
+
+ SPUR WHEELS.
+
+Given diameter and pitch of a spur wheel, to find number of teeth.
+
+Set pitch on C to π (3·1416) on D, and under any diameter on C read
+number of teeth on D.
+
+Given diameter and number of teeth in a spur wheel, to find the pitch.
+
+Set diameter on C to number of teeth on D, and read pitch on C opposite
+3·1416 on D.
+
+Given the distance between the centres of a pair of spur wheels and the
+number of revolutions of each, to determine their diameters.
+
+To twice the distance between the centres on D, set the sum of the
+number of revolutions on C, and under the revolutions of each wheel on C
+find the respective wheel diameters on D.
+
+
+ EX.—The distance between the centres of two spur wheels is 37·5 in.,
+ and they are required to make 21 and 24 revolutions in the same time.
+ Find their respective diameters.
+
+ Set 21 + 24 = 45 on C to 75 (or 37·5 × 2) on D, and under 21 and 24
+ on C find 35 and 40 in. on D as the respective diameters.
+
+
+To find the power transmitted by toothed wheels, given the pitch
+diameter _d_ in inches, the number of revolutions per minute _n_, and
+the pitch _p_ in inches, by the rule, H.P. = (_n_ _d_ _p_^2)/(400).
+
+Set 400 on B to pitch in inches on D; set cursor to d on B, 1 on B to
+cursor, and over any number of revolutions n on B read power transmitted
+on A.
+
+
+ EX.—Find the horse-power capable of being transmitted by a spur wheel
+ 7 ft. in diameter, 3 in. pitch, and running at 90 revolutions per
+ minute.
+
+ Set 400 on B to 3 on D; bring cursor to 84 in. on B, 1 on B to cursor,
+ and over 90 revolutions on B read 170, the horse-power transmitted, on
+ A.
+
+
+ SCREW-CUTTING.
+
+Given the number of threads per inch in the guide screw, to find the
+wheels to cut a screw of given pitch.
+
+Set threads per inch in guide screw on C, to the number of threads per
+inch to be cut on D. Then opposite any number of teeth in the wheel on
+the mandrel on C, is the number of teeth in the wheel to be placed on
+the guide screw on D.
+
+
+ STRENGTH OF SHAFTING.
+
+Given the diameter _d_ of a steel shaft, and the number of revolutions
+per minute _n_, to find the horse-power from:—
+
+H.P. = _d_^3 × _n_ × 0·02.
+
+Set 1 on C to _d_ on D, and bring cursor to _d_ on B. Bring 50 on B to
+cursor, and over number of revolutions on B read H.P. on A.
+
+
+ EX.—Find horse-power transmitted by a 3 in. steel shaft at 110
+ revolutions per minute.
+
+ Set 1 on C to 3 on D, and bring cursor to 3 on B. Bring 50 on B to
+ cursor, and over 110 on B read 59·4 horse-power on A.
+
+
+Given the horse-power to be transmitted and the number of revolutions of
+a steel shaft, to find the diameter.
+
+Set revolutions on B to horse-power on A, and bring cursor to 50 on B.
+Then move the slide until the same number is found on B under the cursor
+that is simultaneously found on D under the index of C. This number is
+the diameter required.
+
+To find the deflection _k_ in inches, of a round steel shaft of diameter
+_d_, under a uniformly distributed load in lb. _w_, and supported by
+bearings, the centres of which are _l_ feet apart (_k_ = (_w_
+_l_^3)/(78,000_d_^4)).
+
+Modifying the form of this expression slightly, we proceed as
+follows:—Set _d_ on C to _l_ on D, and bring the cursor to the same
+number on B that is found on D under the index of C. Bring _d_ on B to
+cursor, cursor to _w_ on B, 78,800 on B to cursor, and read deflection
+on A over index of B.
+
+
+ EX.—Find the deflection in inches of a round steel shaft 3½in.
+ diameter, carrying a uniformly distributed load of 3200 lb., the
+ distance apart of the centres of support being 9 ft.
+
+ Set 3·5 on C to 9 on D, and read 2·57 on D, under the L.H. index of
+ C. Set cursor to 2·57 on B, and bring 3·5 on B to cursor, cursor to
+ 3200 on B, 78,000 on B to cursor, and over L.H. index of B read
+ 0·199 in., the required deflection on A.
+
+
+To find the diameter of a shaft subject to twisting only, given the
+twisting moment in inch-lb. and the allowable stress in lb. per square
+inch.
+
+Set the stress in lb. per square inch on B to the twisting moment in
+inch-lb. on A, and bring cursor to 5·1 on B. Then move the slide until
+the same number is found on B under the cursor that is simultaneously
+found on D under the index of C.
+
+
+ EX.—A steel shaft is subjected to a twisting moment of 2,700,000
+ inch-lb. Determine the diameter if the allowable stress is taken at
+ 9000 lb. per square inch.
+
+ Set 9000 on B to 2,700,000 on A, and bring the cursor to 5·1 on B.
+ Moving the slide to the left, it is found that when 11·51 on the
+ R.H. scale of B is under the cursor, the L.H. index of C is opposite
+ 11·51 on D. This, then, is the required diameter of the shaft.
+
+
+(N.B.—The rules for the scales to be used in finding the cube root (page
+42) must be carefully observed in working these examples.)
+
+
+ MOMENTS OF INERTIA.
+
+To find the moment of inertia of a square section about an axis formed
+by one of its diagonals (I = (_s_^4)/(12)).
+
+Set index of C to the length of the side of square _s_ on D; bring
+cursor to _s_ on C, 12 on B to cursor, and over index of B read moment
+of inertia on A.
+
+To find the moment of inertia of a rectangular section about an axis
+parallel to one side and perpendicular to the plane of bending.
+
+Set index of C to the height or depth _h_ of the section, and bring
+cursor to _h_ on B. Set 12 on B to cursor, and over breadth _b_ of the
+section on B read moment of inertia on A.
+
+
+ EX.—Find the moment of inertia of a rectangular section of which _h_ =
+ 14 in. and _b_ = 7 in.
+
+ Set index of C to 14 on D, and cursor to 14 on B. Bring 12 on B to
+ cursor, and over 7 on B read 1600 on A.
+
+
+ DISCHARGE FROM PUMPS, PIPES, ETC.
+
+To find the theoretical delivery of pumps, in gallons per stroke.
+
+Set 29·4 on B to the diameter of the plunger in inches on D, and over
+length of stroke in feet on B read theoretical delivery in gallons per
+stroke on A.
+
+(N.B.—A deduction of from 20 to 40 per cent. should be made to allow for
+slip.)
+
+To find loss of head of water in feet due to friction in pipes (Prony’s
+rule).
+
+Set diameter of pipe in feet on B to velocity of water in feet per
+second on D and bring cursor to 2·25 on B; bring 1 on B to cursor, and
+over length of pipe in miles on B, read loss of head of water in feet,
+on A.
+
+To find velocity in feet per second, of water in pipes (Blackwell’s
+rule).
+
+Set 2·3 on B to diameter of pipe in feet on A, and under inclination of
+pipe in feet per mile on B read velocity in feet per second on D.
+
+To find the discharge over weirs in cubic feet per minute and per foot
+of width. (Discharge = 214√(_h_^3))
+
+Set 0·00467 on C to the head in feet _h_ on D, and under _h_ on B read
+discharge on D.
+
+To find the theoretical velocity of water flowing under a given head in
+feet.
+
+Set index of B to head in feet on A, and under 64·4 on B read
+theoretical velocity in feet per second on D.
+
+
+ HORSE-POWER OF WATER WHEELS.
+
+To find the effective horse-power of a Poncelet water wheel.
+
+Set 880 on C to cubic feet of flow of water per minute on D, and under
+height of fall in feet on C, read effective horse-power on D.
+
+For breast water wheels use 960, and for overshot wheels 775, in place
+of 880 as above.
+
+
+ ELECTRICAL ENGINEERING.
+
+To find the resistance per mile, in ohms, of copper wire of high
+conductivity, at 60° F. the diameter being given in mils. (1 mil. =
+0·001 in.).
+
+Set diameter of wire in mils. on C to 54,900 on A, and over R.H. or L.H.
+index of B read resistance in ohms on A.
+
+
+ EX.—Find the resistance per mile of a copper wire 64 mils. in
+ diameter.
+
+ Set 64 on C to 54,900 on A, and over R.H. index of B read 13·4 ohms
+ on A.
+
+
+To find the weight of copper wire in lb. per mile.
+
+Set 7·91 on C to diameter of wire in mils. on D, and over index of B
+read weight per mile on A.
+
+Given electromotive force and current, to find electrical horse-power.
+
+Set 746 on C to electromotive force in volts on D, and under current in
+ampères on C read electrical horse-power on D.
+
+Given the resistance of a circuit in ohms and current in ampères, to
+find the energy absorbed in horse-power.
+
+Set 746 on B to current on D, and over resistance on B read energy
+absorbed in H.P. on A.
+
+
+ EX.—Find the H.P. expended in sending a current of 15 ampères through
+ a circuit of 220 ohms resistance.
+
+ Set 746 on B to 15 on D, and over 220 on B read 66·3 H.P. on A.
+
+
+ COMMERCIAL.
+
+To add on percentages.
+
+Set 100 on C to 100 + given percentage on D, and under original number
+on C read result on D.
+
+To deduct percentages.
+
+Set R.H. index of C to 100 − the given percentage on D, and under
+original number on C read result on D.
+
+
+ EX.—From £16 deduct 7½ per cent.
+
+ Set 10 on C to 92·5 on D and under 16 on C, read 14·8 = £14, 16s. on
+ D.
+
+
+To calculate simple interest.
+
+Set 1 on C to rate per cent. on D; bring cursor to period on C and 1 on
+C to cursor. Then opposite any sum on C find simple interest on D.
+
+For interest per annum.
+
+Set R.H. index on C to rate on D, and opposite principal on C read
+interest on D.
+
+
+ EX.—Find the amount with simple interest of £250 at 8 per cent., and
+ for a period of 1 year and 9 months.
+
+ Set 1 on C to 8 on D; bring cursor to 1·75 on C, and 1 on C to
+ cursor; then opposite 250 on C read £35, the interest, on D. Then
+ 250 + 35 = £285 = the amount.
+
+
+To calculate compound interest.
+
+Set the L.H. index of C to the amount of £1 at the given rate of
+interest on D, and find the logarithm of this by reading on the reverse
+side of the rule, as explained on page 46. Multiply the logarithm, so
+found, by the period, and set the result, on the scale of equal parts,
+to the index on the under-side of the rule; then opposite any sum on C
+read the amount (including compound interest) on D.
+
+
+ EX.—Find the amount of £500 at 5 per cent. for 6 years, with compound
+ interest.
+
+ Set L.H. index of C to £1·05 on D, and read at the index on the
+ scale of equal parts on the under-side of rule, 0·0212. Multiply by
+ 6, we obtain 0·1272, which, on the scale of equal parts, is placed
+ to the index in the notch at the end of the rule. Then opposite 500
+ on C read £670 on D, the amount required, including compound
+ interest.
+
+
+ MISCELLANEOUS CALCULATIONS.
+
+To calculate percentages of compositions.
+
+Set weight (or volume) of sample on C, to weight (or volume) of
+substance considered, on D; then under index of C read required
+percentage on D.
+
+
+ EX.—A sample of coal weighing 1·25 grms. contains 0·04425 grm. of ash.
+ Find the percentage of ash.
+
+ Set 1·25 on C to 0·04425 on D, and under index on C read 3·54, the
+ required percentage of ash on D.
+
+
+Given the steam pressure P and the diameter _d_ in millimetres, of the
+throat of an injector, to find the weight W, of water delivered in lb.
+per hour from W = (_d_^2√̅P)/(0·505).
+
+Set 0·505 on C to P on A; bring cursor to _d_ on C and index of C to
+cursor. Then under _d_ on C read delivery of water on D.
+
+To find the pressure of wind per square foot, due to a given velocity in
+miles per hour.
+
+Set 1 on B to 2 on A, and over the velocity in miles per hour on D read
+pressure in lb. per square foot on B.
+
+To find the kinetic energy of a moving body.
+
+Set 64·4 on B to velocity in feet per second on D, and over weight of
+body in lb. on B read kinetic energy or accumulated work in foot-lb. on
+A.
+
+
+
+
+ TRIGONOMETRICAL APPLICATIONS
+
+
+_Scales._—Not the least important feature of the modern slide rule is
+the provision of the special scales on the under-side of the slide, and
+by the use of which, in conjunction with the ordinary scales on the
+rule, a large variety of trigonometrical computations may be readily
+performed.
+
+Three scales will be found on the reverse or under-side of the slide of
+the ordinary Gravêt or Mannheim rule. One of these is the evenly-divided
+scale or scale of equal parts referred to in previous sections, and by
+which, as explained, the decimal parts or mantissæ of logarithms of
+numbers may be obtained. Usually this scale is the centre one of the
+three, but in some rules it will be found occupying the lowest position,
+in which case some little modification of the following instructions
+will be necessary. The requisite transpositions will, however, be
+evident when the purposes of the scales are understood. The upper of the
+three scales, usually distinguished by the letter S, is a scale giving
+the logarithms of the sines of angles, and is used to determine the
+natural sines of angles of from 35 minutes to 90 degrees. The notation
+of this scale will be evident on inspection. The main divisions 1, 2, 3,
+etc., represent the degrees of angles; but the values of the
+subdivisions differ according to their position on the scale. Thus, if
+any primary space is subdivided into 12 parts, each of the latter will
+be read as 5 minutes (5′), since 1° = 60′.
+
+_Sines of Angles._—To find the sine of an angle the slide is placed in
+the groove, with the under-side uppermost, and the end division lines or
+indices on the slide, coinciding with the right and left indices of the
+A scale. Then over the given angle on S is read the value of the sine of
+the angle on A. If the result is found on the left scale of A (1 to 10),
+the logarithmic characteristic is −2; if it is found on the right-hand
+side (10 to 100), it is −1. In other words, results on the right-hand
+scale are prefixed by the decimal point only, while those on the
+left-hand scale are to be preceded by a cypher also. Thus:—
+
+ Sine 2° 40′ = 0·0465; sine 15° 40′ = 0·270.
+
+Multiplication and division of the sines of angles are performed in the
+same manner as ordinary calculations, excepting that the slide has its
+under-face placed uppermost, as just explained. Thus to multiply sine
+15° 40′ by 15, the R.H. index of S is brought to 15 on A, and opposite
+15° 40′ on S is found 4·05 on A. Again, to divide 142 by sine 16° 30′,
+we place 16° 30′ on S to 142 on A, and over R.H. index of S read 500 on
+A.
+
+The rules for the number of integers in the results are thus determined:
+Let N be the number of integers in the multiplier M or in the dividend
+D. Then the number of integers P, in the product or Q, in the quotient
+are as follows:—
+
+ When the result is found to the right of M or D, │P = N − 2│Q = N
+ and in the same scale │ │
+ When the result is found to the right of M or D, │P = N − 1│Q = N + 1
+ and in the other scale │ │
+ When the result is found to the left of M or D, and│P = N − 1│Q = N + 1
+ in the other scale │ │
+ When the result is found to the left of M or D, and│P = N │Q = N + 2
+ in the same scale │ │
+
+If the division is of the form (20° 30′)/(50), the result cannot be read
+off directly on the face of the rule. Thus, if in the above example 20°
+30′ on S, is placed to agree with 50 on the right-hand scale of A, the
+result found on S under the R.H. index of A is 44° 30′. The required
+numerical value can then be found: (1) By placing the slide with all
+indices coincident when opposite 44° 30′ on S will be found 0·007 on A;
+or (2) In the ordinary form of rule, by reading off on the scale B
+opposite the index mark in the opening on the under-side of the rule.
+The above rules for the number of integers in the quotient do not apply
+in this case.
+
+If it is required to find the sine of an angle simply, this may be done
+with the slide in its ordinary position, with scale B under A. The given
+angle on scale S is then set to the index on the under-side of the rule,
+and the value of the sine is read off on B under the right index of A.
+
+Owing to the rapidly diminishing differences of the values of the sines
+as the upper end of the scale is approached, the sines of angles between
+60° and 90° cannot be accurately determined in the foregoing manner. It
+is therefore advisable to calculate the value of the sine by means of
+the formula:
+
+Sine θ = 1 − 2 sin^2 (90 − θ)/(2).
+
+To determine the value of sin^2 (90 − θ)/(2). With the slide in the
+normal position, set the value of (90 − θ)/(2). on S to the index on the
+under-side of the rule, and read off the value _x_ on B under the R.H.
+index of A. Without moving the slide find _x_ on A, and read under it on
+B the value required.
+
+
+ EX.—Find value of sine 79° 40′.
+
+ Sine 79° 40′ = 1 − 2sin^2 5° 10′.
+
+ But sine 5° 10′ = 0·0900, and under this value on A is 0·0081 on B.
+ Therefore sine 79° 40′ = 1 − 0·0162 = 0·9838.
+
+
+The sines of very small angles, being very nearly proportional to the
+angles themselves, are found by direct reading. To facilitate this, some
+rules are provided with two marks, one of which, a single accent (′),
+corresponds to the logarithm of (1)/(sine 1′) and is found at the number
+3438. The other mark—a double accent (″)—corresponds to the logarithm of
+(1)/(sine 1″) and is found at the number 206,265. In some rules these
+marks are found on either the A or the B scales; sometimes they are on
+both. In either case the angle on the one scale is placed so as to
+coincide with the significant mark on the other, and the result read off
+on the first-named scale opposite the index of the second.
+
+In sines of angles under 3″, the number of integers in the result is −5;
+while it is −4 for angles from 3″ to 21″; −3 from 21″ to 3′ 27″; and −2
+from 3′ 27″ to 34′ 23″.
+
+
+ EX.—Find sine 6′.
+
+ Placing the significant mark for minutes coincident with 6, the value
+ opposite the index is found to be 175, and by the rule above this is
+ to be read 0·00175. For angles in seconds the other significant mark
+ is used; while angles expressed in minutes and seconds are to be first
+ reduced to seconds. Thus, 3′ 10″ = 190″.
+
+
+_Tangents of Angles._—There remains to be considered the third scale
+found on the back of the slide, and usually distinguished from the
+others by being lettered T. In most of the more recent forms of rule
+this scale is placed near the lower edge of the slide, but in some
+arrangements it is found to be the centre scale of the three. Again, in
+some rules this scale is figured in the same direction as the scale of
+sines—viz., from left to right,—while in others the T scale is reversed.
+In both cases there is now usually an aperture formed in the back of the
+left extremity of the rule, with an index mark similar to that already
+referred to in connection with the scale of sines. Considering what has
+been referred to as the more general arrangement, the method of
+determining the tangents of angles may be thus explained:—
+
+The tangent scale will be found to commence, in some rules, at about
+34′, or, precisely, at the angle whose tangent is 0·01. More usually,
+however, the scale will be found to commence at about 5° 43′, or at the
+angle whose tangent is 0·1. The other extremity of the scale corresponds
+in all cases to 45°, or the angle whose tangent is 1. This explanation
+will suggest the method of using the scale, however it may be arranged.
+If the graduations commence with 34′, the T scale is to be used in
+conjunction with the right and left scales of A; while if they commence
+with 5° 43′ it is to be used in conjunction with the D scale.
+
+In the former case the slide is to be placed in the rule so that the T
+scale is adjacent to the A scales, and, with the right and left indices
+coinciding, when opposite any angle on T will be found its tangent on A.
+From what has been said above, it follows that the tangents read on the
+L.H. scale of A have values extending from 0·01 to 0·1; while those read
+on the R.H. scale of A have values from 0·1 to 1·0. Otherwise expressed,
+to the values of any tangent read on the L.H. scale of A a cypher is to
+be prefixed; while if found on the R.H. scale, it is read directly as a
+decimal.
+
+
+ EX.—Find tan. 3° 50′.
+
+ Placing the slide as directed, the reading on A opposite 3° 50′ on T
+ is found to be 67. As this is found on the L.H. scale of A, it is to
+ be read as 0·067.
+
+
+ EX.—Find tan. 17° 45′.
+
+ Here the reading on A opposite 17° 45′ on T is 32, and as it is found
+ on the R.H. scale of A it is read as 0·32.
+
+
+As in the case of the scale of sines, the tangents may be found without
+reversing the slide, when a fixed index is provided in the back of the
+rule for the T scale.
+
+We revert now to a consideration of those rules in which a single
+tangent scale is provided. It will be understood that in this case the
+slide is placed so that the scale T is adjacent to the D scale, and that
+when the indices of both are placed in agreement, the value of the
+tangent of any angle on T (from 5° 43′ to 45°) may be read off on D, the
+result so found being read as wholly decimal. Thus tan. 13° 20′ is read
+0·237.
+
+If a back index is provided, the slide is used in its normal position,
+when, setting the angle on the tangent scale to this index, the result
+can be read on C over the L.H. index of D.
+
+The tangents of angles above 45° are obtained by the formula: Tan. θ =
+(1)/(tan. (90 − θ)). For all angles from 45° to (90° − 5° 43′) we
+proceed as follows:—Place (90 − θ) on T to the R.H. index of D, and read
+tan. θ on D under the L.H. index of T. The first figure in the value
+thus obtained is to be read as an integer. Thus, to find tan. 71° 20′ we
+place 90° − 71° 20′ = 18° 40′ on T, to the R.H. index of D, and under
+the L.H. index of T read 2·96, the required tangent.
+
+The tangents of angles less than 40′ are sensibly proportional to the
+angles themselves, and as they may therefore be considered as sines,
+their value is determined by the aid of the single and double accent
+marks on the sine scale, as previously explained. The rules for the
+number of integers are the same as for the sines.
+
+Multiplication and division of tangents may be quite readily effected.
+
+
+ EX.—Tan. 21° 50′ × 15 = 6.
+
+ Set L.H. index of T to 15 on D, and under 21° 50′ on T read 6 on D.
+
+
+ EX.—Tan. 72° 40′ × 117 = 375.
+
+ Set (90° − 72° 40′) = 17° 20′ on T to 117 on D, and under R.H. index
+ of T read 375 on D.
+
+
+_Cosines of Angles._—The cosines of angles may be determined by placing
+the scale S with its indices coinciding with those of A, and when
+opposite (90 − θ) on S is read cos. θ on A. If the result is read on the
+L.H. scale of A, a cypher is to be prefixed to the value read; while if
+it is read on the R.H. scale of A, the value is read directly as a
+decimal. Thus, to determine cos. 86° 30′ we find opposite (90° − 86°
+30′) = 3° 30′ on S, 61° on A, and as this is on the L.H. scale the
+result is read 0·061. Again, to find cos. 59° 20′ we read opposite (90°
+− 59° 20′) or 30° 40′ on S, 51 on A, and as this is found on the R.H.
+scale of A, it is read 0·51.
+
+In finding the cosines of small angles it will be seen that direct
+reading on the rule becomes impossible for angles of less than 20°. It
+is advisable in such cases to adopt the method described for determining
+the _sines_ of the _large_ angles of which the complements are sought.
+
+_Cotangents of Angles._—From the methods of finding the tangents of
+angles previously described, it will be apparent that the cotangents of
+angles may also be obtained with equal facility. For angles between 5°
+45′ and 45°, the procedure is the same as that for finding tangents of
+angles greater than 45°. Thus, the angle on scale T is brought to the
+R.H. index of D, and the cotangent read off on D under the L.H. index of
+T. The first figure of the result so found is to be read as an integer.
+
+If the angle (θ) lies between 45° and 84° 15′, the slide is placed so
+that the indices of T coincide with those of D, and the result is then
+read off on D opposite (90 − θ) on T. In this case the value is wholly
+decimal.
+
+_Secants of Angles._—The secants of angles are readily found by bringing
+(90 − θ) on S to the R.H. index of A and reading the result on A over
+the L.H. index of S. If the value is found on the L.H. scale of A, the
+first figure is to be read as an integer; while if the result is read on
+the R.H. scale of A, the first _two_ figures are to be regarded as
+integers.
+
+_Cosecants of Angles._—The cosecants of angles are found by placing the
+angle on S to the R.H. index of A, and reading the value found on A over
+the L.H. index of S. If the result is read on the L.H. scale of A, the
+first figure is to be read as an integer; while if the result is found
+on the R.H. scale of A, the first _two_ figures are to be read as
+integers.
+
+It will be noted that some of the rules here given for determining the
+several trigonometrical functions of angles apply only to those forms of
+rules in which a single scale of tangents T is used, reading from left
+to right. For the other arrangements of the scale, previously referred
+to, some slight modification of the method of procedure in finding the
+tangents and cotangents of angles will be necessary; but as in each case
+the nature and extent of this modification is evident, no further
+directions are required.
+
+
+
+
+ THE SOLUTION OF RIGHT-ANGLED TRIANGLES.
+
+
+From the foregoing explanation of the manner of determining the
+trigonometrical functions of angles, the methods of solving right-angled
+triangles will be readily perceived, and only a few examples need
+therefore be given.
+
+Let _a_ and _b_ represent the sides and _c_ the hypothenuse of a
+right-angled triangle, and _a_° and _b_° the angles opposite to the
+sides. Then of the possible cases we will take
+
+(1.) Given _c_ and _a_°, to find _a_, _b_, and _b_°.
+
+The angle _b_° = 90 − _a_°, while _a_ = _c_ sin _a_° and _b_ = _c_ sin
+_b_°. To find _a_, therefore, the index of S is set to _c_ on A, and the
+value of _a_ read on A opposite _a_° on S. In the same manner the value
+of _b_ is obtained.
+
+
+ EX.—Given in a right-angled triangle _c_ = 9 ft. and _a_° = 30°. Find
+ _a_, _b_, and _b_°.
+
+ The angle _b_° = 90 − 30 = 60°. To find _a_, set R.H. index of S to 9
+ on A, and over 30° on S read _a_ = 4·5 ft. on A. Also, with the slide
+ in the same position, read _b_ = 7·8 ft. [7·794] on A over 60° on S.
+
+
+(2.) Given _a_ and _c_, to determine _a_°, _b_°, and _b_.
+
+In this case advantage is taken of the fact that in every triangle the
+sides are proportional to the sines of the opposite angles. Therefore,
+as in this case the hypothenuse c subtends a right angle, of which the
+sine = 1, the R.H. index (or 90°) on S is set to the length of _c_ on A,
+when under _a_ on A is found _a_° on S. Hence _b_° and _b_ may be
+determined.
+
+(3.) Given _a_ and _a_°, to find _b_, _c_, and _b_°.
+
+Here _b_° = (90 − _a_°), and the solution is similar to the foregoing.
+
+(4.) Given _a_ and _b_, to find _a_°, _b_°, and _c_.
+
+To find _a_°, we have tan. _a_° = _a_/_b_, which in the above example
+will be (4·5)/(7·8) = 0·577. Therefore, placing the slide so that the
+indices of T coincide with those of D, we read opposite 0·577 on D the
+value of _a_° = 30°. The hypothenuse _c_ is readily obtained from _c_ =
+_a_/(sin _a_°).
+
+
+
+
+ THE SOLUTION OF OBLIQUE-ANGLED TRIANGLES.
+
+
+Using the same letters as before to designate the three sides and the
+subtending angles of oblique-angled triangles, we have the following
+cases:—
+
+(1.) Given one side and two angles, as _a_, _a_°, and _b_°, to find _b_,
+_c_, and _c_°.
+
+In the first place, _c_° = 180° − (_a_° + _b_°); also we note that, as
+the sides are proportional to the sines of the opposite angles, _b_ =
+(_a_ sine _b_°)/(sine _a_°) and _c_ = (_a_ sine _c_°)/(sine _a_°).
+
+Taking as an example, _a_ = 45, _a_° = 57°, and _b_° = 63°, we have _c_°
+= 180 − (57 + 63) = 60°. To find _b_ and _c_, set _a_° on S to _a_ on A,
+and read off on A above 63° and 60° the values of _b_ (= 47·8) and _c_
+(= 46·4) respectively.
+
+(2.) Given _a_, _b_, and _a_°, to find _b_°, _c_°, and _c_.
+
+In this case the angle _a_° on S is placed under the length of side _a_
+on A and under _b_ on A is found the angle _b_° on S. The angle _c_° =
+180 − (_a_° + _b_°), whence the length _c_ can be read off on A over
+_c_° on S.
+
+(3.) Given the sides and the included angle, to find the other side and
+the remaining angles.
+
+If, for example, there are given _a_ = 65, _b_ = 42, and the included
+angle _c_° = 55°, we have (_a_ + _b_) ∶ (_a_ − _b_) = tan. (_a_° +
+_b_°)/(2) ∶ tan. (_a_° − _b_°)/(2). Then, since _a_° + _b_° = 180° − 55°
+= 125°, it follows that (_a_° + _b_°)/(2) = (125°)/(2) = 62° 30′.
+
+By the rule for tangents of angles greater than 45°, we find tan. 62°
+30′ = 1·92. Inserting in the above proportion the values thus found, we
+have 107 ∶ 23 = 1·92 ∶ tan. (_a_° − _b_°)/(2). From this it is found
+that the value of the tangent is 0·412, and placing the slide with all
+indices coinciding, it is seen that this value on D corresponds to an
+angle of 22° 25′. Therefore, since (_a_° + _b_°)/(2) = 62° 30′, and
+(_a_° − _b_°)/(2) = 22° 25′, it follows that _a_° = 84° 55′, and _b_° =
+40° 5′. Finally, to determine the side _c_, we have _c_ = (_a_ sin
+_c_°)/(sin _a_°) as before.
+
+
+ PRACTICAL TRIGONOMETRICAL APPLICATIONS.
+
+A few examples illustrative of the application of the methods of
+determining the functions of angles, etc., described in the preceding
+section, will now be given.
+
+To find the chord of an arc, having given the included angle and the
+radius.
+
+With the slide placed in the rule with the C and D scales outward, bring
+one-half of the given angle on S to the index mark in the back of the
+rule, and read the chord on B under twice the radius on A.
+
+
+ EX.—Required the chord of an arc of 15°, the radius being 23 in.
+
+ Set 7° 30′ on S to the index mark in the back of the rule, and under
+ 46 on A read 6 in., the required length of chord on B.
+
+
+To find the area of a triangle, given two sides and the included angle.
+
+Set the angle on S to the index mark on the back of the rule, and bring
+cursor to 2 on B. Then bring the length of one side on B to cursor,
+cursor to 1 on B, the length of the other side on B to cursor, and read
+area on B under index of A.
+
+
+ EX.—The sides of a triangle are 5 and 6 ft. in length respectively,
+ and they include an angle of 20°. Find the area.
+
+ Set 20 on S to index mark, bring cursor to 2 on B, 5 on B to cursor,
+ cursor to 1 on B, 6 on B to cursor, and under 1 on A read the area =
+ 5·13 sq. ft. on B.
+
+
+To find the number of degrees in a gradient, given the rise per cent.
+
+Place the slide with the indices of T coincident with those of D, and
+over the rate per cent. on D read number of degrees in the slope on T.
+
+As the arrangement of rule we have chiefly considered has only a single
+T scale, it will be seen that only solutions of the above problem
+involving slopes between 10 and 100 per cent. can be directly read off.
+For smaller angles, one of the formulæ for the determination of the
+tangents of submultiple angles must be used.
+
+In rules having a double T scale (which is used with the A scale) the
+value in degrees of any slope from 1 to 100 per cent. can be directly
+read off on A.
+
+To find the number of degrees, when the gradient is expressed as 1 in
+_x_.
+
+Place the index of T to _x_ on D, and over index of D read the required
+angle in degrees on T.
+
+
+ EX.—Find the number of degrees in a gradient of 1 in 3·8.
+
+ Set 1 on T to 3·8 on D, and over R.H. index of D read 14° 45′ on T.
+
+
+Given the lap, the lead and the travel of an engine slide valve, to find
+the angle of advance.
+
+Set (lap + lead) on B to half the travel of the valve on A, and read the
+angle of advance on S at the index mark on the back of the rule.
+
+
+ EX.—Valve travel 4½in., lap 1 in., lead ⁵⁄₁₆in. Find angle of advance.
+
+ Set 1⁵⁄₁₆ = 1·312 on B to 2·25 on A, and read 35° 40′ on S opposite
+ the index on the back of the rule.
+
+
+Given the angular advance θ, the lap and the travel of a slide valve, to
+find the cut-off in percentage of the stroke.
+
+Place the lap on B to half the travel of valve on A, and read on S the
+angle (the supplement of the _angle of the eccentric_) found opposite
+the index in the back of the rule. To this angle, add the angle of
+advance and deduct the sum from 180°, thus obtaining the _angle of the
+crank_ at the point of cut-off. To the cosine of the supplement of this
+angle, add 1 and multiply the result by 50, obtaining the percentage of
+stroke completed when cut-off occurs.
+
+
+ EX.—Given the angular advance = 35° 40′, the valve travel = 4½in., and
+ the lap = 1 in., find the angle of the crank at cut-off and the
+ admission period expressed as a percentage of the stroke.
+
+ Set 1 on B to 2·25 on A, and read off on S opposite the index, the
+ supplement of the angle of the eccentric = 26° 20′. Then 180° − (35°
+ 40′ + 26° 20′) = 118° = the crank angle at the point of cut-off.
+ Further, cos. 118° = cos. 62° = sin (90° − 62°) = sin 28°, and placing
+ 28° on S to the back index, the cosine, read on B under R.H. index of
+ A, is found to be 0·469. Adding 1 and placing the L.H. index of C to
+ the result, 1·469, on D, we read off under 50 on C, the required
+ period of admission = 73·4 per cent. on D.
+
+
+The trigonometrical scales are useful for evaluating certain formulæ.
+Thus in the following expressions, if we find the angle _a_ such that
+sin. _a_ = _k_, we can write:—
+
+ (_k_)/(√1 − _k^2_) = tan. _a_; (√1 − _k^2_)/(_k_) = cot. _a_; √(1 −
+ _k^2_) = cos. _a_; etc.
+
+In the first expression, take _k_ = 0·298. Place the slide with the sine
+scale outward and with its indices agreeing with the indices of the
+rule. Set the cursor to 0·298 on the (R.H.) scale of A, and read 17° 20′
+on the sine scale as the angle required. Then under 17° 20′ on the
+tangent scale, read 0·312 on D as the result.
+
+
+ SLIDE RULES WITH LOG.-LOG. SCALES.
+
+For occasional requirements, the method described on page 45 of
+determining powers and roots other than the square and cube, is quite
+satisfactory. When, however, a number of such calculations are to be
+made, the process may be simplified considerably by the use of what are
+known as _log.-log._, _logo-log._, or _logometric_ scales, in
+conjunction with the ordinary scales of the rule. The principle involved
+will be understood from a consideration of those rules for logarithmic
+computation (page 8) which refer to powers and roots. From these it is
+seen that while for the multiplication and division of numbers we _add_
+their logarithms, for involution and evolution we require to _multiply_
+or _divide_ the logarithms of the numbers by the exponent of the power
+or root as the case may be. Thus to find 3^{2.3}, we have (log. 3) × 2·3
+= log. _x_, and by the ordinary method described on page 45 we should
+determine log. 3 by the aid of the scale L on the back of the slide,
+multiply this by 2·3 by using the C and D scales in the usual manner,
+transfer the result to scale L, and read the value of _x_ on D under 1
+on C. By the simpler method, first proposed by Dr. P. M. Roget,[8] the
+multiplication of log. 3 by 2·3 is effected in the same way as with any
+two ordinary factors—_i.e._, by adding their logarithms and finding the
+number corresponding to the resulting logarithm. In this case we have
+log. (log. 3) + log. 2·3 = log. (log. _x_). The first of the three terms
+is obviously the _logarithm of the logarithm_ of 3, the second is the
+simple logarithm of 2·3, and the third the _logarithm of the logarithm
+of_ the answer. Hence, if we have a scale so graduated that the
+distances from the point of origin represent the logarithms of the
+logarithms (the log.-logs.) of the numbers engraved upon it, then by
+using this in conjunction with the ordinary scale of logarithms, we can
+effect the required multiplication in a manner which is both expeditious
+and convenient. Slightly varying arrangements of the log.-log. scale,
+sometimes referred to as the “P line,” have been introduced from time to
+time, but latterly the increasing use of exponential formulæ in
+thermodynamic, electrical, and physical calculations has led to a
+revival of interest in Dr. Roget’s invention, and various arrangements
+of rules with log.-log. scales are now available.
+
+_The Davis Log.-Log. Rule._—In the rule introduced by Messrs. John Davis
+& Son Limited, Derby, the log.-log. scales are placed upon a separate
+slide—a plan which has the advantage of leaving the rule intact for all
+ordinary purposes, while providing a length of 40 in. for the log.-log.
+scales.
+
+In the 10 in. Davis rule one face of the slide, marked E, has two
+log.-log. scales for numbers greater than unity, the lower extending
+from 1·07 to 2, and the upper continuing the graduations from 2 to 1000.
+On the reverse face of the slide, marked -E, are two log.-log. scales
+for numbers less than unity, the upper extending from 0·001 to 0·5, and
+the lower continuing the graduations from 0·5 to 0·933. Both sets of
+scales are used in conjunction _with the lower or D scale of the rule_,
+which is to be primarily regarded as running from 1 to 10, and
+constitutes a scale of exponents. In the 20 in. rule the log.-log.
+scales are more extensive, and are used in conjunction with the upper or
+A scale of the rule (1 to 100); in what follows, however, the 10 in.
+rule is more particularly referred to.
+
+It has been explained that on the log.-log. scale the distance of any
+numbered graduation from the point of origin represents the log.-log. of
+the number. The point of origin will obviously be that graduation whose
+log.-log. = 0. This is seen to be 10, since log. (log. 10) = log. 1 = 0.
+Hence, confining attention to the E scale, to locate the graduation 20,
+we have log. (log. 20) = log. 1·301 = 0·11397, so that if the scale D is
+25 cm. long, the distance between 10 and 20 on the corresponding
+log.-log. scale would be 113·97 ÷ 4 = 28·49 mm. For numbers less than 10
+the resulting log.-logs. will be negative, and the distances will be
+spaced off from the point of origin in a negative direction—_i.e._, from
+right to left. Thus, to locate the graduation 5, we have
+
+ log. (log. 5) = log. 0·699 = ̅1·844; _i.e._, −1 + 0·844 or −0·156;
+
+so that the graduation marked 5 would be placed 156 ÷ 4 = 39 mm. distant
+from 10 in a _negative_ direction, and proceeding in a similar manner,
+the scale may be extended in either direction. In the -E scale, the
+notation runs in the reverse direction to that of the E scale, but in
+all other respects it is precisely analogous, the distance from the
+point of origin (0·1 in this case) to any graduation _x_ representing
+log. [-log. _x_.]. It follows that of the similarly situated graduations
+on the two scales, those on the -E scale are the _reciprocals_ of those
+on the E scale. This may be readily verified by setting, say, 10 on E to
+(R.H.) 1 on D, when turning to the back of the rule we find 0·1 on -E
+agreeing with the index mark in the aperture at the right-hand extremity
+of the rule.
+
+In using the log.-log. scales it is important to observe (1) that the
+values engraved on the scale are definite and unalterable (_e.g._, 1·2
+can only be read as 1·2 and not as 120, 0·0012, etc., as with the
+ordinary scales); (2) that the upper portion of each scale should be
+regarded as forming a prolongation to the right of the lower portion;
+and (3) that immediately above any value on the lower portion of the
+scale is found the 10th power of that value on the upper portion of the
+scale. Keeping these points in view, if we set 1·1 on E to 1 on D we
+find over 2 on D the value of 1·1^2 = 1·21 on E. Similarly, over 3 we
+find 1·1^3 = 1·331, and so on. Then, reading across the slide, we have,
+over 2, the value of 1·1^{2 × 10} = 1·1^{20} = 6·73, and over 3 we have
+1·1^{3 × 10} = 1·1^{30} = 17·4. Hence the rule:—_To find the value of
+x^n, set x on E to 1 on D, and over n on D read x^n on E._
+
+With the slide set as above, the 8th, 9th, etc., powers of 1·1 cannot be
+read off; but it is seen that, according to (2) in the foregoing, the
+missing portion of the E scale is that part of the upper scale (2 to
+about 2·6) which is outside the rule to the left. Hence placing 1·1 to
+10 on D, the 8th, 9th, etc., powers of 1·1 will be read off _on the
+upper part_ of the E scale. In general, then,
+
+If _x_ on the _lower_ line is set to 1 on D, then _x^n_ is read directly
+on that line and _x_^{10_n_} on the upper line.
+
+If _x_ on the _upper_ line is set to 1 on D, then _x^n_ is read directly
+on that line and _x_^{_ⁿ⁄₁₀_} on the lower line.
+
+If _x_ on the _lower_ line is set to 10 on D, then _x_^{_ⁿ⁄₁₀_} is read
+directly on that line and _x^n_ on the upper line.
+
+If _x_ on the _upper_ line is set to 10 on D, then _x_^{_ⁿ⁄₁₀_} is read
+directly on that line and _x_^{_ⁿ⁄₁₀₀_} on the lower line.
+
+These rules are conveniently exhibited in the accompanying diagram (Fig.
+14). They are equally applicable to both the E and -E scales of the 10
+in. rule, and include practically all the instruction required for
+determining the _n_th power or the _n_th root of a number. They do not
+apply directly to the 20 in. rule, however, for here the relation of the
+lower and upper scales will be _x^n_ and _x_^{100_n_}.
+
+
+ EX.—Find 1·167^{2·56}.
+
+ Set 1·167 on E to 1 on D, and over 2·56 on D read 1·485 on E.
+
+
+ EX.—Find 4·6^{1·61}.
+
+ Set 4·6 on upper E scale to 1 on D, and over 1·61 on D read 11·7
+ (11·67) on E.
+
+
+ EX.—Find 1·4^{0·27} and 1·4^{2·7}.
+
+ Set 1·4 on E to 10 on D, and over 2·7 on D read 1·095 = 1·4^{0·27} on
+ lower E scale and 2·48 = 1·4^{2·7} on upper E scale.
+
+
+[Illustration: FIG. 14.]
+
+
+ EX.—Find 46^{0·0184} and 46^{0·184}.
+
+ Set 46 on upper E scale to 10 on D, and over 1·84 on D read 1·073 on
+ lower E scale and 2·022 (2·0228) on upper E scale.
+
+
+ EX.—Find 0·074^{1·15}.
+
+ Using the -E scale, set 0·074 to 1 on D, and over 1·15 on D read 0·05
+ on -E.
+
+
+The method of determining the root of a number will be obvious from the
+preceding examples.
+
+
+ EX.—Find ^{1.4}√(17) and ^{14}√(17).
+
+ Set 17 on E to 1·4 on D, and over 1 on D read 7·56 on upper E scale
+ and 1·224 on lower E scale.
+
+ EX.—Find ^{0·031}√(0·914).
+
+ Set 0·914 on -E to 3·1 on D, and over 10 on D read 0·055 on upper -E
+ scale.
+
+
+When the exponent _n_ is fractional, it is often possible to obtain the
+result directly with one setting of the slide. Thus to determine
+1·135^{¹⁷⁄₁₆} by the first method we find ¹⁷⁄₁₆ = 1·0625, and placing
+1·135 on E to 1 on D, read 1·144 on E over 1·0625 on D. By the direct
+method we place 1·135 on the E scale on 1·6 on D, and over 1·7 on D read
+1·144 on E. It will be seen that since the scale D is assumed to run
+from 1 to 10 we are unable to read 16 and 17 on this scale; but it is
+obvious that the _ratios_ (1·7)/(1·6) and (17)/(16) are identical, and
+it is with the ratio only that we are, in effect, concerned.
+
+Since an expression of the form _x_^{-_n_} = (1)/(_x^n_) or
+((1)/(_x_))^{_n_}, the required value may be obtained by first
+determining the reciprocal of _x_ and proceeding as before. By using
+both the direct and reciprocal log.-log. scales (E and -E) in
+conjunction however, the required value can be read directly from the
+rule, and the preliminary calculation entirely avoided. In the Davis
+form of rule, the result can be read on the -E scale, used in
+conjunction with the D scale of the rule, _x_ on E being set to the
+index mark in the aperture in the back of the rule.
+
+
+ EX.—Find the value of 1·195^{−1·65}.
+
+ Set 1·195 on E to the index in the left aperture in the back of the
+ rule, and over 1·65 on D read 0·745 on the -E scale.
+
+
+It may be noted in passing that the log.-log. scale affords a simple
+means for determining the logarithm or anti-logarithm of a number to any
+base. For this purpose it is necessary to set the base of the given
+system on E to 1 on D, when _under_ any number on E will be found its
+logarithm on D. Thus, for common logs., we set the base 10 on E to 1 on
+D, and under 100 we find 2, the required log. Similarly we read log. 20
+= 1·301; log. 55 = 1·74; log. 550 = 2·74, etc. Reading reversely, over
+1·38 on D we find its antilog. 24 on E; also antilog. 1·58 = 38;
+antilog. 1·19 = 15·5, etc.
+
+For logs. of numbers under 10 we set the base 10 to 10 on D; hence the
+readings on D will be read as one-tenth their apparent value. Thus log.
+3 = 0·477; log. 5·25 = 0·72; antilog. 0·415 = 2·6; antilog. 0·525 =
+3.·35, etc.
+
+The logs. of the numbers on the lower half of the E scale will also be
+found on the D scale; but a consideration of Fig. 14 will show that this
+will be read as _one-tenth_ its face value if the base is set to 1 on D,
+and as _one-hundredth_ if the base is set to 10.
+
+For natural, hyperbolic, or Napierian logarithms, the base is 2·718. A
+special line marked ε or _e_ serves to locate the exact position of this
+value on the E scale, and placing this to 1 on D we read log._{_e_} 4·35
+= 1·47; log._{_e_} 7·4 = 2·0; antilog._{_e_} × 2·89 = 18, etc. The other
+parts of the scale are read as already described for common logs.
+Calculations involving powers of _e_ are frequently met with, and these
+are facilitated by using the special graduation line referred to, as
+will be readily understood.
+
+If it is required to determine the power or root of a number which does
+not appear on either of the log.-log. scales, we may break up the number
+into factors. Usually it is convenient to make one of the factors a
+power of 10.
+
+
+ EX.—3950^{1·97} = 3·95^{1·97} × 10^{3 × 1·97} = 3·95^{1·97} ×
+ 10^{5·91}.
+
+ Then 3·95^{1·97} = 15, and 10^{5·91} (or antilog.) 5·91 = 812,000.
+ Hence, 15 × 812,000 = 12,180,000 is the result sought.
+
+
+Numbers which are to be found in the higher part of the log.-log. scale
+may often be factorised in this way, and greater accuracy obtained than
+by direct reading.
+
+The form of log.-log. rule which has been mainly dealt with in the
+foregoing gives a scale of comparatively long range, and the only
+objection to the arrangement adopted is the use of a separate slide.
+
+_The Jackson-Davis Double Slide Rule._—In this instrument a pair of
+aluminium clips enable the log.-log. slide to be temporarily attached to
+the lower edge of the ordinary rule, and used, by means of a special
+cursor, in conjunction with the C scale of the ordinary slide. In this
+way both the log.-log. and ordinary scales are available without the
+trouble of replacing one slide by the other. Since the scale of
+exponents is now on the slide, the value of _x^n_ will be obtained by
+setting 1 on C to _x_ on E and reading the result on E under _n_ on C.
+
+By using a pair of log.-log. slides, one in the rule and one clamped to
+the edge by the clips, we have an arrangement which is very useful in
+deducing empirical formulæ of the type _y_ = _x^n_.
+
+_The Yokota Slide Rule._—In this instrument the log.-log. scales are
+placed on the face of the rule, each set comprising three lines. These,
+for numbers greater than 1, are found above the A scale while the three
+reciprocal log.-log. lines are below the D scale. Both sets are used in
+conjunction with the C scale on the slide. Other features of this rule
+are:—The ordinary scales are 10 in. long instead of 25 cm. as hitherto
+usual; hence the logarithms of numbers can be read on the ordinary scale
+of inches on the edge of the rule. There is a scale of cubes in the
+centre of the slide and on the back of the slide there is a scale of
+secants in addition to the sine and tangent scales.
+
+[Illustration: FIG. 15.]
+
+_The Faber Log.-log. Rule._—In this instrument shown in Fig. 15, the two
+log.-log. scales are placed on the face of the rule. One section,
+extending from 1·1 to 2·9, is placed above the A scale, and the other
+section, extending from 2·9 to 100,000, is placed below the D scale.
+These scales are used in conjunction with the C scale of the slide in
+the manner previously described. The width of the rule is increased
+slightly, but the arrangement is more convenient than that formerly
+employed, wherein the log.-log. scales were placed on the bevelled edge
+of the rule and read by a tongue projecting from the cursor.
+
+[Illustration: FIG. 16.]
+
+Another novel feature of this rule is the provision of two special
+scales at the bottom of the groove, to which a bevelled metal index or
+marker on the left end of the slide can be set. The upper of these
+scales is for determining the efficiency of dynamos and electric motors;
+the lower for determining the loss of potential in an electric circuit.
+
+_The Perry Log.-log. Rule._—In this rule, introduced by Messrs. A. G.
+Thornton, Limited, Manchester, the log.-log. scales are arranged as in
+Fig. 16, the E scale, running from 1·1 to 10,000, being placed above the
+A scale of the rule, and the -E or E^{−1} scale running from 0·93 to
+0·0001, below the D scale of the rule. These scales are read in
+conjunction with the B scales on the slide by the aid of the cursor.
+
+The following tabular statement embodies all the instructions required
+for using this form of log.-log. slide rule:—
+
+ When _x_ is greater than 1.
+
+ _x^n_ Set 1 on B to _x_ on E; over _n_ on B read _x^n_ on E
+ _x_^{-_n_} Set 1 on B to _x_ on E; under _n_ on B read _x_^{-_n_} on
+ E^{−1}
+ _x_^{_ⁱ⁄ₙ_} Set _n_ on B to _x_ on E; over 1 on B read _x_^{_ⁱ⁄ₙ_} on
+ E
+ _x_^{_⁻ⁱ⁄ₙ_} Set _n_ on B to _x_ on E; under 1 on B read _x_^{_⁻ⁱ⁄ₙ_}
+ on E^{−1}
+
+ When _x_ is less than 1.
+
+ _x^n_ Set 1 on B to _x_ on E^{−1}; under _n_ on B read _x^n_ on
+ E^{−1}
+ _x_^{-_n_} Set 1 on B to _x_ on E^{−1}; over _n_ on B read _x_^{-_n_}
+ on E
+ _x_^{_ⁱ⁄ₙ_} Set _n_ on B to _x_ on E^{−1}; under 1 on B read
+ _x_^{_ⁱ⁄ₙ_} on E^{−1}
+ _x_^{_⁻ⁱ⁄ₙ_} Set _n_ on B to _x_ on E^{−1}; over 1 on B read
+ _x_^{_⁻ⁱ⁄ₙ_} on E
+
+If 10 on B is used in place of 1 on B, read _x_^{_ⁿ⁄₁₀_} in place of
+_x^n_ on E, and _x_^{-_ⁿ⁄₁₀_} in place of _x_^{-_n_} on E^{−1}. If 100
+on B is used, these readings are to be taken as _x_^{_ⁿ⁄₁₀₀_} and
+_x_^{-_ⁿ⁄₁₀₀_} respectively.
+
+In rules with no -E scale the value of _x_^{-_n_} is obtained by the
+usual rules for reciprocals. We may either determine _x^n_ and find its
+reciprocal or, first find the reciprocal of _x_ and raise it to the
+_n_th power. The first method should be followed when the number _x_ is
+found on the E scale.
+
+
+ EX.—3·45^{−1·82} = 0·105.
+
+ Set 1 on C to 3·45 on E, and under 1·82 on C read 9·51 on C. Then set
+ 1 on B to 9·5 on A, and under index of A read 0·105 on B.
+
+
+When _x_ is less than 1 the second method is more suitable.
+
+
+ EX.—0·23^{−1·77} = ((1)/(0·23))^{1·77} = 4·35^{1·77} = 13·5
+
+ Set 1 on B to 0·23 on A, and under index of A read (1)/(0·23) = 4·35
+ on B.
+
+ Set 1 on C to 4·35 on E, and under 1·77 on C read 13·5 on E.
+
+
+As with the Davis rule, the exponent scale C will be read as ⅒th its
+face value if its R.H. index (10) is used in place of 1.
+
+
+ SPECIAL TYPES OF SLIDE RULES.
+
+In addition, to the new forms of log.-log. slide rules previously
+described, several other arrangements have been recently introduced,
+notably a series by Mr. A. Nestler, of Lahr (London: A. Fastlinger, Snow
+Hill). These comprise the “Rietz,” the “Precision,” the “Universal,” and
+the “Fix” slide rules.
+
+THE RIETZ RULE.—In this rule the usual scales A, B, C, and D, are
+provided, while at the upper edge is a scale, which, being three times
+the range of the D scale, enables cubes and cube roots to be directly
+evaluated and also _n_^{³⁄₂} and _n_^⅔.
+
+A scale at the lower edge of the rule gives the mantissa of the
+logarithms of the numbers on D.
+
+THE PRECISION SLIDE RULE.—In this rule the scales are so arranged that
+the accuracy of a 20 in. rule is obtainable in a length of 10 in. This
+is effected by dividing a 20 in. (50 cm.) scale length into two parts
+and placing these on the working edges of the rule and slide. On the
+upper and lower margins of the face of the rule are the two parts of
+what corresponds to the A scale in the ordinary rule; while in the
+centre of the slide is the scale of logarithms which, used in
+conjunction with the 50 cm. scales on the slide, is virtually twice the
+length of that ordinarily obtainable in a 10 in. rule. The same remark
+applies to the trigonometrical scales on the under face of the slide.
+Both the sine and tangent scales are in two adjacent lengths, while on
+the edge of the stock of the rule, below the cursor groove, is a scale
+of sines of small angles from 1° 49′ to 5° 44′. This is referred to the
+50 cm. scales by an index projection on the cursor.
+
+If C and C′ are the two parts of the scale on the slide and D and D′ the
+corresponding scales on the rule, it is clear that in multiplying two
+factors 1 on C can only be set directly to the upper scale D; while 10
+on C′ can only be set directly to the lower scale D′. Hence if the first
+factor is greater than about 3·2, the cursor must be used to bring 1 on
+C to the first factor on D′. Similarly, in division, numerators and
+denominators which occur on C and D′ or on C′ and D cannot be placed in
+direct coincidence but must be set by the aid of the cursor.
+
+Any uncertainty in reading the result can be avoided by observing the
+following rule: _If in setting the index_ (1 _or_ 10) _in
+multiplication, or in setting the numerator to the denominator in
+division, it is necessary to cross the slide, then it will also be
+necessary to cross the slide to read the product or quotient._
+
+THE UNIVERSAL SLIDE RULE.—In this instrument the stock carries two
+similar scales running from 1 to 10, to which the slide can be set.
+Above the upper one is the logarithm scale and under the lower one the
+scale of squares 1 to 100. On the edge of the stock of the rule, under
+the cursor groove, is a scale running from 1 to 1000. An index
+projecting from the cursor enables this scale to be used with the scales
+on the face of the rule, giving cubes, cube roots, etc.
+
+On the slide, the lower scale is an ordinary scale, 1 to 10. The centre
+scale is the first part of a scale giving the values of sin _n_ cos _n_,
+this scale being continued along the upper edge of the slide (marked
+“sin-cos”) up to the graduation 50. On the remainder of this line is a
+scale running from right to left (0 to 50) and giving the value of
+cos^2_n_. In surveying, these scales greatly facilitate the calculations
+for the horizontal distance between the observer’s station and any
+point, and the difference in height of these two points.
+
+On the back of the slide are scales for the sines and tangents of
+angles. The values of the sines and tangents of angles from 34′ to 5°
+44′ differ little from one another, and the one centre scale suffices
+for both functions of these small angles.
+
+THE FIX SLIDE RULE.—This is a standard rule in all respects, except that
+the A scale is displaced by a distance (π)/(4) so that over 1 on D is
+found 0·7854 on A. This enables calculations relating to the area and
+cubic contents of cylinders to be determined very readily.
+
+THE BEGHIN SLIDE RULE.—We have seen that a disadvantage attending the
+use of the ordinary C and D scales, is that it is occasionally necessary
+to traverse the slide through its own length in order to change the
+indices or to bring other parts of the slide into a readable position
+with regard to the stock. To obviate this disadvantage, Tserepachinsky
+devised an ingenious arrangement which has since been used in various
+rules, notably in the Beghin slide rule made by Messrs. Tavernier-Gravêt
+of Paris. In this rule the C and D scales are used as in the standard
+rule, but in place of the A and B scales, we have another pair of C and
+D scales, displaced by one-half the length of the rule. The lower pair
+of scales may therefore be regarded as running from 10^{_n_} to 10^{_n_
++ 1}, and the upper pair as running from √(10) × 10^{_n_} to √(10) ×
+10^{_n_ + 1}. With this arrangement, _without moving the slide more than
+half its length_, to the left or right, it is always possible to compare
+_all values between_ 1 _and_ 10 _on the two scales_. This is a great
+advantage especially in continuous working.
+
+Another commendable feature of the Beghin rule is the presence of a
+reversed C scale in the centre of the slide, thus enabling such
+calculations as _a_ × _b_ × _c_ to be made with one setting of the
+slide. On the back of the slide are three scales, the lowest of which,
+used with the D scale, is a scale of squares (corresponding to the
+ordinary B scale), while on the upper edge is a scale of sines from 5°
+44′ to 90°, and in the centre, a scale of tangents from 5° 43′ to 45°.
+On the square edge of the stock, under the cursor groove, is the
+logarithm scale, while on the same edge, above the cursor groove, are a
+series of gauge points. All these values are referred to the face scales
+by index marks on the cursor.
+
+THE ANDERSON SLIDE RULE.—The principle of dividing a long scale into
+sections as in the Precision rule, has been extended in the Anderson
+slide rule made by Messrs. Casella & Co., London, and shown in Fig. 17.
+In this the slide carries a scale in four sections, used in conjunction
+with an exactly similar set of scale-lines in the upper part of the
+stock. On the lower part of the stock is a scale in eight sections
+giving the square roots of the upper values. In order to set the index
+of the slide to values in the stock, two indices of transparent
+celluloid are fixed to the slide extending over the face of the rule as
+shown in the illustration. As each scale section is 30 cm. in length,
+the upper lines correspond to a single scale of nearly 4 ft., and the
+lower set to one of nearly 8 ft. in length, giving a correspondingly
+large increase in the number of subdivisions of these scales, and
+consequently much greater accuracy.
+
+In order to decide upon which line a result is to be found, sets of
+“line numbers” are marked at each end of the rule and slide and also on
+the metal frame of the cursor. In multiplication, the line number of the
+product is the sum of the line numbers of the factors if the left index
+is used, or 1 more than this sum if the right index is used. The
+illustration shows the multiplication of 2 by 4. The left index is set
+to 2 (line number, 1), and the cursor set to 4 on the slide (line
+number, 2); hence, as the left index is used, the result is found on
+line No. 3. Similar rules are readily established for division. The
+column of line numbers headed 0 is used for units, that headed 4 for
+tens, and so on; one column is given for tenths, headed −4. The square
+root scale bears similar line numbers, so that the square root of any
+value on the upper scales is found on the correspondingly figured line
+below.
+
+[Illustration: FIG. 17.]
+
+THE MULTIPLEX SLIDE RULE differs from the ordinary form of rule in the
+arrangement of the B scale. The right-hand section of this scale runs
+from left to right as ordinarily arranged, but the left-hand section
+runs in the reverse direction, and so furnishes a reciprocal scale. At
+the bottom of the groove, under the slide, there is a scale running from
+1 to 1000, which is used in conjunction with the D scale, readings being
+referred thereto by a metal index on the end of the slide. By this means
+cubes, cube roots, etc., can be read off directly. Messrs. Eugene
+Dietzgen & Co., New York, are the makers.
+
+THE “LONG” SLIDE RULE has one scale in two sections along the upper and
+lower parts of the stock, as in the “Precision” rule. The scale on the
+slide is similarly divided, but the graduations run in the reverse
+direction, corresponding to an inverted slide. Hence the rules for
+multiplication and division are the reverse of those usually followed
+(page 30). On the back of the slide is a single scale 1–10, and a scale
+1–1000, giving cubes of this single scale. By using the first in
+conjunction with the scales on the stock, squares may be read, while in
+conjunction with the cube scale, various expressions involving squares,
+cubes and their roots may be evaluated.
+
+HALL’S NAUTICAL SLIDE RULE consists of two slides fitting in grooves in
+the stock, and provided with eight scales, two on each slide, and one on
+each edge of each groove. While fulfilling the purposes of an ordinary
+slide rule, it is of especial service to the practical navigator in
+connection with such problems as the “reduction of an ex-meridian sight”
+and the “correction of chronometer sights for error in latitude.” The
+rule, which has many other applications of a similar character, is made
+by Mr. J. H. Steward, Strand, London.
+
+
+ LONG-SCALE SLIDE RULES
+
+It has been shown that the degree of accuracy attainable in slide-rule
+calculations depends upon the length of scale employed. Considerations
+of general convenience, however, render simple straight-scale rules of
+more than 20 in. in length inadmissible, so that inventors of long-scale
+slide rules, in order to obtain a high degree of precision, combined
+with convenience in operation, have been compelled to modify the
+arrangement of scales usually employed. The principal methods adopted
+may be classed under three varieties: (1) The use of a long scale in
+sectional lengths, as in Hannyngton’s Extended Slide Rule and Thacher’s
+Calculating Instrument; (2) the employment of a long scale laid in
+spiral form upon a disc, as in Fearnley’s Universal Calculator and
+Schuerman’s Calculating Instrument; and (3) the adoption of a long scale
+wound helically upon a cylinder, of which Fuller’s and the “R.H.S.”
+Calculating Rules are examples.
+
+FULLER’S CALCULATING RULE.—This instrument, which is shown in Fig. 18,
+consists of a cylinder _d_ capable of being moved up and down and around
+the cylindrical stock _f_, which is held by the handle. The logarithmic
+scale-line is arranged in the form of a helix upon the surface of the
+cylinder _d_, and as it is equivalent to a straight scale of 500 inches,
+or 41 ft. 8 in., it is possible to obtain four, and frequently five,
+figures in a result.
+
+Upon reference to the figure it will be seen that three indices are
+employed. Of these, that lettered _b_ is fixed to the handle; while two
+others, _c_ and _a_ (whose distance apart is equal to the axial length
+of the complete helix), are fixed to the innermost cylinder _g_. This
+latter cylinder slides telescopically in the stock _f_, enabling the
+indices to be placed in any required position relatively to _d_. Two
+other scales are provided, one (_m_) at the upper end of the cylinder
+_d_, and the other (_n_) on the movable index.
+
+[Illustration: FIG. 18.]
+
+In using the instrument a given number on _d_ is set to the fixed index
+_b_, and either _a_ or _c_ is brought to another number on the scale.
+This establishes a ratio, and if the cylinder is now moved so as to
+bring any number to _b_, the fourth term of the proportion will be found
+under _a_ or _c_. Of course, in multiplication, one factor is brought to
+_b_, and _a_ or _c_ brought to 100. The other factor is then brought to
+_a_ or _c_, and the result read off under _b_. Problems involving
+continuous multiplication, or combined multiplication and division, are
+very readily dealt with. Thus, calling the fixed index F, the upper
+movable index A, and the lower movable index B, we have for _a_ × _b_ ×
+_c_:—Bring _a_ to F; A to 100; _b_ to A or B; A to 100; _c_ to A or B
+and read the product at F.
+
+The maximum number of figures in a product is the sum of the number of
+figures in the factors and this results when all the factors except the
+first have to be brought to B. Each time a factor is brought to A, 1 is
+to be deducted from that sum.
+
+For division, as _a_/(_m_ × _n_), bring _a_ to F; A or B to _m_; 100 to
+A; A or B to _a_; 100 to A and read the quotient at F.
+
+[Illustration: FIG. 19.]
+
+The maximum number of figures in the quotient is the difference between
+the sum of the number of figures in the numerator factors and those of
+the denominator factors, _plus_ 1 for each factor of the denominator and
+this results when A has to be set to all the factors of the denominator
+and all the factors of the numerator except the first brought to B. Each
+time B is set to a denominator factor or a numerator factor is brought
+to A, 1 is to be deducted.
+
+Logarithms of numbers are obtained by using the scales _m_ and _n_ and
+hence powers and roots of any magnitude may be obtained by the procedure
+already fully explained. The instrument illustrated is made by Messrs.
+W. F. Stanley & Co., Limited, London.
+
+THE “R.H.S.” CALCULATOR.—In this calculator, designed by Prof. R. H.
+Smith, the scale-line, which is 50 in. long, is also arranged in a
+spiral form (Fig. 19), but in this case it is wrapped around the central
+portion of a tube which is about ¾in. in diameter and 9½in. long. A
+slotted holder, capable of sliding upon the plain portions of this tube,
+is provided with four horns, these being formed at the ends of the two
+wide openings through which the scale is read. An outer ring carrying
+two horns completes the arrangement.
+
+One of the horns of the holder being placed in agreement with the first
+factor, and one of the horns of the ring with the second factor, the
+holder is moved until the third factor falls under the same horn of the
+ring, when the resulting fourth term will be found under the same (right
+or left) horn of the holder, at either end of the slot. In
+multiplication, 100 or 1000 is taken for the second factor in the above
+proportion, as already explained in connection with Fuller’s rule;
+indeed, generally, the mode of operation is essentially similar to that
+followed with the former instrument.
+
+The scale shown on one edge of the opening in the holder, together with
+the circular scale at the top of the spiral, enables the mantissæ of
+logarithms of numbers to be obtained, and thus problems involving powers
+and roots may be dealt with quite readily. This instrument is supplied
+by Mr. J. H. Steward, London.
+
+THACHER’S CALCULATING INSTRUMENT, shown in Fig. 20, consists of a
+cylinder 4 in. in diameter and 18 in. long, which can be given both a
+rotary and a longitudinal movement within an open framework composed of
+twenty triangular bars. These bars are connected to rings at their ends,
+which can be rotated in standards fixed to the baseboard. The scale on
+the cylinder consists of forty sectional lengths, but of each scale-line
+that part which appears on the right-hand half of the cylinder is
+repeated on the left-hand half, one line in advance. Hence each half of
+the cylinder virtually contains two complete scales following round in
+regular order. On the lower lines of the triangular bars are scales
+exactly corresponding to those on the cylinder, while upon the upper
+lines of the bars and not in contact with the slide is a scale of square
+roots.
+
+[Illustration: FIG. 20.]
+
+By rotating the slide any line on it may be brought opposite any line in
+frame and by a longitudinal movement any graduation on these lines may
+be brought into agreement. The whole can be rotated in the supporting
+standards in order to bring any reading into view. As shown in the
+illustration, a magnifier is provided, this being conveniently mounted
+on a bar, along which it can be moved as required.
+
+SECTIONAL LENGTH OR GRIDIRON SLIDE RULES.—The idea of breaking up a long
+scale into sectional lengths is due to Dr. J. D. Everett, who described
+such a gridiron type of slide rule in 1866. Hannyngton’s Extended Slide
+Rule is on the same principle. Both instruments have the lower scale
+repeated. H. Cherry (1880) appears to have been the first to show that
+such duplication could be avoided by providing two fixed index points in
+addition to the natural indices of the scale. These additional indices
+are shown at 10′ and 100′ in Fig. 21, which represents the lower sheet
+of Cherry’s Calculator on a reduced scale. The upper member of the
+calculator consists of a transparent sheet ruled with parallel lines,
+which coincide with the lines of the lower scale when the indices of
+both are placed in agreement. To multiply one number by another, one of
+the indices on the upper sheet is placed to one of the factors, and the
+position of whichever index falls under the transparent sheet is noted
+on the latter. Bringing the latter point to the other factor, the result
+is found under whichever index lies on the card. In other arrangements
+the inventor used transparent scales, the graduations running in a
+reverse direction to those of the lower scale. In this case, a factor on
+the upper scale is set to the other factor on the lower, and the result
+read at the available index.
+
+[Illustration: FIG. 21.]
+
+PROELL’S POCKET CALCULATOR is an application of the last-named
+principle. It comprises a lower card arranged as Fig. 21, with an upper
+sheet of transparent celluloid on which is a similar scale running in
+the reverse direction. For continued multiplication and division, a
+needle (supplied with the instrument) is used as a substitute for a
+cursor, to fix the position of the intermediate results. A series of
+index points on the lower card enable square and cube roots to be
+extracted very readily. This calculator is supplied by Messrs. John J.
+Griffin & Sons, Ltd., London.
+
+
+
+
+ CIRCULAR CALCULATORS.
+
+
+Although the 10 in. slide rule is probably the most serviceable form of
+calculating instrument for general purposes, many prefer the more
+portable circular calculator, of which many varieties have been
+introduced during recent years. The advantages of this type are: It is
+more compact and conveniently carried in the waistcoat pocket. The
+scales are continuous, so that no traversing of the slide from 1 to 10
+is required. The dial can be set quickly to any value; there is no
+trouble with tight or ill-fitting slides. The disadvantages of most
+forms are: Many problems involve more operations than a straight rule.
+The results being read under fingers or pointers, an error due to
+parallax is introduced, so that the results generally are not so
+accurate as with a straight rule. The inner scales are short, and
+therefore are read with less accuracy. Special scale circles are needed
+for cubes and cube roots. The slide cannot be reversed or inverted.
+
+[Illustration: FIG. 22.]
+
+[Illustration: FIG. 23.]
+
+THE BOUCHER CALCULATOR.—This circular calculator resembles a
+stem-winding watch, being about 2 in. in diameter and ⁹⁄₁₆in. in
+thickness. The instrument has two dials, the back one being fixed, while
+the front one, Fig. 22 (showing the form made by Messrs. W. F. Stanley,
+London), turns upon the large centre arbor shown. This movement is
+effected by turning the milled head of the stem-winder. The small centre
+axis, which is turned by rotating the milled head at the side of the
+case, carries two fine needle pointers, one moving over each dial, and
+so fixed on the axis that one pointer always lies evenly over the other.
+A fine index or pointer fixed to the case in line with the axis of the
+winding stem, extends over the four scales of the movable dial as shown.
+Of these scales, the second from the outer is the ordinary logarithmic
+scale, which in this instrument corresponds to a straight scale of about
+4¾in. in length. The two inner circles give the square roots of the
+numbers on the primary logarithmic scale, the smaller circle containing
+the square roots of values between 1 and 3·162 (= √(10)), while the
+other section corresponds to values between 3·162 and 10. The outer
+circle is a scale of logarithms of sines of angles, the corresponding
+sines of which can be read off on the ordinary scale.
+
+On the fixed or back dial there are also four scales, these being
+arranged as in Fig. 23. The outer of these is a scale of equal parts,
+while the three inner scales are separate sections of a scale giving the
+cube roots of the numbers taken on the ordinary logarithmic scale and
+referred thereto by means of the pointers. In dividing this cube-root
+scale into sections, the same method is adopted as in the case of the
+square-root scale. Thus, the smallest circle contains the cube roots of
+numbers between 1 and 10, and is therefore graduated from 1 to 2·154;
+the second circle contains the cube roots of numbers between 10 and 100,
+being graduated from 2·154 to 4·657; while the third section, in which
+are found the cube roots of numbers between 100 and 1000, carries the
+graduations from 4·657 to 10.
+
+What has been said in an earlier section regarding the notation of the
+slide rule may in general be taken to apply to the scales of the Boucher
+calculator. The manner of using the instrument is, however, not quite so
+evident, although from what follows it will be seen that the operative
+principle—that of variously combining lengths of a logarithmic scale—is
+essentially similar. In this case, however, it is seen that in place of
+the straight scale-lengths shown in Fig. 4, we require to add or
+subtract arc-lengths of the circular scales, while, further, it is
+evident that in the absence of a fixed scale (corresponding to the stock
+of the slide rule) these operations cannot be directly performed as in
+the ordinary form of instrument. However, by the aid of the fixed index
+and the movable pointer, we can effect the desired combination of the
+scale-lengths in the following manner. Assuming it is desired to
+multiply 2 by 3, the dial is turned in a backward direction until 2 on
+the ordinary scale lies under the fixed index, after which the movable
+pointer is set to 1 on the scale. As now set, it is clear that the
+arc-length 1–2 is spaced off between the fixed index and the movable
+pointer, and it now only remains to add to this definite arc-length a
+further length of 1–3. To do this we turn the dial still further
+backward until the arc 1–3 has passed under the movable pointer, when
+the result, 6, is read under the fixed index. A little consideration
+will show that any other scale length may be added to that included
+between the fixed and movable pointers, or, in other words, any number
+on the scale may be multiplied by 2 by bringing the number to the
+movable pointer and reading the result under the fixed index. The rule
+for multiplication is now evident.
+
+_Rule for Multiplication._—_Set one factor to the fixed index and bring
+the pointer to 1 on the scale; set the other factor to the pointer and
+read the result under the fixed index._
+
+With the explanation just given, the process of division needs little
+explanation. It is clear that to divide 6 by 3, an arc-length 1–3 is to
+be taken from a length 1–6. To this end we set 6 to the index
+(corresponding in effect to passing a length 1–6 to the left of that
+reference point) and set the pointer to the divisor 3. As now set, the
+arc 1–6 is included between 1 on the scale and the index, while the arc
+1–3 is included between 1 on the scale and the pointer. Obviously if the
+dial is now turned forward until 1 on the scale agrees with the pointer,
+an arc 1–3 will have been deducted from the larger arc 1–6, and the
+remainder, representing the result of this operation, will be read under
+the index as 2.
+
+_Rule for Division._—_Set the dividend to the fixed index, and the
+pointer to the divisor; turn the dial until 1 on the scale agrees with
+the pointer, and read the result under the fixed index._
+
+The foregoing method being an inversion of the rule for multiplication,
+is easily remembered and is generally advised. Another plan is, however,
+preferable when a series of divisions are to be effected with a constant
+divisor—_i.e._, when _b_ in (_a_)/(_b_) = _x_ is constant. In this case
+1 on the scale is set to the index and the pointer set to _b_; then if
+any value of a is brought to the pointer, the quotient _x_ will be found
+under the index.
+
+_Combined Multiplication and Division_, as (_a_ × _b_ × _c_)/(_m_ × _n_)
+= _x_, can be readily performed, while cases of continued multiplication
+evidently come under the same category, since _a_ × _b_ × _c_ = (_a_ ×
+_b_ × _c_)/(1 × 1) = _x_. Such cases as _a_/(_m_ × _n_ × _r_) = _x_ are
+regarded as (_a_ × 1 × 1 × 1)/(_m_ × _n_ × _r_) = _x_; while (_a_ × _b_
+× _c_)/(_m_) = _x_ is similarly modified, taking the form (_a_ × _b_ ×
+_c_)/(_m_ × 1) = _x_. In all cases the expression must be arranged so
+that there is _one more factor in the numerator_ than _in the
+denominator_, _1’s being introduced as often as required_. The simple
+operations of multiplication and division involve a similar disposition
+of factors, since from the rules given it is evident that _m_ × _n_ is
+actually regarded as (_m_ × _n_)/(1), while (_m_)/(_n_) becomes in
+effect (_m_ × 1)/(_n_). It is important to note the general
+applicability of this arrangement-rule, as it will be found of great
+assistance in solving more complicated expressions.
+
+As with the ordinary form of slide rule, the factors in such an
+expression as (_a_ × _b_ × _c_)/(_m_ × _n_) = _x_ are taken in the
+order:—1st factor of numerator; 1st factor of denominator; 2nd factor of
+numerator; 2nd factor of denominator, and so on; the 1st factor as _a_
+being set to the index, and the result _x_ being finally read at the
+same point of reference.
+
+
+ EX.—(39 × 14·2 × 6·3)/(1·37 × 19) = 134.
+
+ Commence by setting 39 to the index, and the pointer to 1·37; bring
+ 14·2 to the pointer; pointer to 19; 6·3 to the pointer, and read the
+ result 134 at the index.
+
+
+It should be noted that after the first factor is set to the fixed
+index, the _pointer_ is set to each of the _dividing_ factors as they
+enter into the calculation, while the _dial_ is moved for each of the
+_multiplying_ factors. Thus the dial is first moved (setting the first
+factor to the index), then the pointer, then the dial, and so on.
+
+_Number of Digits in the Result._—If rules are preferred to the plan of
+roughly estimating the result, the general rules given on pages 21 and
+25 should be employed for simple cases of multiplication and division.
+For combined multiplication and division, modify the expression, if
+necessary, by introducing 1’s, as already explained, and subtract the
+sum of the denominator digits from the sum of numerator digits. Then
+proceed by the author’s rule, as follows:—
+
+_Always turn dial to the_ LEFT; _i.e._, _against the hands of a watch_.
+
+_Note dial movements only; ignore those of the pointer._
+
+_Each time 1 on dial agrees with or passes fixed index_, ADD _1 to the
+above difference of digits_.
+
+_Each time 1 on dial agrees with or passes pointer_, DEDUCT _1 from the
+above difference of digits_.
+
+Treat continued multiplication in the same way, counting the 1’s used as
+denominator digits as one less than the number of multiplied factors.
+
+
+ EX.—(8·6 × 0·73 × 1·02)/(3·5 × 0·23) = 7·95 [7·95473+].
+
+ Set 8·6 to index and pointer to 3·5. Bring 0·73 to pointer (noting
+ that 1 on the scale passes the index) and set pointer to 0·23. Set
+ 1·02 to pointer (noting that 1 on the scale passes the pointer) and
+ read under index 7·95. There are 1 + 0 + 1 = 2 numerator digits and 1
+ + 0 = 1 denominator digit; while 1 is to be added and 1 deducted as
+ per rule. But as the latter cancel, the digits in the result will be 2
+ − 1 = 1.
+
+
+When moving the dial to the left will cause 1 on the dial to pass _both_
+index and pointer (thus cancelling), the dial may be turned back to make
+the setting.
+
+It will be understood that when 1 is the _first_ numerator, and 1 on the
+dial is therefore set to the index, no digit addition will be made for
+this, as the actual operation of calculating has not been commenced.
+
+In the Stanley-Boucher calculator (Fig. 23) a small centre scale is
+added, on which a finger indicates automatically the number of digits to
+be added or deducted; the method of calculating, however, differs from
+the foregoing. To avoid turning back to 0 at the commencement of each
+calculation, a circle is ground on the glass face, so that a pencil mark
+can be made thereon to show the position of the finger when commencing a
+calculation.
+
+_To Find the Square of a Number._— Set the number, on one or other of
+the square root scales, to the index, and read the required square on
+the ordinary scale.
+
+_To Find the Square Root of a Number._—Set the number to the index, and
+if there is an _odd_ number of digits in the number, read the root on
+the inner circle; if an even number, on the second circle.
+
+_To Find the Cube of a Number._—Set 1 on the ordinary scale to the
+index, and the pointer (on the back dial) to the number on one of the
+three cube-root scales. Then under the pointer read the cube on the
+ordinary scale.
+
+_To Find the Cube Root of a Number._—Set 1 to index, and pointer to
+number. Then read the cube root under the pointer on one of the three
+inner circles on the back dial. If the number has
+
+ 1, 4, 7, 10 or −2, −5, etc., digits, use the inner circle.
+ 2, 5, 8, 11 or −1, −4, etc., „ „ second circle.
+ 3, 6, 9, 12 or −0, −3, etc., „ „ third circle.
+
+_For Powers or Roots of Higher Denomination._—Set 1 to index, the
+pointer to the number on the ordinary scale, and read on the outer
+circle on the back dial the mantissa of the logarithm. Add the
+characteristic (see p. 46), multiply by the power or divide by the root,
+and set the pointer to the mantissa of the result on this outer circle.
+Under the pointer on the ordinary scale read the number, obtaining the
+number of figures from the characteristic.
+
+_To Find the Sines of Angles._—Set 1 to index, pointer to the angle on
+the outer circle, and read under the pointer the _natural sine_ on the
+ordinary scale; also under the pointer on the outer circle of the back
+dial read the _logarithmic sine_.
+
+THE HALDEN CALCULEX.—After the introduction of the Boucher calculator in
+1876, circular instruments, such as the Charpentier calculator, were
+introduced, in which a disc turned within a fixed ring, so that scales
+on the faces of both could be set together and ratios established as on
+the slide rule. Cultriss’s Calculating Disc is another instrument on the
+same principle. The Halden Calculex, of which half-size illustrations
+are given in Figs. 24 and 25, represents a considerable improvement upon
+these early instruments. It consists of an outer metal ring carrying a
+fixed-scale ring, within which is a dial. On each side of this dial are
+flat milled heads, so that by holding these between the thumb and
+forefinger the dial can be set quickly and conveniently. The protecting
+glass discs, which are not fixed in the metal ring but are arranged to
+turn therein, carry fine cursor lines, and as these are on the side next
+to the scales a very close setting can be made quite free from the
+effects of parallax. This construction not only avoids the use of
+mechanism, with its risk of derangement, but reduces the bulk of the
+instrument very considerably, the thickness being about ¼in.
+
+On the front face, Fig. 24, the fixed ring carries an outer
+evenly-divided scale, giving logarithms, and an ordinary scale, 1–10,
+which works in conjunction with a similar scale on the edge of the dial.
+The two inner circles give the square roots of values on the main scales
+as in the Boucher calculator. On the back face, Fig. 25, the ring bears
+an outer scale, giving sines of angles from 6° to 90° and an ordinary
+scale, 1–10, as on the front face. The scales on the dial are all
+reversed in direction (running from right to left), the outer one
+consisting of an ordinary (but inverse) scale, 1–10, while the three
+inner circles give the cube roots of values on this inverse scale. As
+the fine cursor lines extend over all the scales, a variety of
+calculations can be effected very readily and accurately.
+
+[Illustration: FIG. 24.]
+
+[Illustration: FIG. 25.]
+
+SPERRY’S POCKET CALCULATOR, made by the Keuffel and Esser Company, New
+York (Fig. 26), has two rotating dials, each with its own pointer and
+fixed index. The S dial has an outer scale of equal parts, an ordinary
+logarithmic scale, and a square-root scale. The L dial has a single
+logarithmic scale arranged spirally, in three sections, giving a scale
+length of 12½in. The pointers are turned by the small milled head, which
+is concentric with the milled thumb-nut by which the two dials are
+rotated. The gearing is such that both the L dial and its pointer rotate
+three times as fast as the S dial and pointer. All the usual
+calculations can be made with the spiral scale, as with the Boucher
+calculator, and the result read off on one or other of the three
+scale-sections. Frequently the point at which to read the result is
+obvious, but otherwise a reference to the single scale on the S dial
+will show on which of the three spirals the result is to be found.
+
+[Illustration: FIG. 26.]
+
+_The K and E Calculator_, also made by the Keuffel and Esser Company, is
+shown in Figs. 27 and 28. It has two dials, of which only one revolves.
+This, as shown in Fig. 27, has an ordinary logarithmic scale and a scale
+of squares. There is an index line engraved on the glass of the
+instrument. The fixed dial has a scale of tangents, a scale of equal
+parts and a scale of sines, the latter being on a two-turn spiral. The
+pointers, which move together, are turned by a milled nut and the
+movable dial by a thumb-nut, as in Sperry’s Calculator, Fig. 26.
+
+[Illustration: FIG. 27.]
+
+[Illustration: FIG. 28.]
+
+
+ SLIDE RULES FOR SPECIAL CALCULATIONS.
+
+ENGINE POWER COMPUTER.—A typical example of special slide rules is shown
+in Fig. 29, which represents, on a scale of about half full size, the
+author’s Power Computer for Steam, Gas, and Oil Engines. This, as will
+be seen, consists of a stock, on the lower portion of which is a scale
+of cylinder diameters, while the upper portion carries a scale of
+horse-powers. In the groove between these scales are two slides, also
+carrying scales, and capable of sliding in edge contact with the stock
+and with each other.
+
+This instrument gives directly the brake horse-power of any steam, gas,
+or oil engine; the indicated horse-power, the dimensions of an engine to
+develop a given power, and the mechanical efficiency of an engine. The
+calculation of piston speed, velocity ratios of pulleys and gear wheels,
+the circumferential speed of pulleys, and the velocity of belts and
+ropes driven thereby, are among the other principal purposes for which
+the computer may be employed.
+
+[Illustration: FIG. 29.]
+
+THE SMITH-DAVIS PIECEWORK BALANCE CALCULATOR has two scales, 11 feet
+long, having a range from 1d. to £20, and marked so that they can be
+used either for money or time calculations. The scales are placed on the
+rims of two similar wheels and so arranged that the divided edges come
+together. The wheels are mounted on a spindle carried at each end in the
+bearings of a supporting stand. The wheels are pressed together by a
+spring, and move as one.
+
+To set the scales one to the other, a treadle gear is arranged to take
+the pressure of the spring so that when the fixed wheel is held by the
+left hand the free wheel can be rotated by the right hand in either
+direction. When the amount of the balance has been set to the combined
+weekly wage the treadle is released locking the two wheels together,
+when the whole can be turned and the amounts respectively due to each
+man read off opposite his weekly wage. The Smith-Davis Premium
+Calculator is on the same principle but the scales are about 4 feet 6
+inches long and the wheels spring-controlled. Both instruments are
+supplied by Messrs. John Davis & Son, Ltd., Derby.
+
+THE BAINES SLIDE RULE.—In this rule, invented by Mr. H. M. Baines,
+Lahore, four slides carrying scales are arranged to move, each in edge
+contact with the next. The slides are kept in contact and given the
+desired relative movement one to the other, by being attached (at the
+back), to a jointed parallelogram. On this principle which is of general
+application, the inventor has made a rule for the solution of problems
+covered by Flamant’s formula for the flow of water in cast-iron pipes:—V
+= 76·28_d_^{⁵⁄₇}_s_^{⁴⁄₇}, in which _s_ is the sine of the inclination
+or loss of head; _d_ the diameter of the pipe in inches and V the
+velocity in feet per second. The formula Q = AV is also included in the
+scope of the rule, Q being the discharge in cubic feet per second and A
+the cross sectional area of the pipe in square inches.
+
+FARMAR’S PROFIT-CALCULATING RULE.—The application of the slide rule to
+commercial calculations has been often attempted, but the degree of
+accuracy required necessitates the use of a long scale, and generally
+this results in a cumbersome instrument. In Farmar’s Profit-calculating
+Rule the money scale is arranged in ten sections, these being mounted in
+parallel form on a roller which takes the place of the upper scale of an
+ordinary rule. The roller, which is ¾in. in diameter, is carried in
+brackets secured to each end of the stock, so that by rotating the
+roller any section of the money scale can be brought into reading with
+the scale on the upper edge of the slide and with which the roller is in
+contact. This scale gives percentages, and enables calculations to be
+made showing profit on turnover, profit on cost, and discount. The lower
+scale on the slide, and that on the stock adjacent to it, are similar to
+the A and B scales of an ordinary rule. The instrument is supplied by
+Messrs. J. Casartelli & Son, Manchester.
+
+
+ CONSTRUCTIONAL IMPROVEMENTS IN SLIDE RULES.
+
+The attention of instrument makers is now being given to the devising of
+means for ensuring the smooth and even working of the slide in the stock
+of the rule. In some cases very good results are obtained by slitting
+the back of the stock to give more elasticity.
+
+In the rules made by Messrs. John Davis & Son, a metal strip, slightly
+curved in cross section as shown at A (Fig. 30), runs for the full
+length of the stock to which it is fastened at intervals. Near each end
+of the rule, openings about 1 in. long are made in the metal backing
+through which the scales on the back of the slide can be read. To
+prevent warping under varying climatic conditions both the stock of the
+rule and the slide are of composite construction. The base of the stock
+is of mahogany, while the grooved sides, firmly secured to the base, are
+of boxwood. Similarly the centre portion of the slide is of mahogany and
+the tongued sides of boxwood. Celluloid also enters into the
+construction, a strip of this material being laid along the bottom of
+the groove in the stock. A fine groove runs along the centre of this
+strip in order to give elasticity and to allow the sides of the stock to
+be pressed together slightly to adjust the fitting of the slide. As a
+further means of adjustment the makers fit metal clips at each end of
+the rule, so that by tightening two small screws the stock can be closed
+on the slide when necessary.
+
+[Illustration: FIG. 30.]
+
+[Illustration: FIG. 32.]
+
+[Illustration: FIG. 31.]
+
+In the rule made by the Keuffel and Esser Company of New York, one strip
+is made adjustable (Fig. 32).
+
+
+ THE ACCURACY OF SLIDE RULE RESULTS.
+
+The degree of accuracy obtainable with the slide rule depends primarily
+upon the length of the scale employed, but the accuracy of the
+graduations, the eyesight of the operator, and, in particular, his
+ability to estimate interpolated values, are all factors which affect
+the result. Using the lower scales and working carefully the error
+should not greatly exceed 0·15 per cent. with short calculations. With
+successive settings, the discrepancy need not necessarily be greater, as
+the errors may be neutralised; but with rapid working the percentage
+error may be doubled. However, much depends upon the graduation of the
+scales. Rules in which one or more of the indices have been thickened to
+conceal some slight inaccuracy should be avoided. The line on the cursor
+should be sharp and fine and both slide and cursor should move smoothly
+or good work cannot be done. Occasionally a little vaseline or clean
+tallow should be applied to the edges of the slide and cursor.
+
+That the percentage error is constant throughout the scale is seen by
+setting 1 on C to 1·01 on D, when under 2 is 2·02; under 3, 3·03; under
+5, 5·05, etc., the several readings showing a uniform error of 1 per
+cent.
+
+A method of obtaining a closer reading of a first setting or of a result
+on D has been suggested to the author by Mr. M. Ainslie, B.Sc. If any
+graduation, as 4 on C, is set to 3 on D, it is seen that 4 main
+divisions on C (40–44) are equal in scale length to 3 main divisions on
+D (30–33). Hence, very approximately, 1 division on C is equal to 0·75
+of a division on D, this ratio being shown, of course, on D under 10 on
+C. Suppose √(4·3) to be required. Setting the cursor to 4·3 on A, it is
+seen that the root is something more than 2·06. Move the slide until a
+main division is found on C, which exactly corresponds to the interval
+between 2 and the cursor line, on D. The division 27–28 just fits,
+giving a reading under 10 on C, of 74. Hence the root is read as 2·074.
+For the higher parts of the scale, the subdivisions, 1–1·1, etc., are
+used in place of main divisions. The method is probably more interesting
+than useful, since in most operations the inaccuracies introduced in
+making settings will impose a limit on the reliable figures of the
+result.
+
+For the majority of engineering calculations, the slide rule will give
+an accuracy consistent with the accuracy of the data usually available.
+For some purposes, however, _logarithmic section paper_ (the use of
+which the author has advocated for the last twenty years) will be found
+especially useful, more particularly in calculations involving
+exponential formulæ.
+
+
+
+
+ APPENDIX.
+
+
+ NEW SLIDE RULES—FIFTH ROOTS, ETC.—THE SOLUTION OF ALGEBRAIC
+ EQUATIONS—GAUGE POINTS AND SIGNS ON SLIDE RULES—TABLES AND DATA—SLIDE
+ RULE DATA SLIPS.
+
+THE PICKWORTH SLIDE RULE.—In this rule, made by Mr. A. W. Faber, the
+novel feature is the provision of a scale of cubes (F) in the stock or
+body of the rule. From Fig. 33 it will be seen that the scale is fixed
+on the bevelled side of a slotted recess in the back of the rule. The
+slide carries an index mark, which is seen through the slot and can be
+set to any graduation of the scale; in its normal position it agrees
+with 1 on the scale. The C scale on the face of the rule is divided into
+three equal parts by two special division lines, marked II. and III.,
+which, together with the initial graduation 1 of the scale, serve for
+setting or reading off values on the D scale. Similar division lines are
+marked on the D scale.
+
+[Illustration: FIG. 33.]
+
+In using the rule for cubes or cube roots the slide is drawn to the
+right, this movement never exceeding one-third of the length of the D
+scale. With this limited movement, and with a single setting of the
+slide, the values of ∛_̅a_, ∛(_a_ × 10), and ∛(_a_ × 100)) (_a_ being
+less than 10 and not less than 1) are given simultaneously and without
+any uncertainty as to the scales to use or the values to be read off.
+
+_To Find the Cube of a Number._—The marks II. and III. on D divide that
+scale into three equal sections. If the number to be cubed is in the
+first section, I. on C is set to it; if in the second section, II. on C
+is set to it; if in the third section, III. on C is set to it. Then,
+under the index mark on the back of the slide will be found the
+significant figures of the cube on the scale F. If I. on C was used for
+the setting, the cube contains 1 digit; if II. was used, 2 digits; if
+III. was used, 3 digits. If the first figure of the number to be cubed
+is not in the units place, the decimal point is moved through _n_ places
+so as to bring the first significant figure into the units place, the
+cube found as above, and the decimal point moved in the _reverse
+direction_ through 3_n_ places.
+
+_To Find the Cube Root of a Number._—The index mark is set to the
+significant figures of the number on scale F, and the cube root is read
+on D under I., II. or III. on C, according as the number has 1, 2 or 3
+digits preceding the decimal point. Numbers which have 1, 2 or 3 figures
+preceding the decimal point are dealt with directly. Numbers of any
+other form are brought to one of the above forms by moving the decimal
+point 3 places (or such multiple of 3 places as may be required), the
+root found and its decimal point moved 1 place for each 3-place
+movement, but in the _reverse direction_.
+
+THE “ELECTRO” SLIDE RULE.—In this special rule for electrical
+calculations, made by Mr. A. Nestler, the upper scales run from 0·1 to
+1000, and are marked “Amp.” and “sq. mm.” respectively. The lower scale
+on the slide running from 1 to 10,000 is marked M (metres), while the
+lower scale on the rule (0·1 to 100) is marked “Volt.” The latter scale
+is so displaced that 10 on M agrees with 0·173 on the Volt scale. The
+four factors involved are the current strength (in Amp.); the area of a
+conductor (in sq. mm.); the length of the conductor (in metres); and the
+permissible loss of potential (in volts). Having given any three of
+these, the fourth can be found very readily. On the back of the slide
+are a scale of squares, a scale of cubes and a single scale
+corresponding to the D scale of an ordinary rule. Hence, by reversing
+the slide, it is possible to obtain the 2nd, 3rd and 4th powers and
+roots of numbers. In another form of the rule, the scale of metres is
+replaced by one of yards, while instead of the area of the conductor in
+sq. mm., the corresponding “gauge” sizes of wires are given.
+
+THE “POLYPHASE” SLIDE RULE.—This instrument, made by the Keuffel & Esser
+Company, New York, has, in addition to the usual scales, a scale of
+cubes on the vertical edge of the stock of the rule, while in the centre
+of the slide there is a reversed C scale; _i.e._, a scale exactly
+similar to an ordinary C scale but with the graduations running from
+right to left. The rule is specially useful for the solution of problems
+containing combinations of three factors and problems involving squares,
+square roots, cubes, cube roots and many of the higher powers and roots.
+It is specially adapted for electrical and hydraulic work.
+
+THE LOG-LOG DUPLEX SLIDE RULE.—The same makers have introduced a log-log
+duplex slide rule, in which the log-log scale is in three sections,
+placed one above the other, these occupying the position usually taken
+up by the A scale. These scales are used in the manner already described
+(page 86), but some advantage is obtained by the manner in which the
+complete log-log scale is divided, the limits being _e_^{¹⁄₁₀₀} to _e_^⅒
+(on Scale L.L. 1); _e_^⅒ to _e_ (on Scale L.L. 2); and _e_ to _e_^{10}
+(on Scale L.L. 3), _e_ being the base of natural or hyperbolic
+logarithms (2·71828). In this way a total log-log range of from 1·01 to
+22,000 is provided, meeting all practical requirements. These log-log
+scales are read in conjunction with a C scale placed at the upper edge
+of the slide. A similar C scale, but reversed in direction, is placed at
+the lower edge of the slide, this having red figures to distinguish it
+readily. The adjacent scale on the body of the rule is an ordinary D
+scale, and under this is an equally-divided scale giving the common
+logarithms of values on D. In the centre of the slide is a scale of
+tangents.
+
+It will be understood that a “duplex” rule consists of two side strips
+securely clamped together at the two ends, forming the body of the rule,
+the slide moving between them; hence both front and back faces of the
+rule and slide are available, graduations on the one side being referred
+to those on the other by the cursor which extends around the whole. In
+this instrument, the scales on the back face are the ordinary scales of
+the standard rule with the addition of a scale of sines which is placed
+in the centre of the slide. It will be evident that this instrument is
+capable of dealing with a very wide range of problems involving
+exponential and trigonometrical formulæ.
+
+SMALL SLIDE RULES WITH MAGNIFYING CURSORS.—Several makers now supply 5
+in. rules having the full graduations of a 10 in. rule, and fitted with
+a magnifying cursor (Fig. 34). This forms a compact instrument for the
+pocket, but owing to the closeness of the graduations it is not usually
+possible to make a setting of the slide without using the cursor. This,
+of course, involves more movements than with the ordinary instrument. It
+is also very necessary to use the magnifying cursor in a _direct_ light,
+if accurate readings are to be obtained. If these slight inconveniences
+are to be tolerated, the principle could be extended, a 10 in. rule
+being marked as fully as a 20 in., and fitted with a magnifying cursor.
+The author has endeavoured, but without success, to induce makers to
+introduce such a rule.
+
+The magnifying cursor, supplied by Messrs. A. G. Thornton, Limited, has
+a lens which fills the entire cursor. It has a powerful magnifying
+effect, and the change from the natural to the magnified reading is less
+abrupt than with the semicircular lens.
+
+[Illustration: FIG. 34.]
+
+THE CHEMIST’S SLIDE RULE.—A slide rule, specially adapted for chemical
+calculations, has been introduced recently by Mr. A. Nestler. In this
+instrument the C and D scales are as usually arranged; but, in place of
+the A and B scales, there are a number of gauge points or marks denoting
+the atomic and molecular weights of the most important elements and
+combinations. The scales on the back of the slide are similarly
+arranged, so that by reversing the slide the operations can be extended
+very considerably. The rule finds its chief use in the calculation of
+analyses. Thus, to find the percentage of chlorine if _s_ grammes of a
+substance have been used and the precipitate of Ag.Cl. weighs _a_
+grammes, we have the equation, _x_ = (Cl.)/(Ag.Cl.) × (_a_)/(_s_).
+Hence, the mark Ag.Cl. on the upper scale of the slide is set to the
+mark Cl. on the upper scale of the rule, when under _a_ on the C scale
+is found the quantity of chlorine on D. By setting the cursor to this
+value and bringing _s_ on C to the cursor, the percentage required can
+be read on C over 10 on D.
+
+The rule is also adapted to the solution of various other chemical and
+electro-chemical calculations.
+
+THE STELFOX SLIDE RULE.—This rule, shown in Fig. 35, has a stock 5 in.
+long, fitted with a 10 in. slide jointed in the middle of its length by
+means of long dowels. By separating the parts the compactness of a 5 in.
+rule is obtained. The upper scales on the rule and slide resemble the
+usual A and B scales. The D scale on the lower part of the stock is in
+two sections, the second portion being placed below the first, as shown
+in the illustration. The centre scale on the slide corresponds to the
+usual C scale, while on the lower edge of the slide is a similar scale,
+but with the index (1) in the middle of its length. The arrangement
+avoids the necessity of resetting the slide, as is sometimes necessary
+with the ordinary rule, and in general it combines the accuracy of a 10
+in. rule with the compactness of a 5 in. rule; but a more frequent use
+of the cursor is necessary. This rule is made by Messrs. John Davis &
+Son, Limited, Derby.
+
+[Illustration: FIG. 35.]
+
+ELECTRICAL SLIDE RULE.—Another rule by the same makers, specially useful
+for electrical engineers, has the usual scales on the working edges of
+the rule and slide, while in the middle of the slide is placed a scale
+of cubes. A log-log scale in two sections is provided; the power
+portion, running from 1·07 to 2, is found on the lower part of the
+stock, and the upper portion, running from 2 to 10^3, on the upper part
+of the stock. The uppermost scale on the stock is in two parts, of which
+that to the left, running from 20 to 100 and marked “Dynamo,” gives the
+efficiencies of dynamos; that on the right, running from 20 to 100 and
+marked “Motor,” gives the efficiencies of electric motors. The lowest
+scale on the stock, marked “Volt,” gives the loss of potential in copper
+conductors. The ordinary upper scale on the stock is marked L (length of
+lead) at the left, and KW (kilowatts) at the right; the ordinary upper
+scale on the slide is marked A (ampères) and mm^2 (sectional area) at
+the left, and HP (horse-power) at the right. Additional lines on the
+cursor enable the electrical calculations to be made either in British
+or metric units.
+
+THE PICOLET CIRCULAR SLIDE RULE.—A simple form of circular calculator,
+made by Mr. L. E. Picolet of Philadelphia, is shown in Fig. 36. It
+consists of a base disc of stout celluloid on which turns a smaller disc
+of thin celluloid. A cursor formed of transparent celluloid is folded
+over the discs, and is attached so that the friction between the cursor
+and the inner disc enables the latter to be turned by moving the former.
+By holding both discs the cursor can be adjusted as required. The
+adjacent scales run in opposite directions, so that multiplication and
+division are performed as with the inverted slide in an ordinary rule.
+The outer scale, which is two-thirds the length of the main scale,
+enables cube roots to be found. Square roots are readily determined and
+continuous multiplication and division conveniently effected. Modified
+forms of this neatly made little instrument are also available.
+
+[Illustration: FIG. 36.]
+
+OTHER RECENT SLIDE RULES.—Among other special types of slide rule,
+mention should be made of the _Jakin_ 10 in. rule for surveyors, made by
+Messrs. John Davis & Son, Limited, Derby. By the provision of a series
+of short subsidiary scales, the multiplication of a sine or tangent of
+an angle by a number can be obtained to an accuracy of 1 in 10,000. The
+_Davis-Lee-Bottomley_ slide rule, by the same makers, has special scales
+provided for circle spacing. The division of a circle into a number of
+equal parts, often required in spacing rivets, bolts, etc., and in
+setting out the teeth of gearwheels, is readily effected by the aid of
+this instrument. The _Cuntz_ slide rule is a very comprehensive
+instrument, having a stock about 2¼ in. wide, with the slide near the
+lower edge. Above the slide are eleven scales, referable to the main
+scales by the cursor. These scales enable squares and square roots,
+cubes and cube roots, and areas and circumferences of circles to be
+obtained by direct reading. A much more compact instrument could be
+obtained by removing one-half the scales to the back of the rule and
+using a double cursor.
+
+[Illustration: FIG. 37.]
+
+In one form of 10 in. rule, supplied by Mr. W. H. Harling, London, the
+body of the rule is made of well-seasoned cane, with the usual celluloid
+facings. The rule has a metal back, enabling the fit of the slide to be
+regulated. This backing extends the full length of the rule, openings
+about 1 in. long being provided at each end, enabling the scales on the
+back of the slide to be set with greater facility than is possible with
+the notched recesses usually adopted. The author has long endeavoured,
+but without success, to induce makers to fit windows of glass or
+celluloid in place of the notched recesses. This would allow the
+graduation of the S and T scales to be set more accurately, and enable
+both to be used at each end of the rule—an advantage in certain
+trigonometrical calculations. It would have the further advantage of
+permitting each alternate graduation of the evenly-divided or logarithm
+scale to be placed at opposite sides of one central line, enabling the
+reading to be made more accurately and conveniently.
+
+Many special slide rules have lately been devised for determining the
+time necessary to perform various machine-tool operations and for
+analogous purposes, while attention has again been given to rules for
+calculating the weights of iron and steel bars, plates, etc.
+
+THE DAVIS-STOKES FIELD GUNNERY SLIDE RULE.—This rule, which is adapted
+for calculations involved in “encounter” and “entrenched” field gunnery,
+is designed for the 18 pr. quick-firing gun. The upper and lower
+portions of the boxwood stock are united by a flexible centre of
+celluloid, thus providing grooves front and rear to receive boxwood
+slides. Each of the nineteen scales is marked with its name, and
+corresponding scales are coloured red or black. The front edge is
+bevelled and carries a scale of 1 in 20,000. The rule solves
+displacement problems, map angles of sight, changes of corrector and
+range corrections for changes in temperature, wind and barometer, etc. A
+special feature for displacement calculations is the provision of a 50
+yd. sub-base angle scale, by which the apex angle is read at one
+setting.
+
+THE DAVIS-MARTIN WIRELESS SLIDE RULE.—In wireless telegraphy it is
+frequently necessary to determine wave-length, capacity or
+self-induction when one or other of the factors of the equation, λ =
+59·6√(LC) is unknown. The Davis-Martin wireless rule is designed to
+simplify such calculations. The upper scale in the stock (inductance)
+runs from 10,000 to 1,000,000; the adjacent scale on the slide
+(capacity) runs from 0·0001 to 0·01 but in the reverse direction. The
+lower scale on the stock (wave-length) runs from 100 to 1000, giving
+square roots of the upper scale; while on the lower edge of the scale
+are several arrows to suit the various denominations in which the
+wave-length and capacity may be expressed.
+
+IMPROVED CURSORS.—In some slide-rule operations, notably in those
+involved in solving quadratic and cubic equations, it not infrequently
+happens that readings are obscured by the frame of the cursor. Frameless
+cursors have been introduced to obviate this defect. A piece of thick
+transparent celluloid is sometimes employed, but this is liable to
+become scratched in use. Fig. 37 shows a recent form of frameless glass
+cursor made by the Keuffel & Esser Company, Hoboken, N.J., which is
+satisfactory in every way.
+
+Cursors having three hair lines are now fitted to some rules, the
+distance apart of the lines being equal to the interval 0·7854–1 on the
+A scale.
+
+THE DAVIS-PLETTS SLIDE RULE.—In this rule a single log.-log. scale and
+its reciprocal scale are arranged opposite the ordinary upper log.
+scale. Thus, common logarithms can be read directly, while by taking
+advantage of the properties of characteristics and mantissas of common
+logarithms, the scale can be extended indefinitely. As 10 is the highest
+number on the log.-log. scale, it is carried down to within 0·025 of
+unity. The reading of log.-log. values above 10 is effected in a very
+simple manner. There is also a scale in the centre of the slide which,
+used in conjunction with the upper log. scale enables the natural
+logarithm of any number between 0·0001 and 10,000 to be read direct,
+while any number on the upper log. scale can be multiplied or divided by
+_e^x_ if the latter is between these limits. On the back of the slide
+are scales for all circular and hyperbolic functions, these being used
+in conjunction with the upper log. scales.
+
+THE CROMPTON-GALLAGHER BOILER EFFICIENCY CALCULATOR has a stock in the
+thickness of which is a slot admitting a chart which can be moved at
+right angles to the two separate slides. On the bevelled edge of one
+slide, the graduations are continued so as to read against curves on the
+chart, through an opening in the stock.
+
+THE DAVIS-GRINSTED COMPLEX CALCULATOR.—This slide rule is of
+considerable service in connection with calculations involving the
+conversion of complex quantities from the form _a_ + _j_ _b_ to the form
+R∠θ, and _vice versa_. The usual process of conversion necessitates
+repeated reference to trigonometrical tables, and is both tedious and
+time-taking. The Complex Calculator enables the conversions to be
+effected without reference to tables and with the minimum expenditure of
+time and labour.
+
+The rule, which is about 16 in. long, has five scales. The upper one (A)
+is an ordinary logarithmic scale thrice-repeated. The adjacent scales on
+the slide comprise (1) a logarithmic scale of tangents (B) ranging from
+0·1° to 45°, and (2) a logarithmic scale of secants (C) from 0° to 45°.
+The lower scales D and E are identical with the A scale, and are
+provided to enable multiplication, etc., to be performed without the
+need for a separate slide rule. Readings can be transferred from A to
+the lower scales by means of the cursor.
+
+In using the rule to convert _a_ + _j_ _b_ to R∠θ, the index (45°) of
+the B scale is set to the larger component and the cursor to the smaller
+component, on scale A. Then θ (or its complement if _b_ is greater than
+_a_) is read on B under the cursor. The cursor is then set to θ on the C
+scale, and R is read on A under the cursor. The rule is made by Messrs.
+John Davis & Son, Limited, Derby.
+
+
+ THE SOLUTION OF ALGEBRAIC EQUATIONS.
+
+The slide rule finds an interesting application in the solution of
+equations of the second and third degree; and although the process is
+essentially one of trial and error, it may often serve as an efficient
+substitute for the more laborious algebraic methods, particularly when
+the conditions of the problem or the operator’s knowledge of the theory
+of equations enables some idea to be obtained as to the character of the
+result sought. The principle may be thus briefly explained:—If 1 on C is
+set to _x_ on D (Fig. 38), we find _x_(_x_) = _x_^2 on D under _x_ on C.
+If, however, with the slide set as before, instead of reading under _x_,
+we read under _x_ + _m_ on C, the result on D will now be _x_(_x_ + _m_)
+= _x_^2 + _mx_ = _q_. Hence to solve the equation _x_^2 + _mx_ − _q_ =
+0, we reverse the above process, and setting the cursor to _q_ on D, we
+move the slide until the number on C under the cursor, and that on D
+under 1 on C, _differ by m_. It is obvious from the setting that the
+_product_ of these numbers = _q_, and as their difference = _m_, they
+are seen to be the roots of the equation as required. For the equation
+_x_^2 − _mx_ + _q_ = 0, we require _m_ to equal the _sum_ of the roots.
+Hence, setting the cursor as before to _q_ on D, we move the slide until
+the number on C under the cursor, and that on D under 1 on C, are
+_together equal to_ _m_, these numbers being the roots sought. The
+alternative equations _x_^2 − _mx_ − _q_ = 0, and _x_^2 + _mx_ + _q_ = 0
+are deducible from the others by changing the signs of the roots, and
+need not be further considered.
+
+[Illustration: FIG. 38.]
+
+
+ EX.—Find the roots of _x_^2 − 8_x_ + 9 = 0.
+
+ Set the cursor to 9 on D, and move the slide to the right until when
+ 6·64 is found under the cursor, 1·355 on D is under 1 on C. These
+ numbers are the roots required.
+
+
+The upper scales can of course be used; indeed, in general they are to
+be preferred.
+
+
+ EX.—Find the roots of _x_^2 + 12·8_x_ + 39·4 = 0.
+
+ Set the cursor to 39·4 on A, and move the slide to the right until we
+ read 7·65 on B under the cursor, and 5·15 on A over 1 on B. The roots
+ are therefore −7·65 and −5.15.
+
+
+With a little consideration of the relative value of the upper and lower
+scales, the student interested will readily perceive how equations of
+the third degree may be similarly resolved. The subject is not of
+sufficient general importance to warrant a detailed examination being
+made of the several expressions which can be dealt with in the manner
+suggested; but the author gives the following example as affording some
+indication of the adaptability of the method to practical calculations.
+
+
+ EX.—A hollow copper ball, 7·5 in. in diameter and 2 lb. in weight,
+ floats in water. To what depth will it sink?
+
+ The water displaced = 27·7 × 2 = 55·4 cub. in. The cubic contents of
+ the immersed segment will be (π)/(3)(3_r_ _x_^2 − _x_^3), _r_ being
+ the radius and _x_ the depth of immersion. Hence (π)/(3)(3_r_ _x_^2 −
+ _x_^3) = 55·4, and 11·25_x_^2 − _x_^3 = 52·9.
+
+ To solve this equation we place the cursor to 52·9 on A, and move the
+ slide until the reading on D under 1 and that on B under the cursor
+ together amount to 11·25. In this way find 2·45 on D under 1, with 8·8
+ on B under the cursor _c_, _c_, as a pair of values of which the sum
+ is 11·25. Hence we conclude that _x_ = 2·45 in. is the result sought.
+
+ With the rule thus set (Fig. 39) the student will note that the slide
+ is displaced to the right by an amount which represents _x_ on D, and
+ therefore _x_^2 on A; while the length on B from 1 to the cursor line
+ represents 11·25 − _x_. Hence the upper scale setting gives
+ _x_^2(11·25 − _x_) = 11·25_x_^2 − _x_^3 = 52·9 as required.
+
+
+[Illustration: FIG. 39.]
+
+When in doubt as to the method to be pursued in any given case, the
+student should work synthetically, building up a simple example of an
+analogous character to that under consideration, and so deducing the
+plan to be followed in the reverse process.
+
+
+ SCREW-CUTTING GEAR CALCULATIONS.
+
+The slide rule has long found a useful application in connection with
+the gear calculations necessary in screw-cutting, helical gear-cutting,
+and spiral gear work.
+
+SINGLE GEARS.—For simple cases of screw-cutting in the lathe it is only
+necessary to set the threads per inch to be cut to the threads per inch
+in the guide screw (or the pitch in inches in each case, if more
+convenient). Then any pair of coinciding values on the two scales will
+give possible pairs of wheels.
+
+
+ EX.—Find wheels to cut a screw of 1⅝ threads per inch with a guide
+ screw of 2 threads per inch.
+
+ Setting 1·625 on C to 2 on D, it is seen that 80 (driver) and 65
+ (driven) are possible wheels.
+
+
+COMPOUND GEARS.—When wheels so found are of inconvenient size, a
+compound train is used, consisting (usually) of two drivers and two
+driven wheels, the product of the two former and the product of the two
+latter being in the same ratio as the simple wheels. Thus with 60 and 40
+as drivers, and 65 and 30 as driven, we have, (60 × 40)/(65 × 30) =
+(2400)/(1950) = (2)/(1·625) as before.
+
+With the slide set as above, values convenient for splitting up into
+suitable wheels are readily obtainable. Thus, (1600)/(1300);
+(2400)/(1950); (4000)/(3250); (4800)/(3900) are a few suggestive values
+which may be readily factorised.
+
+SLIDE RULES FOR SCREW-CUTTING CALCULATIONS.—Special circular and
+straight slide rules for screw-cutting gear calculations have long been
+employed. For compound gears these usually entail the use of six scales,
+two on each of the two slides and two on the stock. The upper scale on
+the stock may be a scale of threads per inch to be cut, the adjacent
+scale (on the upper slide) a scale of threads per inch in the guide
+screw. Setting the guide screw-graduation to the threads to be cut, the
+lower slide is adjusted until a convenient pair of drivers is found in
+coincidence on the central pair of scales, while a pair of driven wheels
+are in coincidence on the two lower scales.
+
+Some years ago, a slide rule was introduced by which compound gears
+could be obtained with a single slide. Assuming the set of wheels
+usually provided—20 to 120 teeth advancing by 5 teeth—the products of 20
+× 25, 20 × 30, etc., up to 115 × 120 were calculated. These products
+were laid out along each of the two lower scales. The upper scales were
+a scale of threads per inch to be cut and a scale of the threads per
+inch of various guide screws. Setting the guide screw-graduation to the
+threads to be cut, any coinciding graduations on the lower scales gave
+the required pairs of drivers and driven wheels.
+
+FRACTIONAL PITCH CALCULATIONS.—The author has long advocated the use of
+the slide rule for determining the wheels necessary for cutting
+fractional pitch threads, and it is gratifying to find its value in this
+connection is now being appreciated. For the best results a good 20 in.
+rule is desirable, but with care very close approximations can be found
+with an accurate 10 in. rule. In any case a magnifying cursor or a hand
+reading-glass is of great assistance.
+
+
+ EX.—Find wheels to cut a thread of 0·70909 in. pitch; guide screw, 2
+ threads per inch.
+
+ To 0·70909 on D, set 0·5 (guide screw pitch in inches) on C. To make
+ this setting as accurately as possible, the method described on page
+ 112 may be used. Set 10 on C to about 91 on D, and note that the
+ interval 77–78 on C represents 0·91 of the interval 70–71 on D. Set
+ the cursor to 78 on C and bring 5 to the cursor. The slide is then set
+ so that 5 on C agrees with 7·091 on D.
+
+
+Inspection of the two scales shows various coinciding factors in the
+ratio required. The most accurate is seen to be (55 on C)/(78 on D).
+These values may be split up into (55 × 50)/(65 × 60) to form a suitable
+compound train of gears.
+
+
+ GAUGE POINTS AND SIGNS ON SLIDE RULES.
+
+Many slide rules have the sign (Prod.)/(−1) at the right-hand end of the
+D scale, while on the left is (Quot.)/(+1.) It is somewhat unfortunate
+that these signs refer to rules for determining the number of digits in
+products and quotients, which are used to a considerable extent on the
+Continent, and conflict with those used in this country. By the
+Continental method the number of digits in a product is equal to the sum
+of the digits in the two factors, if the result is obtained on the LEFT
+_of the first factor_; but if the result is found on the RIGHT of the
+first factor, it is equal to this sum − 1. The sign (Prod.)/(−1) the
+_right_-hand end of the D scale provides a visible reminder of this
+rule.
+
+Similarly for division:—The number of digits in a quotient is equal to
+the number of the digits in the dividend, minus those in the divisor, if
+the quotient appears on the RIGHT _of the dividend_, and to this
+difference + 1, if the quotient appears on the LEFT of the dividend. The
+sign (Quot.)/(+1) at the _left_-hand end of the D scale provides a
+visible reminder of this rule.
+
+The sign
+
+ +ⵏ–
+ ⟵ⵏ⟶
+ –ⵏ+
+
+found at both ends of the A scale is of general application but of
+questionable utility. It is assumed to represent a fraction, the
+vertical line indicating the position of the decimal point. If the
+number 455 is to be dealt with in a multiplication on the lower scales,
+we may suppose the decimal point moved two places to the left, giving
+4·55, a value which can be actually found on the scale. If we use this
+value, then to the number of digits in this result, as many must be
+added as the number of places (two in this case) by which the decimal
+point was moved. If the point is moved to the right, the number of
+places must be subtracted. Similarly, in division, if the decimal point
+in the divisor is moved _n_ places to the left, then _n_ places must be
+subtracted at the end of the operation; while if the point is moved
+through _n_ places to the right, then _n_ places must be added. The sign
+referred to, which, of course, applies to all scales, completely
+indicates these processes and is submitted as a reminder of the
+procedure to be followed by those using the method described.
+
+The signs π, _c_, _c′_, and M are explained in the Section on “Gauge
+Points,” p. 53.
+
+On some rules additional signs are found on the D scale. One, locating
+the value (180 × 60)/(π) = 3437·74 and hence giving the number of
+minutes in a radian, is marked ρ′. Another, representing the value (180
+× 60 × 60)/(π) = 206265, and hence giving the number of seconds in a
+radian is marked ρ″. A third point, marked ρ_{˶}, placed at the value
+(200 × 100 × 100)/(π) = 636620, is used when the newer graduation of the
+circle is employed.
+
+These gauge points are useful when converting angles into circular
+measure, or _vice versa_, and also for determining the functions of
+small angles.
+
+A gauge point is sometimes marked at 1146 on the A and B scales. This is
+known as the “Gunner’s Mark,” and is used in artillery calculations
+involving angles of less than 20°, when, for the purpose in view, the
+tangent and circular measure of the angle may be regarded as equal. For
+this constant, the angle is taken in minutes, the auxiliary base in
+feet, and the base in yards. The auxiliary base in feet on B is set to
+the angle in minutes on A when over 1146 on B is the base in yards on A.
+The value (1)/(1146) = (π × 3)/(180 × 60).
+
+
+ TABLES AND DATA.
+
+
+ MENSURATION FORMULAE.
+
+
+ Area of a parallelogram = base × height.
+
+ Area of rhombus = ½ product of the diagonals.
+
+ Area of a triangle = ½ base × perpendicular height.
+
+ Area of equilateral triangle = square of side × 0·433.
+
+ Area of trapezium = ½ sum of two parallel sides × height.
+
+ Area of any right-lined figure of four or more unequal sides is found
+ by dividing it into triangles, finding area of each and adding
+ together.
+
+ Area of regular polygon = (1) length of one side × number of sides ×
+ radius of inscribed circle; or (2) the sum of the triangular areas
+ into which the figures may be divided.
+
+ Circumference of a circle = diameter × 3·1416.
+
+ Circumference of circle circumscribing a square = side × 4·443.
+
+ Circumference of circle = side of equal square × 3·545.
+
+ Length of arc of circle = radius × degrees in arc × 0·01745.
+
+ Area of a circle = square of diameter × 0·7854.
+
+ Area of sector of a circle = length of arc × ½ radius.
+
+ Area of segment of a circle = area of sector − area of triangle.
+
+ Side of square of area equal to a circle = diameter × 0·8862.
+
+ Diameter of circle equal in area to square = side of square × 1·1284.
+
+ Side of square inscribed in circle = diameter of circle × 0·707.
+
+ Diameter of circle circumscribing a square = side of square × 1·414.
+
+ Area of square = area of inscribed circle × 1·2732.
+
+ Area of circle circumscribing square = square of side × 1·5708.
+
+ Area of square = area of circumscribing circle × 0·6366.
+
+ Area of a parabola = base x ⅔ height.
+
+ Area of an ellipse = major axis × minor axis × 0·7854.
+
+ Surface of prism or cylinder = (area of two ends) + (length ×
+ perimeter).
+
+ Volume of prism or cylinder = area of base × height.
+
+ Surface of pyramid or cone = ½(slant height × perimeter of base) +
+ area of base.
+
+ Volume of pyramid or cone = (⅓)(area of base × perpendicular height).
+
+ Surface of sphere = square of diameter × 3·1416.
+
+ Volume of sphere = cube of diameter × 0·5236.
+
+ Volume of hexagonal prism = square of side × 2·598 × height.
+
+ Volume of paraboloid = ½ volume of circumscribing cylinder.
+
+ Volume of ring (circular section) = mean diameter of ring × 2·47 ×
+ square of diameter of section.
+
+
+ SPECIFIC GRAVITY AND WEIGHT OF MATERIALS.
+
+ METALS.
+ ─────────────────────┬───────────────┬───────────────┬───────────────
+ METAL. │ Specific │ Weight of 1 │ Weight of 1
+ │ Gravity. │Cub. Ft. (Lb.).│Cub. In. (Lb.).
+ ─────────────────────┼───────────────┼───────────────┼───────────────
+ Aluminium, Cast │ 2·56│ 160│ 0·0927
+ Aluminium, Bronze │ 7·68│ 475│ 0·275
+ Antimony │ 6·71│ 418│ 0·242
+ Bismuth │ 9·90│ 617│ 0·357
+ Brass, Cast │ 8·10│ 505│ 0·293
+ „ Wire │ 8·548│ 533│ 0·309
+ Copper, Sheet │ 8·805│ 549│ 0·318
+ „ Wire │ 8·880│ 554│ 0·321
+ Gold │ 19·245│ 1200│ 0·695
+ Gun metal │ 8·56│ 534│ 0·310
+ Iron, Wrought (mean) │ 7·698│ 480│ 0·278
+ „ Cast (mean) │ 7·217│ 450│ 0·261
+ Lead, Milled Sheet │ 11·418│ 712│ 0·412
+ Manganese │ 8·012│ 499│ 0·289
+ Mercury │ 13·596│ 849│ 0·491
+ Nickel, Cast │ 8·28│ 516│ 0·300
+ Phosphor Bronze, Cast│ 8·60│ 536·8│ 0·310
+ Platinum │ 21·522│ 1342│ 0·778
+ Silver │ 10·505│ 655│ 0·380
+ Steel (mean) │ 7·852│ 489·6│ 0·283
+ Tin │ 7·409│ 462│ 0·268
+ Zinc, Sheet │ 7·20│ 449│ 0·260
+ „ Cast │ 6·86│ 428│ 0·248
+ ─────────────────────┴───────────────┴───────────────┴───────────────
+
+ MISCELLANEOUS SUBSTANCES.
+ ────────────┬──────────┬──────────
+ SUBSTANCE. │ Specific │Weight of
+ │ Gravity. │1 Cub. In.
+ │ │ (Lb.).
+ ────────────┼──────────┼──────────
+ Asbestos │ 2·1–2·80 │·076-·101
+ Brick │ 1·90 │ ·069
+ Cement │2·72–3·05 │·0984-·109
+ Clay │ 2·0 │ ·072
+ Coal │ 1·37 │ ·0495
+ Coke │ 0·5 │ ·0181
+ Concrete │ 2·0 │ ·072
+ Fire-brick │ 2·30 │ ·083
+ Granite │ 2·5–2·75 │·051-·100
+ Graphite │ 1·8–2·35 │·065-·085
+ Sand-stone │ 2·3 │ ·083
+ Slate │ 2·8 │ ·102
+ Wood— │ │
+ Beech │ 0·75 │ ·0271
+ Cork │ 0·24 │ ·0087
+ Elm │ 0·58 │ ·021
+ Fir │ 0·56 │ ·0203
+ Oak │ ·62-·85 │·025-·031
+ Pine │ 0·47 │ ·017
+ Teak │ 0·80 │ ·029
+ ────────────┴──────────┴──────────
+
+ ULTIMATE STRENGTH OE MATERIALS.
+ ──────────────────┬────────────┬────────────┬────────────┬────────────
+ MATERIAL. │ Tension in │Compression │Shearing in │ Modulus of
+ │lb. per sq. │ in lb. per │lb. per sq. │ Elasticity
+ │ in. │ sq. in. │ in. │ in lb. per
+ │ │ │ │ sq. in.
+ ──────────────────┼────────────┼────────────┼────────────┼────────────
+ Cast Iron │ 11,000 to│ 50,000 to│ │ 14,000,000
+ │ 30,000│ 130,000│ │ to
+ │ │ │ │ 23,000,000
+ „ aver.│ 16,000│ 95,000│ 11,000│
+ Wrought Iron │ 40,000 to│ │ │ 26,000,000
+ │ 70,000│ │ │ to
+ │ │ │ │ 31,000,000
+ „ aver.│ 50,000│ 50,000│ 40,000│
+ Soft Steel │ 60,000 to│ │ │ 30,000,000
+ │ 100,000│ │ │ to
+ │ │ │ │ 36,000,000
+ Soft Steel aver.│ 80,000│ 70,000│ 55,000│
+ Cast Steel aver.│ 120,000│ │ │ 15,000,000
+ │ │ │ │ to
+ │ │ │ │ 17,000,000
+ Copper, Cast │ 19,000│ 58,000│ │
+ „ Wrought │ 34,000│ │ │ 16,000,000
+ Brass, Cast │ 18,000│ 10,500│ │ 9,170,000
+ Gun Metal │ 34,000│ │ │ 11,500,000
+ Phosphor Bronze │ 58,000│ │ 43,000│ 13,500,000
+ Wood, Ash │ 17,000│ 9,300│ 1,400│
+ „ Beech │ 16,000│ 8,500│ │
+ „ Pine │ 11,000│ 6,000│ 650│ 1,400,000
+ „ Oak │ 15,000│ 10,000│ 2,300│ 1,500,000
+ Leather │ 4,200│ │ │ 25,000
+ ──────────────────┴────────────┴────────────┴────────────┴────────────
+
+ POWERS, ROOTS, ETC., OF USEFUL FACTORS.
+ _n_ │(1)/(_n_)│ _n_^2 │ _n_^3 │ √_̅n_ │ (1)/(√_̅n_) │ ∛_̅n_ │ (1)/(∛_̅n_)
+ ────────────────┼─────────┼───────┼──────────┼──────┬┴───────────┬─┴────┬──┴─────────
+ π = 3·142 │ 0·318│ 9·870│ 31·006│ 1·772│ 0·564│ 1·465│ 0·683
+ 2π= 6·283 │ 0·159│ 39·478│ 248·050│ 2·507│ 0·399│ 1·845│ 0·542
+ (π)/(2) = 1·571 │ 0·637│ 2·467│ 3·878│ 1·253│ 0·798│ 1·162│ 0·860
+ (π)/(3) = 1·047 │ 0·955│ 1·097│ 1·148│ 1·023│ 0·977│ 1·016│ 0·985
+ (4)/(3)π = 4·189│ 0·239│ 17·546│ 73·496│ 2·047│ 0·489│ 1·612│ 0·622
+ (π)/(4) = 0·785 │ 1·274│ 0·617│ 0·484│ 0·886│ 1·128│ 0·923│ 1·084
+ (π)/(6) = 0·524 │ 1·910│ 0·274│ 0·144│ 0·724│ 1·382│ 0·806│ 1·241
+ π^2 = 9·870 │ 0·101│ 97·409│ 961·390│ 3·142│ 0·318│ 2·145│ 0·466
+ π^3 = 31·006 │ 0·032│961·390│29,809·910│ 5·568│ 1·796│ 3·142│ 0·318
+ (π)/(32) = 0·098│ 10·186│ 0·0095│ 0·001│ 0·313│ 3·192│ 0·461│ 2·168
+ _g_ = 32·2 │ 0·031│1036·84│ 33,386·24│ 5·674│ 0·176│ 3·181│ 0·314
+ 2_g_ = 64·4 │ 0·015│4147·36│ 267,090│ 8·025│ 0·125│ 4·007│ 0·249
+ ────────────────┴─────────┴───────┴──────────┴──────┴────────────┴──────┴────────────
+
+
+ HYDRAULIC EQUIVALENTS.
+
+ 1 foot head = 0·434 lb. per square inch.
+ 1 lb. per square inch = 2·31 ft. head.
+ 1 imperial gallon = 277·274 cubic inches.
+ 1 imperial gallon = 0·16045 cubic foot.
+ 1 imperial gallon = 10 lb.
+ 1 cubic foot of water = 62·32 lb. = 6·232 imperial gallons.
+ 1 cubic foot of sea water = 64·00 lb.
+ 1 cubic inch of water = 0·03616 lb.
+ 1 cubic inch of sea water = 0·037037 lb.
+ 1 cylindrical foot of water = 48·96 lb.
+ 1 cylindrical inch of water = 0·0284 lb.
+ A column of water 12 in. long 1 in. square = 0·434 lb.
+ A column of water 12 in. long 1 in. diameter = 0·340 lb.
+ Capacity of a 12 in. cube = 6·232 gallons.
+ Capacity of a 1 in. square 1 ft. long = 0·0434 gallon.
+ Capacity of a 1 ft. diameter 1 ft. long = 4·896 gallons.
+ Capacity of a cylinder 1 in. diameter 1 ft. long = 0·034 gallon.
+ Capacity of a cylindrical inch = 0·002832 gallon.
+ Capacity of a cubic inch = 0·003606 gallon.
+ Capacity of a sphere 12 in. diameter = 3·263 gallons.
+ Capacity of a sphere 1 in. diameter = 0·00188 gallon.
+ 1 imperial gallon = 1·2 United States gallon.
+ 1 imperial gallon = 4·543 litres of water.
+ 1 United States gallon = 231·0 cubic inches.
+ 1 United States gallon = 0·83 imperial gallon.
+ 1 United States gallon = 3·8 litres of water.
+ 1 cubic foot of water = 7·476 United States gallons.
+ 1 cubic foot of water = 28·375 litres of water.
+ 1 litre of water = 0·22 imperial gallon.
+ 1 litre of water = 0·264 United States gallon.
+ 1 litre of water = 61·0 cubic inches.
+ 1 litre of water = 0·0353 cubic foot.
+
+ ─────────────────────────────────────────────────────────────────────────
+ EQUIVALENTS OF POUNDS AVOIRDUPOIS.
+ ─┬───────┬────────────┬────────────────┬────────────────┬────────────────
+ │ 10 │ 100 │ 1000 │ 10,000 │ 100,000
+ ─┼───────┼────────────┼────────────────┼────────────────┼────────────────
+ │qr. lb.│cwt. qr. lb.│ton cwt. qr. lb.│ton cwt. qr. lb.│ton cwt. qr. lb.
+ 1│ 0 10│ 0 3 16│ 0 8 3 20│ 4 9 1 4│ 44 12 3 12
+ 2│ 0 20│ 1 3 4│ 0 17 3 12│ 8 18 2 8│ 89 5 2 24
+ 3│ 1 2│ 2 2 20│ 1 6 3 4│ 13 7 3 12│133 18 2 8
+ 4│ 1 12│ 3 2 8│ 1 15 2 24│ 17 17 0 16│178 11 1 20
+ 5│ 1 22│ 4 1 24│ 2 4 2 16│ 22 6 1 20│223 4 1 4
+ 6│ 2 4│ 5 1 12│ 2 13 2 8│ 26 15 2 24│267 17 0 16
+ 7│ 2 14│ 6 1 0│ 3 2 2 0│ 31 5 0 0│312 10 0 0
+ 8│ 2 24│ 7 0 16│ 3 11 1 20│ 35 14 1 4│357 2 3 12
+ 9│ 3 6│ 8 0 4│ 4 0 1 12│ 40 3 2 8│401 15 2 24
+ ─┴───────┴────────────┴────────────────┴────────────────┴────────────────
+
+
+ TRIGONOMETRICAL FUNCTIONS.
+
+
+ RIGHT-ANGLED TRIANGLES.
+
+[Illustration: [Right-angled Triangle]]
+
+Sin. A = (_a_)/(_b_) Sec. A = (_b_)/(_c_) Tan. A = (_a_)/(_c_)
+
+Cos. A = (_c_)/(_b_) Cosec. A = (_b_)/(_a_) Cotan. A = (_c_)/(_a_)
+
+Versin. A = (_b_ − _c_)/(_b_). Coversin. A = (_b_ − _a_)/(_b_).
+
+ ───────┬─────────┬─────────────────────────────────────────────────────
+ Given. │Required.│ Formulæ.
+ ───────┼─────────┼─────────────────────────────────────────────────────
+ _a_,_b_│ A,C,_c_ │Sin. A = (_a_)/(_b_) Cos. C = (_a_)/(_b_) _c_ =
+ │ │ √((_b + a_)(_b − a_))
+ │ │
+ _a_,_c_│ A,C,_b_ │Tan. A = (_a_)/(_c_) Cotan. B = (_a_)/(_c_) _b_ =
+ │ │ √(_a_^2 + _c_^2)
+ │ │
+ A,_a_ │C,_c_,_b_│ C = 90° − A _c_ = _a_ × Cotan. A _b_ =
+ │ │ (_a_)/(Sin. A)
+ │ │
+ A,_b_ │C,_a_,_c_│C = 90° − A _a_ = _b_ × Sin. A _c_ = _b_ × Cos.
+ │ │ A
+ │ │
+ A,_c_ │C,_a_,_b_│ C = 90° − A _a_ = _c_ × Tan. A _b_ =
+ │ │ (_c_)/(Cos. A)
+ │ │
+ ───────┴─────────┴─────────────────────────────────────────────────────
+
+
+ OBLIQUE-ANGLED TRIANGLES.
+
+_s_ = ½(_a + b + c_)
+
+[Illustration: [Oblique-angled Triangle]]
+
+ ───────────┬─────────┬─────────────────────────────────────────────────
+ Given. │ │ Formulæ.
+ ───────────┼─────────┼─────────────────────────────────────────────────
+ A,B,C,_a_ │ Area= │(_a_^2 × Sin. B × Sin. C) ÷ 2 Sin. A
+ A,_b_,_c_ │ „ │½(_c_ × _b_ × Sin. A)
+ _a_,_b_,_c_│ „ │√(_s_(_s_ − _a_)(_s_ − _b_)(_s_ − _c_))
+ ───────────┼─────────┼─────────────────────────────────────────────────
+ Given. │Required.│ Formulæ.
+ ───────────┼─────────┼─────────────────────────────────────────────────
+ A,C,_a_ │ _c_ │ _c_ = _a_(Sin. C)/(Sin. A)
+ ───────────┼─────────┼─────────────────────────────────────────────────
+ A,_a_,_c_ │ C │ Sin. C = (_c_ Sin. A)/(_a_)
+ ───────────┼─────────┼─────────────────────────────────────────────────
+ _a_,_c_,B │ A │ Tan. A = (_a_ Sin. B)/(_c_ − _a_ Cos. B)
+ ───────────┼─────────┼─────────────────────────────────────────────────
+ _a_,_b_,_c_│ A │Sin. ½A = √(((_s_ − _b_)(_s_ − _c_))/(_b_ × _c_))
+ „ │ „ │ Cos. ½A = √((_s_(_s_ − _a_))/(_b_ × _c_));
+ „ │ „ │ Tan. ½A = √(((_s_ − _b_)(_s_ − _c_))/(_s_(_s_ −
+ │ │ _a_)))
+ ───────────┴─────────┴─────────────────────────────────────────────────
+
+
+ COMPOUND ANGLES.
+
+ Sin. (A + B) = Sin. A Cos. B + Cos. A Sin. B.
+ Sin. (A − B) = Sin. A Cos. B − Cos. A Sin. B.
+ Cos. (A + B) = Cos. A Cos. B − Sin. A Sin. B.
+ Cos. (A − B) = Cos. A Cos. B + Sin. A Sin. B.
+
+Tan. (A + B) = (Tan. A + Tan. B)/(1 − Tan. A Tan. B).
+
+Tan. (A − B) = (Tan. A − Tan. B)/(1 + Tan. A Tan. B).
+
+
+ SLIDE RULE DATA SLIPS, COMPILED BY C. N. PICKWORTH, WH.SC.
+
+ (_It is suggested that this page be removed by cutting through the above
+ line, and selected portions of the Sectional Data Slips attached to the
+ back of the Slide Rule._)
+
+ ¹⁄₃₂ │0·03125
+ ¹⁄₁₆ │0·0625
+ ³⁄₃₂ │0·09375
+ ⅛ │0·125
+ ⁵⁄₃₂ │0·15625
+ ³⁄₁₆ │0·1875
+ ⁷⁄₃₂ │0·21875
+ ¼ │0·25
+ ⁹⁄₃₂ │0·28125
+ ⁵⁄₁₆ │0·3125
+ ¹¹⁄₃₂ │0·34375
+ ⅜ │0·375
+ ¹³⁄₃₂ │0·40625
+ ⁷⁄₁₆ │0·4375
+ ¹⁵⁄₃₂ │0·46875
+ ¹⁷⁄₃₂ │0·53125
+ ⁹⁄₁₆ │0·5625
+ ¹⁹⁄₃₂ │0·59375
+ ⅝ │0·625
+ ²¹⁄₃₂ │0·65625
+ ¹¹⁄₁₆ │0·6875
+ ²³⁄₃₂ │0·71875
+ ¾ │0·75
+ ²⁵⁄₃₂ │0·78125
+ ¹³⁄₁₆ │0·8125
+ ²⁷⁄₃₂ │0·84375
+ ⅞ │0·875
+ ²⁹⁄₃₂ │0·90625
+ ¹⁵⁄₁₆ │0·9375
+ ³¹⁄₃₂ │0·96875
+
+Circ. of circle = 3·1416 _d_.
+
+Area „ „ = 0·7854 _d_^2.
+
+Sq. eq. area to cir., _s_ = 0·886 _d_.
+
+Circle eq. to sq., _d_ = 1·128 _s_.
+
+Sq. inscbd. in circ., _s_ = 0·707 _d_.
+
+Circsb. circ. of sq., _d_ = 1·414 _s_.
+
+Area of ellipse = 0.7854 _a_ × _b_.
+
+Surface of sphere = 3·1416 _d_^2.
+
+Volume „ „ = 0·5236 _d_^3.
+
+ „ „ cone = 0·2618 _d_^2 _h_.
+
+Radian = (180°)/(π) = 57·29 deg.
+
+Base of nat. or hyp. log. = e = 2·7183.
+
+Nat. or hyp. log. = com. log. × 2·3026.
+
+g (at London) 32·18 ft. per sec., per sec.
+
+Abs. temp. = deg. F. + 461° = deg. C. + 274°.
+
+C.° = (5)/(9)(F.° − 32°); F.° = (9)/(5)C.° + 32°.
+
+Cal. pr.—Ther. units per lb.: Coal, 14,300;
+
+ petrol’m, 20,000; coal gas per cu. ft., 700.
+
+Sp. heat:—Wt. iron, 0·1138; C.I., 0·1298;
+
+ copper, brass, 0·095; lead, 0·0314.
+
+Inch = 25·4 mil’metres; mil’metre = 0·03937 in.
+
+Foot = 0·3048 metres; metre = 3·2809 feet.
+
+Yard = 0·91438 metre; metre = 1·0936 yards.
+
+Mile = 1·6093 kilomtrs.; kilomtr. = 0·6213 mile.
+
+Sq. in. = 6·4513 sq. cm.; sq. cm. = 0·155 sq. in.
+
+Sq. ft. = 9·29 sq. decmtr.; sq. decmtr. = 0·1076 sq. ft.
+
+Sq. yd. = 0·836 sq. metre; sq. metre = 1·196 sq. yds.
+
+Sq. ml. = 258·9 hectares; hectare = 0·00386 sq. ml.
+
+Cu. in. = 16·386 c. cm.; c. cm. = 0·06102 cu. in.
+
+Cu. ft. = 0·0283 c. metre; c. metre = 35·316 cu. ft.
+
+Grain = 0·0648 gramme; gram. = 15·43 grs.
+
+Ounce = 28·35 grams.; „ = 0·03527 oz.
+
+Pound = 0·4536 kilogm.; kilogm. = 2·204 lb.
+
+Ton = 1·016 tonnes; tonne = 0·9842 ton.
+
+Mile per hr. = 1·466 ft., or 44·7 cm., per sec.
+
+Lb. per cu. in. = 0·0276 kilogram per cu. cm.
+
+Kilogram per cu. cm. = 36·125 lb. per cu. in.
+
+Lb. per cu. ft. = 16·019 kilogm. per cu. mtre.
+
+Grain per gall. = 0·01426 gramme per litre.
+
+Gramme per litre = 70·116 grains per gall.
+
+ Ultimate Strength│Lb. per Sq. in.
+ „ │Tens’n.│Comp’n.
+ ─────────────────┼───────┼───────
+ Wt. iron │ 50,000│ 50,000
+ Cast „ │ 16,000│ 95,000
+ Steel │ 80,000│ 70,000
+ Copper │ 21,000│ 50,000
+ Brass │ 18,000│ 10,500
+ Lead │ 2,500│ 7,000
+ Pine │ 11,000│ 6,000
+ Oak │ 15,000│ 10,000
+
+ Weight of Metals.│ Cub. In. │ Cub. Ft. │12 Cu. In.
+ ─────────────────┼──────────┼──────────┼──────────
+ Wt. iron │ 0·277│ 480│ 3·33
+ Cast „ │ 0·260│ 450│ 3·12
+ Steel │ 0·283│ 490│ 3·40
+ Copper │ 0·318│ 550│ 3·82
+ Brass │ 0·300│ 520│ 3·61
+ Zinc │ 0·248│ 430│ 2·98
+ Alumin’m │ 0.096│ 168│ 1·16
+ Lead │ 0.411│ 710│ 4·93
+
+ Lb. per sq. in. = 2·31 ft. water = 2·04 in. mercury = 0·0703 kilo. per
+ sq. cm.
+ Atmosphere = 14·7 lb. per sq. in. = 33·94 ft. water = 1·0335 „ „
+ Ft. hd. water = 0·433 lb. per sq. in. = 62·35 lb. per sq. ft. = 0·0304 „
+ „
+ Cub. ft. of water = 62·35 lb. = 0·0278 ton = 28·315 litres = 7·48 U.S.
+ galls.
+ Gall. (Imp.) = 277·27 cu. in. = 0·1604 cu. ft. = 10 lb. water = 4·544
+ litres.
+ Litre = 1·76 pints = 0·22 gall. = 61 cu. in. = 0·0353 cu. ft. = 0·264
+ U.S. gall.
+ Horse-power = 33,000 ft.-lb. per min. = 0·746 kilowatt = 42·4 heat units
+ per min.
+ Heat unit = 778 ft.-lb. = 1055 watt-sec. = 107·5 kilogrammetres = 0·252
+ calorie.
+ Foot-pound = 0·00129 heat unit = 1·36 joules = 0·1383 kilogrammetres.
+ Kilowatt = 1·34 H.P. = 44,240 ft.-lb. per min. = 3412 heat units per
+ hour.
+
+-----
+
+Footnote 1:
+
+ It will be recognised that n is the characteristic of the logarithm of
+ the original number.
+
+Footnote 2:
+
+ The special case in which the numerator is 1, 10, or any power of 10
+ must be treated by the rule for reciprocals (page 27).
+
+Footnote 3:
+
+ The possible need for traversing the slide, to change the indices,
+ when using the C and D scales, is not considered as a setting.
+
+Footnote 4:
+
+ The reader may be reminded that cross-multiplication of the factors in
+ any such slide rule setting will give a constant product, _e.g._, 20 ×
+ 94·5 = 27 × 70.
+
+Footnote 5:
+
+ In this case cross _dividing_ gives a constant quotient, _e.g._, 8 ÷ 3
+ = 4 ÷ 1·5. Since the upper scale is now a scale of reciprocals, the
+ ratio is really
+
+ O ⅛ ¼
+ ───────────
+ D 1·5 3
+
+Footnote 6:
+
+ These lines should not be brought to the working edge of the scale but
+ should terminate in the horizontal line which forms the border of the
+ finer graduations, their value being read into the calculation by
+ means of the cursor (see page 55).
+
+Footnote 7:
+
+ The same principle may be applied to the cursor.
+
+Footnote 8:
+
+ Philosophical Transactions of the Royal Society, 1815.
+
+------------------------------------------------------------------------
+
+
+
+
+ _BY THE SAME AUTHOR._
+
+
+ LOGARITHMS FOR BEGINNERS.
+
+“An extremely useful and much-needed little work, giving a complete
+explanation of the theory and use of logarithms, by a teacher of great
+clearness and good style.”—_The Mining Journal._
+
+ 1s. 8d. Post Free.
+
+
+ THE INDICATOR HANDBOOK.
+
+Comprising “The Indicator: Its Construction and Application” and “The
+Indicator Diagram: Its Analysis and Calculation.” Complete in One
+Volume.
+
+ 7s. 10d. Post Free.
+
+“Mr. Pickworth’s judgment is always sound, and is evidently derived from
+a personal acquaintance with indicator work.”—_The Engineer._
+
+
+ POWER COMPUTER FOR STEAM, GAS AND OIL ENGINES, Etc.
+
+“Accurate, expeditious and thoroughly practical.... We can confidently
+recommend it, and engineers will find it a great boon in undertaking
+tests, etc.”—_The Electrician._
+
+ 7s. 6d. Post Free.
+
+------------------------------------------------------------------------
+
+
+
+
+ ADVERTISEMENTS.
+
+
+ LOGARITHMS FOR BEGINNERS
+
+For a full and intelligent appreciation of the Slide Rule and its
+various applications an elementary knowledge of logarithms is necessary.
+All that is required will be found in this little work, which gives a
+simple, detailed and practical explanation of logarithms and their uses,
+particular care having been taken to elucidate all difficult points by
+the aid of a number of worked examples.
+
+ Seventh Edition, 1s. 8d. Post Free.
+
+
+ POWER COMPUTER
+ for
+ STEAM, GAS, AND OIL ENGINES, Etc.
+
+Gives The Indicated Horse-Power of Steam, Gas, and Oil Engines—The Brake
+Horse-Power of Steam, Gas, and Oil Engines—The Size of Engine Necessary
+to Develop any Given Power—The Mechanical Efficiency of an Engine—The
+Ratio of Compound Engine Cylinders—The Piston Speed of an Engine—The
+Delivery of Pumps with any Efficiency—The Horse-Power of Belting—The Rim
+Speeds of Wheels, Speeds of Ropes, Belts, etc.—Speed Ratios of Pulleys,
+Gearing, etc.
+
+ Pocket size, in neat case, with instructions and examples.
+
+ Post Free, 7s. 6d. net.
+
+
+ C. N. PICKWORTH, Withington, Manchester
+
+ ┌─────────────────────────────────────────────────────────────────────┐
+ │ W. P. THOMPSON, G. C. DYMOND, │
+ │ F.C.S., M.I.Mech.E., F.I.C.P.A. M.I.Mech.E., F.I.C.P.A. │
+ │ │
+ │ W. P. Thompson & Co., │
+ │ 12 CHURCH STREET, LIVERPOOL, │
+ │ CHARTERED PATENT AGENTS. │
+ │ │
+ │ H. E. POTTS, J. V. ARMSTRONG, │
+ │ M.Sc., Hon. Chem., F.I.C.P.A. M.Text.I., F.I.C.P.A. │
+ │ │
+ │ W. H. BEESTON, R.P.A. │
+ └─────────────────────────────────────────────────────────────────────┘
+
+------------------------------------------------------------------------
+
+
+
+
+ BRITISH
+ SLIDE RULES
+
+ for all
+ ARTS and
+ INDUSTRIES
+
+ including
+
+[Illustration: [Slide Rule]]
+
+ _LOG-O-LOG
+ DR. YOKOTA’S
+ SURVEYORS’
+ WIRELESS
+ GUNNERY
+ ELECTRICAL RULES, Etc._
+
+ SEND FOR LIST 55
+
+MADE BY—
+
+ JOHN DAVIS & SON (Derby), Ltd.
+ ALL SAINTS’ WORKS, DERBY
+
+------------------------------------------------------------------------
+
+
+
+
+ K & E Slide Rules
+
+are constantly growing in popularity, and they can now be obtained from
+the leading houses in our line throughout the United Kingdom.
+
+[Illustration: [Slide Rule]]
+
+ We manufacture a complete line of ENGINE-DIVIDED SLIDE RULES, and call
+special attention to our Patent Adjustment, ensuring smooth working of
+the Slide; also to our new “Frameless” Indicator, which hides no figures
+on the Rule.
+
+[Illustration: [Thacher’s Calculating Instrument]]
+
+THACHER’S CALCULATING INSTRUMENT, for solving problems in
+multiplication, division, or combinations of the two; has upwards of
+33,000 divisions. Results can be obtained to the fourth and usually to
+the fifth place of figures with a surprising degree of accuracy.
+
+ We also make
+
+ ALL METAL, CIRCULAR, STADIA, CHEMISTS’, ELECTRICAL, and OTHER SPECIAL
+ SLIDE RULES
+ _DESCRIPTIVE CIRCULARS ON REQUEST_
+
+ KEUFFEL & ESSER CO.
+ 127 Fulton St., NEW YORK General Office and Factories, HOBOKEN,
+ N.J.
+ CHICAGO − ST. LOUIS − SAN FRANCISCO − MONTREAL
+
+ _DRAWING MATERIALS_
+ _MATHEMATICAL and SURVEYING INSTRUMENTS_
+ _MEASURING TAPES_
+
+------------------------------------------------------------------------
+
+
+
+
+[Illustration: 6 in. Standard with magnifying Cursor complete in pocket
+case, 5/-]
+
+ NORTON
+ &
+ GREGORY
+ LTD.
+
+
+ Head Office
+
+ CASTLE LANE, WESTMINSTER, LONDON, S.W. 1
+
+ Branches
+
+ 71 QUEEN STREET, GLASGOW.
+ PHOENIX HOUSE, QUEEN STREET and SANDHILL, NEWCASTLE-ON-TYNE.
+
+
+ SLIDE RULES in Stock, from 17/6 to 27/6
+
+ Special Quotations to the Trade for Quantities
+
+
+ For particulars of Surveying, Measuring and Mathematical Instruments,
+ Appliances and Material of all kinds for the Drawing Office, write
+ to the Head Office.
+
+[Illustration: NORTON & GREGORY LTD]
+
+------------------------------------------------------------------------
+
+
+
+
+ NORTON & GREGORY, LTD.,
+ London.
+
+
+ “DIAMOND”
+ DRAWING INSTRUMENTS
+ Manufactured at our London Works.
+
+ CENTRE SCREW SPRING BOW HALF SET.
+
+[Illustration: [Centre Screw Spring Bow Half Set]]
+
+4 inch Spring Bow Half Set centre screw adjustment, with interchangeable
+needle, pen, and pencil points Price 17/6
+
+The Centre Screw Spring Bow Half Set of Compasses, as illustrated,
+possesses the advantage of COMBINING IN ONE INSTRUMENT THE SET OF THREE
+SEPARATE SPRING BOWS hitherto in use, while the centre screw makes for
+ease and accuracy of manipulation, at the same time providing a radius
+of over 2 inches, or double that of the old pattern.
+
+This instrument is less expensive than the set of 3 bows, while
+considerably stronger in construction.
+
+The fixed needle point is shouldered.
+
+This illustration is given as an indication of the various Drawing
+Instruments manufactured by us.
+
+Illustrated Booklet giving full particulars and prices of other
+Instruments and Cases of Instruments sent on application.
+
+
+ Specially arranged Sets of Instruments made for Colleges, Schools,
+ Technical Institutes
+
+ Estimates submitted on Application.
+
+
+ _Write to our Head Office_:
+ CASTLE LANE, WESTMINSTER, LONDON, S.W. 1.
+
+------------------------------------------------------------------------
+
+
+ DRAWING AND SURVEYING INSTRUMENTS
+
+ A. G. THORNTON Ltd.
+ SLIDE RULES FOR Paragon Works ACCURATE SECTIONAL
+ ENGINEERS 2 King St. West PAPERS AND CLOTHS
+ MANCHESTER
+
+ D 1916 Illustrated Catalogue, just published, in two editions; Drawing
+ Office (448 pages); Draughtsman’s (160 pages): the most complete
+ Catalogues in the trade.
+
+ _CONTRACTORS TO H.M. WAR OFFICE AND ADMIRALTY_
+ _Manufacturers also of Drawing Materials and Drawing Office Stationary._
+
+ (ALSO AT MINERVA WORKS AND ALBERT MILLS, MANCHESTER.)
+
+
+ MATHEMATICAL INSTRUMENTS
+ SURVEYING INSTRUMENTS
+ SLIDE RULES
+ For Students and Engineers
+
+ MANNHEIM, POLYPHASE, DUPLEX, ELECTRICAL, LOG-LOG, AND CALCULEX
+
+ J. H. STEWARD LTD.
+ Scientific Instrument Makers
+
+ 406 STRAND, and 457 WEST STRAND
+ LONDON, W.C. 2
+
+------------------------------------------------------------------------
+
+
+
+
+ _A True Friend and Trusty Guide_
+
+
+ THE
+ ‘HALDEN CALCULEX’
+
+[Illustration: [Halden Calculex]]
+
+ ACTUAL SIZE| | | BRITISH MADE
+
+ The handiest and most perfect form of Slide Rule.
+ Does all that can be done with a straight rule.
+ Complete in Case, with book of instructions,
+ 27/6 post free.
+
+ J. HALDEN & CO., LTD., 8 ALBERT SQUARE MANCHESTER
+
+ _Depots_—London, Newcastle-on-Tyne, Birmingham, Glasgow, and Leeds
+
+------------------------------------------------------------------------
+
+
+[Illustration: [Rope]]
+
+ ENGINEERING,
+ SURVEYING
+ AND
+ MATHEMATICAL
+ INSTRUMENTS,
+ ETC.
+
+
+ SLIDE RULES.
+
+ JOSEPH CASARTELLI & SON,
+ 43 MARKET STREET, MANCHESTER.
+ Tel. No. 2958 City.| | | Established 1790.
+
+ROPE DRIVING
+
+ Is the most EFFICIENT and most ECONOMICAL METHOD of Power
+ Transmission.
+
+The LAMBETH Cotton Driving Rope
+
+ Is the most EFFICIENT and most ECONOMICAL ROPE for Power Transmission.
+
+[Illustration: Made 4 Strand or 3 Strand.]
+
+SPECIAL FEATURES:
+
+ LESS STRETCH THAN ANY OTHER ROPE. MORE PLIABLE THAN ANY OTHER ROPE.
+ GREATER DRIVING POWER THAN ANY OTHER ROPE.
+
+ THOMAS HART LTD., Lambeth Works, BLACKBURN.
+
+------------------------------------------------------------------------
+
+
+
+
+ TRANSCRIBER’S NOTES
+
+
+ Page Changed from Changed to
+
+ 24 the right, so the number of the right, so the number of
+ digits in the answer = 3 − 2 × 1 digits in the answer = 3 − 2 + 1
+ = 2 = 2
+
+ 116 grammes, we have the equation, grammes, we have the equation,
+ _x_ × (Cl.)/(Ag.Cl.) × _x_ = (Cl.)/(Ag.Cl.) ×
+ (_a_)/(_s_). Hence, the mark (_a_)/(_s_). Hence, the mark
+
+ ● Typos fixed; non-standard spelling and dialect retained.
+ ● Used numbers for footnotes, placing them all at the end of the last
+ chapter.
+ ● Enclosed italics font in _underscores_.
+ ● Enclosed bold font in =equals=.
+ ● The caret (^) serves as a superscript indicator, applicable to
+ individual characters (like 2^d) and even entire phrases (like
+ 1^{st}).
+ ● Subscripts are shown using an underscore (_) with curly braces { },
+ as in H_{2}O.
+
+
+
+*** END OF THE PROJECT GUTENBERG EBOOK 75904 ***